'Windows' path using GetFullPathName() -- code below. My question is how best to do the opposite -- not necessarily from a 'Windows' program. Ex., given a path such as 'C:\PRETEST\GEM01494\GEM01494.RTF', how do I get '/home/justin/.cxoffice/dotwine/fake_windows/pretest/GEM01494/GEM01494.rtf'? I currently have a 'solution' using a lookup table { 'C:': '/home/justin/.cxoffice/dotwine/fake_windows', 'Y:': '/home/justin', 'Z:': '/', } and recursively case-insensitively comparing each remaining part of the path with the folder contents. My 'solution', however, breaks down when given a path such as ex., 'C:\PROG~FBU\MICR~HFZ\TEMP~JWQ\MEMOS\Professional Memo.dot' where the linux path for this is '/home/justin/.cxoffice/dotwine/fake_windows/Program Files/Microsoft Office/Templates/Memos/Professional Memo.dot' as 'PROG~FBU' does not match 'Program Files' <CODE> Option Explicit Private Declare Function GetFullPathName Lib "kernel32" _ Alias "GetFullPathNameA" (ByVal lpFileName As String, _ ByVal nBufferLength As Long, ByVal lpBuffer As String, _ ByVal lpFilePart As String) As Long Sub test() Dim buff As String Dim ret As Long Dim pth As String pth = "/home/justin/.cxoffice/dotwine/fake_windows/pretest/GEM01494/GEM01494.rtf" buff = Space$(1024) ret = GetFullPathName(pth, 1024, buff, "") buff = Left$(buff, ret) Debug.Print ">>>" & buff & "<<<" End Sub </CODE> <OUTPUT>>>>C:\PRETEST\GEM01494\GEM01494.RTF<<<</OUTPUT> <MACHINE> Mandrakelinux 10.0 Wine 20040213 Microsoft Word 97 </MACHINE> Thank you.