rsync - Oct 2006 - strange error when run from cron

Hi all,

            I have the following in a cron job    

/usr/bin/rsync -ub --suffix=~$(date +%F) /Data/Jobs/ /Data/Backups/Jobs/
-razv --no-whole-file  --ignore-errors -partial

 

Problem is that when the command is run on the command line everything
works. However, when its in a cron job it fails with the following,

 

/bin/sh: -c: line 0: unexpected EOF while looking for matching `)'

/bin/sh: -c: line 1: syntax error: unexpected end of file

 

Anyone seen this before or able to put some light on the problem?

 

 

Thanks

Jason Cox

System Administrator
Multiskilled Resources Australia Pty Ltd
ph        02 4908 0000 (office)
ph        02 4908 0015 (direct)
mob       0423 600 156
fx        02 4942 4125

email    jason.cox@multiskilled.com.au

 

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On Tue, 31 Oct 2006, Jason Cox <jason.cox@multiskilled.com.au>
wrote:
> Hi all,
>             I have the following in a cron job    
> /usr/bin/rsync -ub --suffix=~$(date +%F) /Data/Jobs/ /Data/Backups/Jobs/
-razv --no-whole-file  --ignore-errors partial
>   
> Problem is that when the command is run on the command line everything
> works. However, when its in a cron job it fails with the following,
>   
> /bin/sh: -c: line 0: unexpected EOF while looking for matching `)'
> /bin/sh: -c: line 1: syntax error: unexpected end of file
>   
> Anyone seen this before or able to put some light on the problem?
Cron treats '%' as a special character.  From the crontab man page:

     The sixth field of a line in a crontab file is a string that
     is  executed  by the shell at the specified times. A percent
     character in this field (unless escaped by \) is  translated
     to a NEWLINE character.

HTH.

    John