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Courtney Benjamin

2017-Aug-10 03:54 UTC

[R] Creating New Variable Using Ifelse

Hello R Help List,

I am an R novice and trying to use the ifelse function to create a new binary
variable based off of the responses of two other binary variables; NAs are
involved.  I pulled it off almost successfully, but when I checked the counts of
my new variable for accuracy, I found that a small portion of the NA cases were
not being passed through as NAs, but as "0" counts in my new variable.
My many attempts at creating a nested ifelse statement that would pass the NAs
through properly have not been successful.  Any help is greatly appreciated.

Here is a MRE:?

library(RCurl)
data <-
getURL("https://raw.githubusercontent.com/cbenjamin1821/careertech-ed/master/elsq2wbl.csv")
elsq2wbl <- read.csv(text = data)

##Recoding Negative Responses to NA
elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3, "EVERRELJOB"]
<- NA
elsq2wbl [elsq2wbl[, "PSWBL"] < -2, "PSWBL"] <- NA

#Labeling categorical variable levels
elsq2wbl$EVERRELJOB <- factor(elsq2wbl$EVERRELJOB, levels = c(0,1), labels =
c("No","Yes"))
elsq2wbl$PSWBL <- factor(elsq2wbl$PSWBL, levels = c(0,1), labels =
c("No","Yes"))

##Trying to create a new variable to indicate if the student had a job
#related to the college studies that was NOT a WBL experience
elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes",1,0)

#Cross tab to check counts of two variables that new variable is based upon
xtabs(~PSWBL+EVERRELJOB,subset(elsq2wbl,BYSCTRL==1&G10COHRT==1),addNA=TRUE)

#Checking count of newly created variable
Q2sub <- subset(elsq2wbl,BYSCTRL==1&G10COHRT==1)
library(plyr)
count(Q2sub,'NONWBLRELJOB')

#The new variable has the correct count of "1", but 88 cases too many
for "0"
#The cross tab shows 20 and 68 NA cases that are being incorrectly counted as
"0" in the new variable

#My other approach at trying to handle the NAs properly-returns an error
elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes",1,ifelse(is.na(elsq2wbl$PSWBL)&is.na(elsq2wbl$EVERRELJOB),NA,
                                                                                
ifelse(elsq2wbl$PSWBL!="No" &
elsq2wbl$EVERRELJOB!="Yes",0)))



Courtney Benjamin

Broome-Tioga BOCES

Automotive Technology II Teacher

Located at Gault Toyota

Doctoral Candidate-Educational Theory & Practice

State University of New York at Binghamton

cbenjami at btboces.org<mailto:cbenjami at btboces.org>

607-763-8633

	[[alternative HTML version deleted]]

