Puppet users - Sep 2012 - Automatic require in custom type?

Hi.

I have 3 custom types, for example A, B, and C.

A and B are build blocks for C. So if there is no A or B, C will fail to
be added. For example:


typeA { ''A'':
 ...
 ...
}


typeB { ''B'':
 ...
 ...
}

typeC { ''C'':
  optionA => ''A'',
  optionB => ''B'',
}

So, I would have to write the require in this case:

typeC { ''C'':
  optionA => ''A'',
  optionB => ''B'',
  require => [ typeA[''A''], typeB[''B''] ],
}

But, if the user of my module doesn''t specify correct require, typeC
will fail. Should I also write checks for this in the provider of the C
type, or just leave it to fail running extern shell command for managing C?

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On Fri, Sep 14, 2012 at 03:49:56PM +0200, Jakov Sosic
wrote:
> Hi.
> 
> I have 3 custom types, for example A, B, and C.
> 
> A and B are build blocks for C. So if there is no A or B, C will fail to
> be added. For example:
> 
> 
> typeA { ''A'':
>  ...
>  ...
> }
> 
> 
> typeB { ''B'':
>  ...
>  ...
> }
> 
> typeC { ''C'':
>   optionA => ''A'',
>   optionB => ''B'',
> }
> 
> So, I would have to write the require in this case:
> 
> typeC { ''C'':
>   optionA => ''A'',
>   optionB => ''B'',
>   require => [ typeA[''A''],
typeB[''B''] ],
> }
> 
Do you mean a custom type you have defined with

    define typeC($optionA,$optionB) {
      ...
    }

or a custom type you are shipping as a plugin and is written in ruby? If
it is the latter you can use

    Puppet::Type.newtype(:typeC) do
      ...
      autorequire(:typeA) do
        self[:optionA]
      end

      autorequire(:typeB) do
        self[:optionB]
      end
    end

-Stefan

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