similar to: code patterns in vector

Hello, I'm using the eclat function of the arules package (1.0-6) for the identification of frequent itemsets. I need the tidLists, but if I set in the function tidLists=TRUE R crashes (Windows XP Professional SP3, 32 bit, R version 2.12.1 (2010-12-16), reproducible on two different computers) with two different error messages or non at all. Minimum examples are: library(arules)

Dear All, I'm dealing with a case, where 'manhattan' distance of each of 100 vectors is calculated from 10000 other vectors. For achieving this, following 4 scenarios are tested: 1) scenario 1: > x<-read.table("query.vec") > v<-read.table("query.vec2") > d<-matrix(nrow=nrow(v),ncol=nrow(x)) > for (i in 1:nrow(v)){ + d[i,]<-

Hello Wise Ones... I need a clever way around a problem with findInterval. Consider: vec1 <- 1:10 vec2 <- seq(1, 10, by = 0.1) x1 <- c(2:3) a1 <- findInterval(x1, vec1); a1 # example 1 a2 <- findInterval(x1, vec2); a2 # example 2 In the problem I'm working on, vec* may be either integer or numeric, like vec1 and vec2. I need to remove one or more sections of this vector;

I want to create a number of vectors like : vec1 <- rnorm(1) vec2 <- rnorm(2) vec3 <- rnorm(3) and so on........... Here I tried following : for (i in 1:10) paste("vec", i, sep="") <- rnorm(i) However obviously that is not working. Here vectors I need to be seperated i.e I do not want to create a "list". How to modify above code? -- View this

Dear all, Without a loop, I would like transform 3 numeric vectors empty of 0/1 of same length Vec1 : transform 1 to A and 0 to "" Vec2 : transform 1 to B and 0 to "" Vec3 : transform 1 to C and 0 to "" to obtain only 1 vector Vec who is the paste of the 3 vectors (Ex : ABC, BC, AC, AB,...) Any idea ? Thank you for your help -- Michel ARNAUD

Hi! I'm new to R and have problems with the following code: <code> awprob<-c(0.4,0.4,0.1,0.1) awsample<-sample(c(1:4),3,awprob,replace=TRUE) vec<-vector(mode="numeric",10000) vec[]<-sum(sample(c(1:4),20,awprob,replace=TRUE)) </code> My problem: The elements of vec have the same value. How can I tell R that I want to have a *new* sample for each value and

Simple one, have read and googled, still no luck! I want to create several empty vectors all of the same length. I would like multiple empty vectors (vec1, vec2, vec3) and want to create them all in one line. I've tried vec1,vec2,vec3 <- vector(length=5) and c(vec1,vec2,vec3) <- vector(length=5) and several other attempts but nothing seems to work ... suggestions? Thanks Jim

Hi, May be this helps: vec<- "this is a nice text with nice characters" library(stringr) ?vec2<-unlist(str_match_all(vec,"\\w+")) #or # vec2<-str_split(vec," ")[[1]] res<-unique(lapply(vec2,function(x) which(!is.na(match(vec2,x))))) ?names(res)<- unique(vec2) res #$this #[1] 1 # #$is #[1] 2 # #$a #[1] 3 # #$nice #[1] 4 7 # #$text #[1] 5 # #$with #[1]

Hi, there I'm currently trying to figure out how to keep my "factor" levels for a variable when moving it from one data frame or matrix to another. Example below: vec1<-(rep("10",5)) vec2<-(rep("30",5)) vec3<-(rep("80",5)) vecs<-c(vec1, vec2, vec3) resp<-rnorm(2,15) dat<-as.data.frame(cbind(resp, vecs))

Hello list, I just started R today and tried something quite simple. I wanted to create a colored plot and eventually after hours of fiddling around got it working. However, my solution seems very suboptimal and I'd really appreciate your hints on how to improve. I believe that R already offers many functions I coded (e.g. distance between two vectors, vector length, vector normalization and

Hello R-users, I need to create a vector inserting an 1 after each value of another vector. For example: vec1<-c(2,3,4) I need to create a vector with the values 2,1,3,1,4 Does anyone know how create this vector without loops (vec1 could have 1000 elements) Thank you, Juan -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

Hello. Sorry I am not sure this question should go to llvm or mesa3d-dev mailing list, so I post it to both. I am writing a llvm backend for a modern graphics processor which has a ISA very similar to that of Direct 3D. I am reading the code in Gallium-3D driver in a mesa3d branch, which converts the shader programs (TGSI tokens) to LLVM IR. For the shader instruction also found in LLVM IR,

I would like to selectively remove rows from a table. I had hoped that I could create a table and selectively add rows with something like > NewTable<-table(nrow=100, ncol=4) > NewTable[1,]<-OldTable[10,] but that doesn't work. The former call gives > NewTable ncol nrow 4 100 1 while the latter call gives a table the length of OldTable. Making a matrix, m, with the

Dear expeRts, I know I can't paste expressions in the normal way, but I just couldn't figure out how to get the following (I want to paste a character vector to an expression vector) right with bquote() or substitute. vec1 <- c("a", expression(tilde(b)), "c") vec2 <- c("1", "2", "3") main <- as.expression(paste(vec1, vec2))

Hi all, I have 4 matrices, each having 5 columns and 4 rows .....denoted by B1,B2,B3,B4. I have generated a vector of 7 indices, say (1,2,4,3,2,3,1} which refers to the index of the matrices to be chosen and then appended one on the top of the next: like, in this case, I wish to have the following mega matrix: B1over B2 over B4 over B3 over B2 over B3 over B1. 1> How can I achieve this?

Hi, Try: ?vec1<-c(1,1,1,1,1,1,1,1,1) if(all(vec1==1)) "xxxxxxxxx" else? "yyyyyyyyyyy" #[1] "xxxxxxxxx" ?vec2<-c(rep(1,4),2) ?if(all(vec2==1)) "xxxxxxxxx" else? "yyyyyyyyyyy" #[1] "yyyyyyyyyyy" #or if(length(unique(vec1))==1) "xxxxxxxxx" else? "yyyyyyyyyyy" #[1] "xxxxxxxxx" ? if(length(unique(vec2))==1)

Is there any built-in way to lexicographically compare two vectors of the same length in R? The textbook algorithm could be coded as follows: lex.cmp <- function (vec1,vec2) { for (j in 1:length(vec1)) { if (vec1[j] < vec2[j]) { return(-1) } if (vec1[j] > vec2[j]) { return(1) } } return(0) } Thanks, Gabriel

On Jun 27, 2008, at 8:02 AM, Stefanus Du Toit wrote: >>>> <result> = shufflevector <a x <ty>> <v1>, <b x <ty>> <v2>, <d x >>>> i32> >>>> <mask> ; yields <d x <ty>> >>> >>> With the requirement that the entries in the (still constant) mask >>> are >>> within

This is to announce that XMCD 2.1 patchlevel 0 has been released which fixes all of the issues previously raised by David Meltzer. It also contains a number of other minor feature and functionality enhancements. The new version may be obtained via the xmcd web page at: http://sunsite.unc.edu/~cddb/xmcd/ Users of xmcd with older versions are encouraged to upgrade. -Ti -- \\ // XMCD - Motif CD

To clear up a question regarding my earlier posting regarding random changes in a vector: Say you have a vector (1, -1, -1, 1, 1, -1). I want each value in the vector to have a probability that it will change signs when this vector is regenerated. For example, probability = 50%. When the vector is regenerated, the first value in the vector (1) has a 50% chance of switching to -1. If I