Ismail SEZEN

2017-Aug-10 05:55 UTC

head link

[R] Creating New Variable Using Ifelse

> On 10 Aug 2017, at 06:54, Courtney Benjamin <cbenjami at BTBOCES.ORG>
wrote:
> 
> Hello R Help List,
> 
> I am an R novice and trying to use the ifelse function to create a new
binary variable based off of the responses of two other binary variables; NAs
are involved.  I pulled it off almost successfully, but when I checked the
counts of my new variable for accuracy, I found that a small portion of the NA
cases were not being passed through as NAs, but as "0" counts in my
new variable.  My many attempts at creating a nested ifelse statement that would
pass the NAs through properly have not been successful.  Any help is greatly
appreciated.
> 
> Here is a MRE:?
> 
> library(RCurl)
> data <-
getURL("https://raw.githubusercontent.com/cbenjamin1821/careertech-ed/master/elsq2wbl.csv")
> elsq2wbl <- read.csv(text = data)
> 
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3,
"EVERRELJOB"] <- NA
> elsq2wbl [elsq2wbl[, "PSWBL"] < -2, "PSWBL"] <-
NA
> 
> #Labeling categorical variable levels
> elsq2wbl$EVERRELJOB <- factor(elsq2wbl$EVERRELJOB, levels = c(0,1),
labels = c("No","Yes"))
> elsq2wbl$PSWBL <- factor(elsq2wbl$PSWBL, levels = c(0,1), labels =
c("No","Yes"))
> 
> ##Trying to create a new variable to indicate if the student had a job
> #related to the college studies that was NOT a WBL experience
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes",1,0)
> 
> #Cross tab to check counts of two variables that new variable is based upon
>
xtabs(~PSWBL+EVERRELJOB,subset(elsq2wbl,BYSCTRL==1&G10COHRT==1),addNA=TRUE)
> 
> #Checking count of newly created variable
> Q2sub <- subset(elsq2wbl,BYSCTRL==1&G10COHRT==1)
> library(plyr)
> count(Q2sub,'NONWBLRELJOB')
> 
> #The new variable has the correct count of "1", but 88 cases too
many for "0"
> #The cross tab shows 20 and 68 NA cases that are being incorrectly counted
as "0" in the new variable
> 
> #My other approach at trying to handle the NAs properly-returns an error
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes",1,ifelse(is.na(elsq2wbl$PSWBL)&is.na(elsq2wbl$EVERRELJOB),NA,
>                                                                            
ifelse(elsq2wbl$PSWBL!="No" &
elsq2wbl$EVERRELJOB!="Yes",0)))
> 
> 
> 
> Courtney Benjamin
I could not follow the question up clearly. But one thing that come across to my
sight is that you have values in elsq2wbl$EVERRELJOB as below:

summary(factor(elsq2wbl$EVERRELJOB))
  -9   -8   -7   -4   -3    0    1 
 139  459  946 2488 1948 4619 5598 

and in fact, you want to set negative values to NA.
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3,
"EVERRELJOB"] <- NA
But after the command, you still have 1948 ?-3' in the variable;

summary(factor(elsq2wbl$EVERRELJOB))
  -3    0    1 NA's 
1948 4619 5598 4032 

So I think, you need to fix the line as follows:
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] <= -3,
"EVERRELJOB"] <- NA

Instead of using ?-2' and ?-3' as threshold to set NA for different
variables, why don?t you use ?less than zero? condition as follows?

elsq2wbl [elsq2wbl[, "EVERRELJOB"] < 0, "EVERRELJOB"]
<- NA
elsq2wbl [elsq2wbl[, "PSWBL"] < 0, "PSWBL"] <- NA

Hence, in both columns (variables), values lower than zero will be NA and you
only will have 0, 1 and NA values in the variable as you called ?binary?.

_ifelse_ part:

You have NA?s in both variables. In this circumstances, consider following
ifelse samples (both sides of '&' can be exchanged)

ifelse(TRUE & TRUE, 1, 0) # 1
ifelse(TRUE & FALSE, 1, 0) # 0
ifelse(FALSE & FALSE, 1, 0) # 0
ifelse(TRUE & NA, 1, 0) # NA
ifelse(FALSE & NA, 1, 0) # 0

according to above, try to create new logic to achieve what you need.

In your last neste-ifelse, you forgot to define a value if deepest ifelse
statement fails.

elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes", 1,
                                ifelse(is.na(elsq2wbl$PSWBL) &
is.na(elsq2wbl$EVERRELJOB), NA,
                                       ifelse(elsq2wbl$PSWBL != "No"
& elsq2wbl$EVERRELJOB != "Yes",0, "Forgotten value")))

Also, please, try to create a _minimal reproducible example_ instead of make us
download a big csv file (219 columns x 16197 rows) and try to understand what
you are trying to do. :)

