Hi I have a iax configuration: [IaxServer] type=friend host=172.16.1.14 port=4569 defaultuser=IaxServer auth=md5 secret=mypassword context=Internal peercontext=Internal qualify=yes trunk=no disallow=all allow=alaw i see the peer: ipbx*CLI> iax2 show peers Name/Username Host Mask Port Status IaxServer 172.16.1.14 (S) 255.255.255.255 4569 (E) OK (6 ms) ipbx*CLI> iax2 show peer IaxServer * Name : IaxServer Secret : <Set> Context : Internal Parking lot : Mailbox : Dynamic : No Callnum limit: 0 Calltoken req: No Trunk : No Callerid : "" <> Expire : -1 ACL : No Addr->IP : 172.16.1.14 Port 4569 Defaddr->IP : 0.0.0.0 Port 0 Username : Codecs : 0x8 (alaw) Codec Order : (alaw) Status : OK (4 ms) Qualify : every 60000ms when OK, every 10000ms when UNREACHABLE (sample smoothing Off) But when i receive the call, my server said: [Apr 24 09:25:30] NOTICE[22148]: chan_iax2.c:10241 socket_process: Rejected connect attempt from 172.16.1.14, request '280 at default' does not exist He search the extention "280" in "default" but not in "Internal" Anyone know why ? for information, the 172.16.1.14 is a old asterisk server and i have put it into calltokenoptional thanks for your help Olivier