Hi
You can check boxplot output by str
> iris[1,1] <- 10
> iris[2,1] <- 8
> bbb <- boxplot(split(iris[,1], iris$Species))
> str(bbb)
List of 6
$ stats: num [1:5, 1:3] 4.3 4.8 5 5.3 5.8 4.9 5.6 5.9 6.3 7 ...
$ n : num [1:3] 50 50 50
$ conf : num [1:2, 1:3] 4.89 5.11 5.74 6.06 6.34 ...
$ out : num [1:3] 10 8 4.9
$ group: num [1:3] 1 1 3
$ names: chr [1:3] "setosa" "versicolor"
"virginica">
and you can find that result is list with out vector containing all outliers and
group vector of indication to which group outliers belong.
Getting the output depends on what you want to do with it.
Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Thomas
> Subia via R-help
> Sent: Thursday, April 7, 2016 6:10 AM
> To: r-help at stat.math.ethz.ch
> Subject: [R] identifying outliers
>
> Thanks for writing this great piece of code.
>
>
>
> x = rnorm(100)
>
> boxplot(x) # you shouldn't see any outliers here although sometimes yow
> will
>
>
>
> # lets add some outliers intentionally
>
> x = c(21, 20, 25, x) # now 10, 15 and 20 are outliers
>
>
>
> myboxplot <- boxplot(x) # now you should see your three outliers
>
>
>
> myboxplot$out # it will print the values of the outliers
>
>
>
> How does one amend this code to produce the outliers by a group?
>
>
>
> All the best,
>
>
>
> Thomas Subia
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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