PIKAL Petr

2017-Aug-10 09:39 UTC

head link

[R] Creating New Variable Using Ifelse

Hi

see in line
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Courtney
> Benjamin
> Sent: Thursday, August 10, 2017 5:55 AM
> To: r-help at r-project.org
> Subject: [R] Creating New Variable Using Ifelse
>
> Hello R Help List,
>
> I am an R novice and trying to use the ifelse function to create a new
binary
> variable based off of the responses of two other binary variables; NAs are
> involved.  I pulled it off almost successfully, but when I checked the
counts of
> my new variable for accuracy, I found that a small portion of the NA cases
were
> not being passed through as NAs, but as "0" counts in my new
variable.  My
> many attempts at creating a nested ifelse statement that would pass the NAs
> through properly have not been successful.  Any help is greatly
appreciated.
>
> Here is a MRE:?
>
> library(RCurl)
> data <-
> getURL("https://raw.githubusercontent.com/cbenjamin1821/careertech-
> ed/master/elsq2wbl.csv")
Did not work for me probably due to some restriction of data access.
> elsq2wbl <- read.csv(text = data)
>
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3,
"EVERRELJOB"] <- NA
> elsq2wbl [elsq2wbl[, "PSWBL"] < -2, "PSWBL"] <-
NA
If you wanted recode values below zero to NA you can do this easily without any
ifelse
> summary(test)       mp             tepl           kryst
 Min.   : 7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.:32.25   1st Qu.:400.0   1st Qu.: 24.15
 Median :37.50   Median :500.0   Median : 26.55
 Mean   :38.44   Mean   :485.7   Mean   : 42.64
 3rd Qu.:44.75   3rd Qu.:600.0   3rd Qu.: 33.62
 Max.   :76.02   Max.   :900.0   Max.   :150.00
 NA's   :3                       NA's   :6> test[is.na(test)] <- 999
> summary(test)       mp              tepl           kryst
 Min.   :  7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.: 34.27   1st Qu.:400.0   1st Qu.: 25.93
 Median : 41.75   Median :500.0   Median : 92.90
 Mean   :244.28   Mean   :485.7   Mean   :452.51
 3rd Qu.: 70.05   3rd Qu.:600.0   3rd Qu.:999.00
 Max.   :999.00   Max.   :900.0   Max.   :999.00>
> test[test>900] <- NA
> summary(test)       mp             tepl           kryst
 Min.   : 7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.:32.25   1st Qu.:400.0   1st Qu.: 24.15
 Median :37.50   Median :500.0   Median : 26.55
 Mean   :38.44   Mean   :485.7   Mean   : 42.64
 3rd Qu.:44.75   3rd Qu.:600.0   3rd Qu.: 33.62
 Max.   :76.02   Max.   :900.0   Max.   :150.00
 NA's   :3                       NA's   :6

>
> #Labeling categorical variable levels
> elsq2wbl$EVERRELJOB <- factor(elsq2wbl$EVERRELJOB, levels = c(0,1),
labels > c("No","Yes"))
> elsq2wbl$PSWBL <- factor(elsq2wbl$PSWBL, levels = c(0,1), labels >
c("No","Yes"))
>
> ##Trying to create a new variable to indicate if the student had a job
> #related to the college studies that was NOT a WBL experience
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
> elsq2wbl$EVERRELJOB=="Yes",1,0)
You can use simple logical functions to get desired result

First sample data> a <- sample(c("Y", "N"), 30, replace=TRUE)
> b <- sample(c("Y", "N"), 30, replace=TRUE)
> (a=="N")*(b=="Y") [1] 1 1 0 0 1 0 0 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1

has 1 only if both conditions are met.

and it works with NA values too.
> a[c(3,5,8)] <- NA
> b[c(3,6,7,8)] <- NA
> (a=="N")*(b=="Y") [1]  1  1 NA  0 NA NA NA NA  0  0  1  0  0  1  0  0  0  0  1  0  0  0  0  0  0
[26]  0  0  0  0  1

