similar to: Combining Custom and Preset Linetypes

Dear R-Users, I created the xyplot below using 10 groups (9 groups + 'Total' of all groups) with lty=1:10. I need the 'Total' to be a bold solid line (lty=1) where as the 9 groups just need to be distinguishable from each other. As you can probably see, when the group reaches CRA6 the lty starts from 1 again. I have tried to specify ten unique lines using lty=

I am confused by the behavior of the lines function when the lty argument is a vector. ?lines indicates that lty is a valid parameter, but says nothing else about it. ?plot.xy (which I think is what gets called) refers back to ?lines. ?plot.default says to see ?par. In ?par, about lty it says "Some functions such as lines accept a vector of values which are recycled. Other uses will take

The Blue Book allows the 'type' argument to be used in matpoints and matlines. matlines(x, y, type="l", lty=1:5, pch=, col=1:4) R-1.0.0 does not. Thus, type="h", "b", must be invoked thru matplot( x, y, type = "h", add=TRUE) For the sake of consistency with S, it would be nice to have matlines defined as: "matlines" <-

Dear All, When I plot the values and linear regression line for one data set, it is fine. But for another one I see zigzags, when I plot the confidence interval >cd Depth CHAOsep12RNA 9,94 804 25,06 1476,833333 40,04 1540,561404 50,11 1575,166667 52,46 349,222222 54,92 1941,5 57,29 1053,507042 60,11 1535,1 70,04 2244,963303 79,97 1954,507042 100,31 2679,140625 >

Dear R help, This seems to be a commonly asked question and I am able to run examples that have been proposed, but I can't seems to get this to work with my own data. Reproducible code is below. Thank you in advance for any help you can provide. The main problem is that I can not get the confidence lines to plot correctly. The secondary problem is that predict is not able to find my object

I have a sample of lung capacities from a population measured against height. I need to know the 95% CI of the lung capacity of a person of average height. I have fitted a regression line. How do I get a minimum and maximum values of the 95% CI? My thinking was that this has something to do with covariance, but how? My other thinking was that I could derive the 0.975 (sqrt 0.95) CI for the

Dear R-Users I have 2 questions: Firstly, If I create a matplot and legend for multiple vectors and then tag another vector on using matlines (e.g. a 'total' of all vectors), is there anyway to add the new line to the legend without recreating it? I have created the plot this way because I would like to define the lty and lwd for the 'total' vector so that it can be

Dear all I have tried to estimate the confidence intervals for predicted values of a nonlinear model fitted with nls. The function predict gives the predicted values and the lower and upper limits of the prediction, when the class of the object is lm or glm. When the object is derived from nls, the function predict (or predict.nls) gives only the predicted values. The se.fit and interval aguments

Hi I had to use a glm instead of my basic lm on some data due to unconstant variance. now, when I plot the model over the data, how can I easily get the 95% confidence interval that sormally coming from: > yv <- predict(modelVar,list(aveLength=xv),int="c") > matlines(xv,yv,lty=c(1,2,2)) There is no "interval" argument to pass to the

On Tue, 06 Feb 2018 12:43:20 -0500 Dan Oriani via samba <samba at lists.samba.org> wrote: > Quoting Dan Oriani via samba <samba at lists.samba.org>: > > There seems to be an open bug open about this issue, > https://bugs.debian.org/cgi-bin/bugreport.cgi?bug=858981, however > the FQDN of this machine is already in /etc/hostname, which seemed to > be the

Hi all, I want to plot the grouped means of some variables. The dependent variables and the grouping factor are stored in different columns. I want to draw a simple line-plot of means, in which the x-axis represents the variables and y-axis represents the means. The means of the groups should be connected by lines. So far, the only function that I could find comes closest to what I'm

Dear friends, I met a problem on plotting. My dataset is : year MHBC LHBC MHRC LURC 1993 11.75 4.50 0.43 0.46 1994 7.25 1.25 0.35 0.51 1995 8.67 2.17 0.54 0.44 1996 2.67 1.33 0.78 0.47 1997 3.42 4.92 0.69 0.48 1998 1.92 3.08 0.72 0.54 1999 2.33 2.58 0.74 0.41 2000 5.75 4.50 0.45 0.50 2001 3.75 4.42 0.52 0.47 2002 2.33

On Tue, 06 Feb 2018 14:09:08 -0500 Dan Oriani via samba <samba at lists.samba.org> wrote: > > I'm not opposed to the idea. Does 'net ads join' support supplying > the machine name as the user, and the one-time-password given to it? > The only reason I'm using adcli at all is the preset-computer option > which I couldn't find an analogue to in 'net

Dear R-list, I'm iterating several calls to plotCI [gplots], like so: plotCI( x = xvals.f[sorted], y = yvals.f[sorted], xlim = c(xmin, xmax), ylim = c(ymin, ymax), pch = plot_symbols[graph_idx], type = "b", lty = plot_linetypes[1], col = plot_colors[graph_idx], barcol = plot_colors[graph_idx], uiw = NA, xlab = "", ylab = "", add =

Hello all, I'm kind of pulling my hair out over here. I'll preface this by saying that I'm using the latest version of Samba packaged in Debian Stretch as my domain controller. Currently, I'm trying to build an infrastructure where I can deploy a new virtual machine, then have it automatically join the domain so that users can log in to it without very much (if any)

Hi, I have a dataset called 'fish'. fish$Species returns extract 1. When I use fish$Species != c("CRA","PHC"), i.e. I want all species except "CRA" and "PHC", I get extract 2 which is blatantly wrong. Can anyone see what I'm doing wrong? Regards, James EXTRACT 1 > fish$Species [1] ALB ALB ALB ALB ALB ALB ALB ALB ALB ALB ALB ALB ALB

Hi R People: If I have a fitted values from a model, how do I plot the (1-alpha)100% confidence intervals along with the fitted values, please? Also, if the intervals are "shaded" gray, that would be nice too, please? I check confint, but that doesn't seem to do what I want. Thanks in advance, Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and

Anyone who is interested in using optimal colour palettes should look at the work of Cindy Brewer: www.colorbrewer.org I have written code to use her colour schemes in R. It is included below. Perhaps someone may find this interesting enough to work into a package. Included also is a function showpalette, which was posted here a while back. I don't remember who wrote it. I have copied all

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

Quoting Dan Oriani via samba <samba at lists.samba.org>: > Quoting Rowland Penny via samba <samba at lists.samba.org>: > >> On Tue, 06 Feb 2018 14:09:08 -0500 >> Dan Oriani via samba <samba at lists.samba.org> wrote: >> >>> >>> I'm not opposed to the idea. Does 'net ads join' support supplying >>> the machine name as