Displaying 20 results from an estimated 10000 matches similar to: "How to handle large numbers?"
2007 Aug 30
7
Behaviour of very large numbers
Dear all,
I am struggling to understand this.
What happens when you raise a negative value to a power and the result
is a very large number?
B
[1] 47.73092
> -51^B
[1] -3.190824e+81
# seems fine
# now this:
> x <- seq(-51,-49,length=100)
> x^B
[1] NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN <snip>
> is.numeric(x^B)
[1] TRUE
> is.real(x^B)
[1]
2008 May 28
1
indexing lists, using brobdingnagian
Dear R-Gurus,
I have ended up with a calculation problem where I need to use brobs.
I have to work my way through a vector with a for loop to act on each
element in a calculation (refering to the previous
value in the new vector of results -- so as far as I know I can't use
"apply") -- this produces a list of brobs.
My problem is, how do I act on, plot this list, or do vector
2006 Aug 30
1
setMethod() and log()
Hi
I am having difficulty with setMethod(). I have a "brob" class of
objects whose
representation has two slots: "x" and "positive". Slot "x" (double)
holds the log
of a number and slot "positive" (logical) its sign. The idea is
that large numbers
can be handled.
I'm trying to implement a log() method using an analogue of the
2007 Nov 08
1
Bug (?) in read.fwf
Hi,
I'm trying to use read.fwf
temp = read.fwf ("Raw data.txt", widths = c (11, 21, 10, rep
(16, 6)) ,skip = 2, n = 2, stringsAsFactors = FALSE, strip.white = TRUE)
but no matter what I do the strings are turned into factors. I believe
it's the "n=2" parameter that causes the problem as it seems to work
without this. Am I missing something?
Thanks in advance,
2010 Oct 27
2
Which version control system to learn for managing Rprojects?
Gabor
As someone trying to the rest of my team using Subversion (which I have used for a while, but more as a backup / record of changes), have you a neat / automated way of building a package from a subversion repository?
Thanks
David Jessop
--------------------------
David Jessop
Global Head of Quantitative Research
UBS Investment Research
+44 20 7567 9882
----- Original Message -----
2006 Oct 31
1
setReplaceMethod
Hi
If x <- 1:10 then x[5] <- 1i will promote
x to be a complex vector.
Suppose I have an S4 class "brob", and have functions
is.brob(), as.brob(), as.numeric() and so forth (minimal self-contained
code below).
If x is numeric (1:10, say) and y is a brob, what
is the best way to make
x[5] <- y
promote x to a brob in the same way as the complex example?
Or is
2006 Sep 15
1
setMethod() woes
Hello everybody
R version 2.4.0 alpha (2006-09-15 r39323), MacOSX 10.4.7
Next S4 problem.
I have "brob" objects that are large real numbers, and now I want "glub"
numbers that are to be a pair of glubs that represent complex numbers.
I want to define binary operator "+" so that if either the left or right
argument are glubs, it uses .ArithGlub.
If either
2006 Sep 04
1
setMethod("Summary")
Hi everyone and thanks for being patient. I've used "!.foo"() et
seq pro tem.
Next problem: how to define "Summary" methods for brobs.
?max says
'max' and 'min' are generic functions: methods can be defined for
them individually or via the 'Summary' group generic. For this to
work properly, the arguments '...' should be
2005 Feb 28
2
A problem about outer()
Dear all,
I have something about function outer() that I can't understand. Just see the following example. The two NaNs are due to 0/0, but I can't figure out the cause of the last two errors. I wonder if some one can explain this for me.
___________________________________________________________________
> sx=rbinom(10,1,0.5);ot=rbinom(10,1,0.5);ag <- rbinom(10,100,0.3);ho <-
2010 Oct 08
2
Error message in as.brob Usage
I am getting the following error message while using the as.brob function in
some computations:
Error in out.x[ss] <- pmax(x1[ss], x2[ss]) + log1p(+exp(-abs(x1[ss] - :
NAs are not allowed in subscripted assignments
Is there any obvious mistake I am making here that can resolve the above
error message?