Cheers
Petr

>
> #Cross tab to check counts of two variables that new variable is based upon
> xtabs(~PSWBL+EVERRELJOB,subset(elsq2wbl,BYSCTRL==1&G10COHRT==1),add
> NA=TRUE)
>
> #Checking count of newly created variable
> Q2sub <- subset(elsq2wbl,BYSCTRL==1&G10COHRT==1)
> library(plyr)
> count(Q2sub,'NONWBLRELJOB')
>
> #The new variable has the correct count of "1", but 88 cases too
many for "0"
> #The cross tab shows 20 and 68 NA cases that are being incorrectly counted
as
> "0" in the new variable
>
> #My other approach at trying to handle the NAs properly-returns an error
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
>
elsq2wbl$EVERRELJOB=="Yes",1,ifelse(is.na(elsq2wbl$PSWBL)&is.na(elsq2wbl$
> EVERRELJOB),NA,
>
> ifelse(elsq2wbl$PSWBL!="No" &
elsq2wbl$EVERRELJOB!="Yes",0)))
>
>
>
> Courtney Benjamin
>
> Broome-Tioga BOCES
>
> Automotive Technology II Teacher
>
> Located at Gault Toyota
>
> Doctoral Candidate-Educational Theory & Practice
>
> State University of New York at Binghamton
>
> cbenjami at btboces.org<mailto:cbenjami at btboces.org>
>
> 607-763-8633
>
>       [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
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Courtney Benjamin

2017-Aug-10 12:43 UTC

head link

[R] Creating New Variable Using Ifelse

Thanks very much; with your tips, I was able to get the nested ifelse statement
to work properly!

Courtney Benjamin


________________________________________
From: PIKAL Petr <petr.pikal at precheza.cz>
Sent: Thursday, August 10, 2017 5:39 AM
To: Courtney Benjamin; r-help at r-project.org
Subject: RE: Creating New Variable Using Ifelse

Hi

see in line
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Courtney
> Benjamin
> Sent: Thursday, August 10, 2017 5:55 AM
> To: r-help at r-project.org
> Subject: [R] Creating New Variable Using Ifelse
>
> Hello R Help List,
>
> I am an R novice and trying to use the ifelse function to create a new
binary
> variable based off of the responses of two other binary variables; NAs are
> involved.  I pulled it off almost successfully, but when I checked the
counts of
> my new variable for accuracy, I found that a small portion of the NA cases
were
> not being passed through as NAs, but as "0" counts in my new
variable.  My
> many attempts at creating a nested ifelse statement that would pass the NAs
> through properly have not been successful.  Any help is greatly
appreciated.
>
> Here is a MRE:?
>
> library(RCurl)
> data <-
> getURL("https://raw.githubusercontent.com/cbenjamin1821/careertech-
> ed/master/elsq2wbl.csv")
Did not work for me probably due to some restriction of data access.
> elsq2wbl <- read.csv(text = data)
>
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3,
"EVERRELJOB"] <- NA
> elsq2wbl [elsq2wbl[, "PSWBL"] < -2, "PSWBL"] <-
NA
If you wanted recode values below zero to NA you can do this easily without any
ifelse
> summary(test)       mp             tepl           kryst
 Min.   : 7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.:32.25   1st Qu.:400.0   1st Qu.: 24.15
 Median :37.50   Median :500.0   Median : 26.55
 Mean   :38.44   Mean   :485.7   Mean   : 42.64
 3rd Qu.:44.75   3rd Qu.:600.0   3rd Qu.: 33.62
 Max.   :76.02   Max.   :900.0   Max.   :150.00
 NA's   :3                       NA's   :6> test[is.na(test)] <- 999
> summary(test)       mp              tepl           kryst
 Min.   :  7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.: 34.27   1st Qu.:400.0   1st Qu.: 25.93
 Median : 41.75   Median :500.0   Median : 92.90
 Mean   :244.28   Mean   :485.7   Mean   :452.51
 3rd Qu.: 70.05   3rd Qu.:600.0   3rd Qu.:999.00
 Max.   :999.00   Max.   :900.0   Max.   :999.00>
> test[test>900] <- NA
> summary(test)       mp             tepl           kryst
 Min.   : 7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.:32.25   1st Qu.:400.0   1st Qu.: 24.15
 Median :37.50   Median :500.0   Median : 26.55
 Mean   :38.44   Mean   :485.7   Mean   : 42.64
 3rd Qu.:44.75   3rd Qu.:600.0   3rd Qu.: 33.62
 Max.   :76.02   Max.   :900.0   Max.   :150.00
 NA's   :3                       NA's   :6

