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Courtney Benjamin

2017-Aug-10 03:54 UTC

[R] Creating New Variable Using Ifelse

Hello R Help List,

I am an R novice and trying to use the ifelse function to create a new binary
variable based off of the responses of two other binary variables; NAs are
involved.  I pulled it off almost successfully, but when I checked the counts of
my new variable for accuracy, I found that a small portion of the NA cases were
not being passed through as NAs, but as "0" counts in my new variable.
My many attempts at creating a nested ifelse statement that would pass the NAs
through properly have not been successful.  Any help is greatly appreciated.

Here is a MRE:?

library(RCurl)
data <-
getURL("https://raw.githubusercontent.com/cbenjamin1821/careertech-ed/master/elsq2wbl.csv")
elsq2wbl <- read.csv(text = data)

##Recoding Negative Responses to NA
elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3, "EVERRELJOB"]
<- NA
elsq2wbl [elsq2wbl[, "PSWBL"] < -2, "PSWBL"] <- NA

#Labeling categorical variable levels
elsq2wbl$EVERRELJOB <- factor(elsq2wbl$EVERRELJOB, levels = c(0,1), labels =
c("No","Yes"))
elsq2wbl$PSWBL <- factor(elsq2wbl$PSWBL, levels = c(0,1), labels =
c("No","Yes"))

##Trying to create a new variable to indicate if the student had a job
#related to the college studies that was NOT a WBL experience
elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes",1,0)

#Cross tab to check counts of two variables that new variable is based upon
xtabs(~PSWBL+EVERRELJOB,subset(elsq2wbl,BYSCTRL==1&G10COHRT==1),addNA=TRUE)

#Checking count of newly created variable
Q2sub <- subset(elsq2wbl,BYSCTRL==1&G10COHRT==1)
library(plyr)
count(Q2sub,'NONWBLRELJOB')

#The new variable has the correct count of "1", but 88 cases too many
for "0"
#The cross tab shows 20 and 68 NA cases that are being incorrectly counted as
"0" in the new variable

#My other approach at trying to handle the NAs properly-returns an error
elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes",1,ifelse(is.na(elsq2wbl$PSWBL)&is.na(elsq2wbl$EVERRELJOB),NA,
                                                                                
ifelse(elsq2wbl$PSWBL!="No" &
elsq2wbl$EVERRELJOB!="Yes",0)))



Courtney Benjamin

Broome-Tioga BOCES

Automotive Technology II Teacher

Located at Gault Toyota

Doctoral Candidate-Educational Theory & Practice

State University of New York at Binghamton

cbenjami at btboces.org<mailto:cbenjami at btboces.org>

607-763-8633

	[[alternative HTML version deleted]]