Thanks for your help.
Chow
--
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2006 Sep 01
1
setMethod("Logic", ...)
Hi
In V&R the "polynomial" class is explicitly specified to have no
logical operators:
setMethod("Logic", signature(e1="polynomial"), function(e1,e2){stop
("...")})
I too have a class of objects for which I want to
specify that Logic operators do not work, but executing
setClass("brob",
representation = representation
2011 Aug 03
1
NAMESPACE problems
Hi.
I am having difficulty following section 1.6.6 of the R-extensions manual.
I am trying to update the Brobdingnag package to include a NAMESPACE file (the
untb package requires the Brobdingnag package).
Without the NAMESPACE file, the package passes R CMD check cleanly.
However, if I include a NAMESPACE file, even an empty one, R CMD check
gives the following error in 00install.out:
2011 Jun 21
2
Documentation
I am new in R.
Can anyone tell :
1. how we can write our own functions in R ?
2. how we can save those functions and recall to use them?
3. what extensions are used for saving a file?
--
Siddharth Arun,
4th Year Undergraduate student
Industrial Engineering and Management,
IIT Kharagpur
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2002 Nov 07
2
The integration of the square of the c.d.f of normal distribution
Assume F(x) is the cdf of stardard normal c.d.f,
and want to get the integration of F(x)^2 over
(-infinite, +infinite).
So whats the value of this integration?
And is there some function to achieve this?
Thanks.
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Send "info",
2007 Nov 21
1
equivalent of Matlab robustfit?
Hi,
I've been using the Matlab robustfit function for linear regressions
where I suspect some data points are outliers. Is there an equivalent
function in R?
Take care, Darren
PS, This is the Matlab help on robustfit:
>> help robustfit
ROBUSTFIT Robust linear regression
B = ROBUSTFIT(X,Y) returns the vector B of regression coefficients,
obtained by performing robust
2008 Aug 11
1
A zoo question / problem
Hi
I'm having a problem using the zoo library and I can't see what I'm
doing wrong. For example setting up the data
> t1 = zoo (matrix (1:12, nrow = 3), order.by = as.Date
(c("2008-08-01","2008-08-02","2008-08-03")))
> colnames (t1) = c ("A", "B", "C", "D")
> t2 = zoo (matrix (1:12, nrow = 3), order.by =
2008 Apr 11
4
Object.isNumber() returns true on NaN??
Hi,
Object.isNumber() returns true on NaN. I don''t think that''s true....
NaN is Not a Number so it''s not a number... right?
By the way, I''m using Prototype 1.6.0.2.
Satoru
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2011 Mar 16
2
Singularity problem
Dear R,
If I have remembered correctly, a square matrix is singular if and only if
its determinant is zero. I am a bit confused by the following code error.
Can someone give me a hint?
> a <- matrix(c(1e20,1e2,1e3,1e3),2)
> det(a)
[1] 1e+23
> solve(a)
Error in solve.default(a) :
system is computationally singular: reciprocal condition number = 1e-17
Thanks in advance!
Feng
--
2009 Jan 03
5
Power functions?
I had a question about the basic power functions in R.
For example from the R console I enter:
-1 ^ 2
[1] -1
but also
-1^3
[1] -1
-0.1^2
[1] -0.01
Normally pow(-1, 2) return either -Infinity or NaN. Has R taken over the math functions? If so I would think that -1^2 is 1 not -1 and -0.1^2 is 0.01 not -0.01.
Thank you.
Kevin
2000 Nov 07
3
infinity in integrate function in R
sorry the integration was from -Inf to 1.96
The integrate function in R is not taking Inf (infinity). How do you use
infinity in R. I was doing: integrate(dnorm,- Inf, 1.96) and I was getting
Error: NA/NaN/Inf in foreign function call (arg 2). Obviously this should
be equal to pnorm(1.96)= 0.9750021. How do you get around the infinity
problem in R?