>
> #Labeling categorical variable levels
> elsq2wbl$EVERRELJOB <- factor(elsq2wbl$EVERRELJOB, levels = c(0,1),
labels > c("No","Yes"))
> elsq2wbl$PSWBL <- factor(elsq2wbl$PSWBL, levels = c(0,1), labels >
c("No","Yes"))
>
> ##Trying to create a new variable to indicate if the student had a job
> #related to the college studies that was NOT a WBL experience
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
> elsq2wbl$EVERRELJOB=="Yes",1,0)
You can use simple logical functions to get desired result

First sample data> a <- sample(c("Y", "N"), 30, replace=TRUE)
> b <- sample(c("Y", "N"), 30, replace=TRUE)
> (a=="N")*(b=="Y") [1] 1 1 0 0 1 0 0 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1

has 1 only if both conditions are met.

and it works with NA values too.
> a[c(3,5,8)] <- NA
> b[c(3,6,7,8)] <- NA
> (a=="N")*(b=="Y") [1]  1  1 NA  0 NA NA NA NA  0  0  1  0  0  1  0  0  0  0  1  0  0  0  0  0  0
[26]  0  0  0  0  1

Cheers
Petr

>
> #Cross tab to check counts of two variables that new variable is based upon
> xtabs(~PSWBL+EVERRELJOB,subset(elsq2wbl,BYSCTRL==1&G10COHRT==1),add
> NA=TRUE)
>
> #Checking count of newly created variable
> Q2sub <- subset(elsq2wbl,BYSCTRL==1&G10COHRT==1)
> library(plyr)
> count(Q2sub,'NONWBLRELJOB')
>
> #The new variable has the correct count of "1", but 88 cases too
many for "0"
> #The cross tab shows 20 and 68 NA cases that are being incorrectly counted
as
> "0" in the new variable
>
> #My other approach at trying to handle the NAs properly-returns an error
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
>
elsq2wbl$EVERRELJOB=="Yes",1,ifelse(is.na(elsq2wbl$PSWBL)&is.na(elsq2wbl$
> EVERRELJOB),NA,
>
> ifelse(elsq2wbl$PSWBL!="No" &
elsq2wbl$EVERRELJOB!="Yes",0)))
>
>
>
> Courtney Benjamin
>
> Broome-Tioga BOCES
>
> Automotive Technology II Teacher
>
> Located at Gault Toyota
>
> Doctoral Candidate-Educational Theory & Practice
>
> State University of New York at Binghamton
>
> cbenjami at btboces.org<mailto:cbenjami at btboces.org>
>
> 607-763-8633
>
>       [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny
pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
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to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.

This e-mail and any documents attached to it may be confidential and are
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender.
Delete the contents of this e-mail with all attachments and its copies from your
system.
If you are not the intended recipient of this e-mail, you are not authorized to
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by
modifications of the e-mail or by delay with transfer of the email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to immediately
accept such offer; The sender of this e-mail (offer) excludes any acceptance of
the offer on the part of the recipient containing any amendment or variation.
- the sender insists on that the respective contract is concluded only upon an
express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into
any contracts on behalf of the company except for cases in which he/she is
expressly authorized to do so in writing, and such authorization or power of
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recipient, or the existence of such authorization is known to the recipient of
the person represented by the recipient.

R help - Aug 2017 - Creating New Variable Using Ifelse

[R] Creating New Variable Using Ifelse

[R] Creating New Variable Using Ifelse

[R] Creating New Variable Using Ifelse

[R] Creating New Variable Using Ifelse

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