Ismail SEZEN

2017-Aug-10 05:55 UTC

head link

[R] Creating New Variable Using Ifelse

> On 10 Aug 2017, at 06:54, Courtney Benjamin <cbenjami at BTBOCES.ORG>
wrote:
> 
> Hello R Help List,
> 
> I am an R novice and trying to use the ifelse function to create a new
binary variable based off of the responses of two other binary variables; NAs
are involved.  I pulled it off almost successfully, but when I checked the
counts of my new variable for accuracy, I found that a small portion of the NA
cases were not being passed through as NAs, but as "0" counts in my
new variable.  My many attempts at creating a nested ifelse statement that would
pass the NAs through properly have not been successful.  Any help is greatly
appreciated.
> 
> Here is a MRE:?
> 
> library(RCurl)
> data <-
getURL("https://raw.githubusercontent.com/cbenjamin1821/careertech-ed/master/elsq2wbl.csv")
> elsq2wbl <- read.csv(text = data)
> 
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3,
"EVERRELJOB"] <- NA
> elsq2wbl [elsq2wbl[, "PSWBL"] < -2, "PSWBL"] <-
NA
> 
> #Labeling categorical variable levels
> elsq2wbl$EVERRELJOB <- factor(elsq2wbl$EVERRELJOB, levels = c(0,1),
labels = c("No","Yes"))
> elsq2wbl$PSWBL <- factor(elsq2wbl$PSWBL, levels = c(0,1), labels =
c("No","Yes"))
> 
> ##Trying to create a new variable to indicate if the student had a job
> #related to the college studies that was NOT a WBL experience
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes",1,0)
> 
> #Cross tab to check counts of two variables that new variable is based upon
>
xtabs(~PSWBL+EVERRELJOB,subset(elsq2wbl,BYSCTRL==1&G10COHRT==1),addNA=TRUE)
> 
> #Checking count of newly created variable
> Q2sub <- subset(elsq2wbl,BYSCTRL==1&G10COHRT==1)
> library(plyr)
> count(Q2sub,'NONWBLRELJOB')
> 
> #The new variable has the correct count of "1", but 88 cases too
many for "0"
> #The cross tab shows 20 and 68 NA cases that are being incorrectly counted
as "0" in the new variable
> 
> #My other approach at trying to handle the NAs properly-returns an error
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes",1,ifelse(is.na(elsq2wbl$PSWBL)&is.na(elsq2wbl$EVERRELJOB),NA,
>                                                                            
ifelse(elsq2wbl$PSWBL!="No" &
elsq2wbl$EVERRELJOB!="Yes",0)))
> 
> 
> 
> Courtney Benjamin
I could not follow the question up clearly. But one thing that come across to my
sight is that you have values in elsq2wbl$EVERRELJOB as below:

summary(factor(elsq2wbl$EVERRELJOB))
  -9   -8   -7   -4   -3    0    1 
 139  459  946 2488 1948 4619 5598 

and in fact, you want to set negative values to NA.
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3,
"EVERRELJOB"] <- NA
But after the command, you still have 1948 ?-3' in the variable;

summary(factor(elsq2wbl$EVERRELJOB))
  -3    0    1 NA's 
1948 4619 5598 4032 

So I think, you need to fix the line as follows:
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] <= -3,
"EVERRELJOB"] <- NA

Instead of using ?-2' and ?-3' as threshold to set NA for different
variables, why don?t you use ?less than zero? condition as follows?

elsq2wbl [elsq2wbl[, "EVERRELJOB"] < 0, "EVERRELJOB"]
<- NA
elsq2wbl [elsq2wbl[, "PSWBL"] < 0, "PSWBL"] <- NA

Hence, in both columns (variables), values lower than zero will be NA and you
only will have 0, 1 and NA values in the variable as you called ?binary?.

_ifelse_ part:

You have NA?s in both variables. In this circumstances, consider following
ifelse samples (both sides of '&' can be exchanged)

ifelse(TRUE & TRUE, 1, 0) # 1
ifelse(TRUE & FALSE, 1, 0) # 0
ifelse(FALSE & FALSE, 1, 0) # 0
ifelse(TRUE & NA, 1, 0) # NA
ifelse(FALSE & NA, 1, 0) # 0

according to above, try to create new logic to achieve what you need.

In your last neste-ifelse, you forgot to define a value if deepest ifelse
statement fails.

elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
elsq2wbl$EVERRELJOB=="Yes", 1,
                                ifelse(is.na(elsq2wbl$PSWBL) &
is.na(elsq2wbl$EVERRELJOB), NA,
                                       ifelse(elsq2wbl$PSWBL != "No"
& elsq2wbl$EVERRELJOB != "Yes",0, "Forgotten value")))

Also, please, try to create a _minimal reproducible example_ instead of make us
download a big csv file (219 columns x 16197 rows) and try to understand what
you are trying to do. :)

PIKAL Petr

2017-Aug-10 09:39 UTC

head link

[R] Creating New Variable Using Ifelse

Hi

see in line
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Courtney
> Benjamin
> Sent: Thursday, August 10, 2017 5:55 AM
> To: r-help at r-project.org
> Subject: [R] Creating New Variable Using Ifelse
>
> Hello R Help List,
>
> I am an R novice and trying to use the ifelse function to create a new
binary
> variable based off of the responses of two other binary variables; NAs are
> involved.  I pulled it off almost successfully, but when I checked the
counts of
> my new variable for accuracy, I found that a small portion of the NA cases
were
> not being passed through as NAs, but as "0" counts in my new
variable.  My
> many attempts at creating a nested ifelse statement that would pass the NAs
> through properly have not been successful.  Any help is greatly
appreciated.
>
> Here is a MRE:?
>
> library(RCurl)
> data <-
> getURL("https://raw.githubusercontent.com/cbenjamin1821/careertech-
> ed/master/elsq2wbl.csv")
Did not work for me probably due to some restriction of data access.
> elsq2wbl <- read.csv(text = data)
>
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3,
"EVERRELJOB"] <- NA
> elsq2wbl [elsq2wbl[, "PSWBL"] < -2, "PSWBL"] <-
NA
If you wanted recode values below zero to NA you can do this easily without any
ifelse
> summary(test)       mp             tepl           kryst
 Min.   : 7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.:32.25   1st Qu.:400.0   1st Qu.: 24.15
 Median :37.50   Median :500.0   Median : 26.55
 Mean   :38.44   Mean   :485.7   Mean   : 42.64
 3rd Qu.:44.75   3rd Qu.:600.0   3rd Qu.: 33.62
 Max.   :76.02   Max.   :900.0   Max.   :150.00
 NA's   :3                       NA's   :6> test[is.na(test)] <- 999
> summary(test)       mp              tepl           kryst
 Min.   :  7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.: 34.27   1st Qu.:400.0   1st Qu.: 25.93
 Median : 41.75   Median :500.0   Median : 92.90
 Mean   :244.28   Mean   :485.7   Mean   :452.51
 3rd Qu.: 70.05   3rd Qu.:600.0   3rd Qu.:999.00
 Max.   :999.00   Max.   :900.0   Max.   :999.00>
> test[test>900] <- NA
> summary(test)       mp             tepl           kryst
 Min.   : 7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.:32.25   1st Qu.:400.0   1st Qu.: 24.15
 Median :37.50   Median :500.0   Median : 26.55
 Mean   :38.44   Mean   :485.7   Mean   : 42.64
 3rd Qu.:44.75   3rd Qu.:600.0   3rd Qu.: 33.62
 Max.   :76.02   Max.   :900.0   Max.   :150.00
 NA's   :3                       NA's   :6

>
> #Labeling categorical variable levels
> elsq2wbl$EVERRELJOB <- factor(elsq2wbl$EVERRELJOB, levels = c(0,1),
labels > c("No","Yes"))
> elsq2wbl$PSWBL <- factor(elsq2wbl$PSWBL, levels = c(0,1), labels >
c("No","Yes"))
>
> ##Trying to create a new variable to indicate if the student had a job
> #related to the college studies that was NOT a WBL experience
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
> elsq2wbl$EVERRELJOB=="Yes",1,0)
You can use simple logical functions to get desired result

First sample data> a <- sample(c("Y", "N"), 30, replace=TRUE)
> b <- sample(c("Y", "N"), 30, replace=TRUE)
> (a=="N")*(b=="Y") [1] 1 1 0 0 1 0 0 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1

has 1 only if both conditions are met.

and it works with NA values too.
> a[c(3,5,8)] <- NA
> b[c(3,6,7,8)] <- NA
> (a=="N")*(b=="Y") [1]  1  1 NA  0 NA NA NA NA  0  0  1  0  0  1  0  0  0  0  1  0  0  0  0  0  0
[26]  0  0  0  0  1

Cheers
Petr

>
> #Cross tab to check counts of two variables that new variable is based upon
> xtabs(~PSWBL+EVERRELJOB,subset(elsq2wbl,BYSCTRL==1&G10COHRT==1),add
> NA=TRUE)
>
> #Checking count of newly created variable
> Q2sub <- subset(elsq2wbl,BYSCTRL==1&G10COHRT==1)
> library(plyr)
> count(Q2sub,'NONWBLRELJOB')
>
> #The new variable has the correct count of "1", but 88 cases too
many for "0"
> #The cross tab shows 20 and 68 NA cases that are being incorrectly counted
as
> "0" in the new variable
>
> #My other approach at trying to handle the NAs properly-returns an error
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
>
elsq2wbl$EVERRELJOB=="Yes",1,ifelse(is.na(elsq2wbl$PSWBL)&is.na(elsq2wbl$
> EVERRELJOB),NA,
>
> ifelse(elsq2wbl$PSWBL!="No" &
elsq2wbl$EVERRELJOB!="Yes",0)))
>
>
>
> Courtney Benjamin
>
> Broome-Tioga BOCES
>
> Automotive Technology II Teacher
>
> Located at Gault Toyota
>
> Doctoral Candidate-Educational Theory & Practice
>
> State University of New York at Binghamton
>
> cbenjami at btboces.org<mailto:cbenjami at btboces.org>
>
> 607-763-8633
>
>       [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
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Courtney Benjamin

2017-Aug-10 12:43 UTC

head link

[R] Creating New Variable Using Ifelse

Thanks very much; with your tips, I was able to get the nested ifelse statement
to work properly!

Courtney Benjamin


________________________________________
From: PIKAL Petr <petr.pikal at precheza.cz>
Sent: Thursday, August 10, 2017 5:39 AM
To: Courtney Benjamin; r-help at r-project.org
Subject: RE: Creating New Variable Using Ifelse

Hi

see in line
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Courtney
> Benjamin
> Sent: Thursday, August 10, 2017 5:55 AM
> To: r-help at r-project.org
> Subject: [R] Creating New Variable Using Ifelse
>
> Hello R Help List,
>
> I am an R novice and trying to use the ifelse function to create a new
binary
> variable based off of the responses of two other binary variables; NAs are
> involved.  I pulled it off almost successfully, but when I checked the
counts of
> my new variable for accuracy, I found that a small portion of the NA cases
were
> not being passed through as NAs, but as "0" counts in my new
variable.  My
> many attempts at creating a nested ifelse statement that would pass the NAs
> through properly have not been successful.  Any help is greatly
appreciated.
>
> Here is a MRE:?
>
> library(RCurl)
> data <-
> getURL("https://raw.githubusercontent.com/cbenjamin1821/careertech-
> ed/master/elsq2wbl.csv")
Did not work for me probably due to some restriction of data access.
> elsq2wbl <- read.csv(text = data)
>
> ##Recoding Negative Responses to NA
> elsq2wbl [elsq2wbl[, "EVERRELJOB"] < -3,
"EVERRELJOB"] <- NA
> elsq2wbl [elsq2wbl[, "PSWBL"] < -2, "PSWBL"] <-
NA
If you wanted recode values below zero to NA you can do this easily without any
ifelse
> summary(test)       mp             tepl           kryst
 Min.   : 7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.:32.25   1st Qu.:400.0   1st Qu.: 24.15
 Median :37.50   Median :500.0   Median : 26.55
 Mean   :38.44   Mean   :485.7   Mean   : 42.64
 3rd Qu.:44.75   3rd Qu.:600.0   3rd Qu.: 33.62
 Max.   :76.02   Max.   :900.0   Max.   :150.00
 NA's   :3                       NA's   :6> test[is.na(test)] <- 999
> summary(test)       mp              tepl           kryst
 Min.   :  7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.: 34.27   1st Qu.:400.0   1st Qu.: 25.93
 Median : 41.75   Median :500.0   Median : 92.90
 Mean   :244.28   Mean   :485.7   Mean   :452.51
 3rd Qu.: 70.05   3rd Qu.:600.0   3rd Qu.:999.00
 Max.   :999.00   Max.   :900.0   Max.   :999.00>
> test[test>900] <- NA
> summary(test)       mp             tepl           kryst
 Min.   : 7.11   Min.   :100.0   Min.   : 21.70
 1st Qu.:32.25   1st Qu.:400.0   1st Qu.: 24.15
 Median :37.50   Median :500.0   Median : 26.55
 Mean   :38.44   Mean   :485.7   Mean   : 42.64
 3rd Qu.:44.75   3rd Qu.:600.0   3rd Qu.: 33.62
 Max.   :76.02   Max.   :900.0   Max.   :150.00
 NA's   :3                       NA's   :6

>
> #Labeling categorical variable levels
> elsq2wbl$EVERRELJOB <- factor(elsq2wbl$EVERRELJOB, levels = c(0,1),
labels > c("No","Yes"))
> elsq2wbl$PSWBL <- factor(elsq2wbl$PSWBL, levels = c(0,1), labels >
c("No","Yes"))
>
> ##Trying to create a new variable to indicate if the student had a job
> #related to the college studies that was NOT a WBL experience
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
> elsq2wbl$EVERRELJOB=="Yes",1,0)
You can use simple logical functions to get desired result

First sample data> a <- sample(c("Y", "N"), 30, replace=TRUE)
> b <- sample(c("Y", "N"), 30, replace=TRUE)
> (a=="N")*(b=="Y") [1] 1 1 0 0 1 0 0 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1

has 1 only if both conditions are met.

and it works with NA values too.
> a[c(3,5,8)] <- NA
> b[c(3,6,7,8)] <- NA
> (a=="N")*(b=="Y") [1]  1  1 NA  0 NA NA NA NA  0  0  1  0  0  1  0  0  0  0  1  0  0  0  0  0  0
[26]  0  0  0  0  1

Cheers
Petr

>
> #Cross tab to check counts of two variables that new variable is based upon
> xtabs(~PSWBL+EVERRELJOB,subset(elsq2wbl,BYSCTRL==1&G10COHRT==1),add
> NA=TRUE)
>
> #Checking count of newly created variable
> Q2sub <- subset(elsq2wbl,BYSCTRL==1&G10COHRT==1)
> library(plyr)
> count(Q2sub,'NONWBLRELJOB')
>
> #The new variable has the correct count of "1", but 88 cases too
many for "0"
> #The cross tab shows 20 and 68 NA cases that are being incorrectly counted
as
> "0" in the new variable
>
> #My other approach at trying to handle the NAs properly-returns an error
> elsq2wbl$NONWBLRELJOB <- ifelse(elsq2wbl$PSWBL=="No" &
>
elsq2wbl$EVERRELJOB=="Yes",1,ifelse(is.na(elsq2wbl$PSWBL)&is.na(elsq2wbl$
> EVERRELJOB),NA,
>
> ifelse(elsq2wbl$PSWBL!="No" &
elsq2wbl$EVERRELJOB!="Yes",0)))
>
>
>
> Courtney Benjamin
>
> Broome-Tioga BOCES
>
> Automotive Technology II Teacher
>
> Located at Gault Toyota
>
> Doctoral Candidate-Educational Theory & Practice
>
> State University of New York at Binghamton
>
> cbenjami at btboces.org<mailto:cbenjami at btboces.org>
>
> 607-763-8633
>
>       [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny
pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.

This e-mail and any documents attached to it may be confidential and are
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender.
Delete the contents of this e-mail with all attachments and its copies from your
system.
If you are not the intended recipient of this e-mail, you are not authorized to
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by
modifications of the e-mail or by delay with transfer of the email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to immediately
accept such offer; The sender of this e-mail (offer) excludes any acceptance of
the offer on the part of the recipient containing any amendment or variation.
- the sender insists on that the respective contract is concluded only upon an
express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into
any contracts on behalf of the company except for cases in which he/she is
expressly authorized to do so in writing, and such authorization or power of
attorney is submitted to the recipient or the person represented by the
recipient, or the existence of such authorization is known to the recipient of
the person represented by the recipient.

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