Displaying 20 results from an estimated 10000 matches similar to: "Combining Custom and Preset Linetypes"
2009 Jan 22
1
Defining Solid Line using Line Type Specification
Dear R-Users,
I created the xyplot below using 10 groups (9 groups + 'Total' of all
groups) with lty=1:10. I need the 'Total' to be a bold solid line (lty=1)
where as the 9 groups just need to be distinguishable from each other. As
you can probably see, when the group reaches CRA6 the lty starts from 1
again. I have tried to specify ten unique lines using lty=
2008 Nov 20
1
Vector lty argrument for lines or plot
I am confused by the behavior of the lines function when the lty argument is a vector. ?lines indicates that lty is a valid parameter, but says nothing else about it. ?plot.xy (which I think is what gets called) refers back to ?lines. ?plot.default says to see ?par. In ?par, about lty it says "Some functions such as lines accept a vector of values which are recycled. Other uses will take
2000 Mar 26
1
matlines, matpoints don't follow prototype (PR#506)
The Blue Book allows the 'type' argument to be used in matpoints and
matlines.
matlines(x, y, type="l", lty=1:5, pch=, col=1:4)
R-1.0.0 does not.
Thus, type="h", "b", must be invoked thru matplot( x, y, type = "h",
add=TRUE)
For the sake of consistency with S, it would be nice to have matlines
defined as:
"matlines" <-
2013 May 17
2
zigzag confidence interval in a plot
Dear All,
When I plot the values and linear regression line for one data set, it is fine. But for another one I see zigzags, when I plot the confidence interval
>cd
Depth CHAOsep12RNA
9,94 804
25,06 1476,833333
40,04 1540,561404
50,11 1575,166667
52,46 349,222222
54,92 1941,5
57,29 1053,507042
60,11 1535,1
70,04 2244,963303
79,97 1954,507042
100,31 2679,140625
>
2009 Mar 12
3
help with predict and plotting confidence intervals
Dear R help,
This seems to be a commonly asked question and I am able to run examples that have been proposed, but I can't seems to get this to work with my own data. Reproducible code is below. Thank you in advance for any help you can provide.
The main problem is that I can not get the confidence lines to plot correctly.
The secondary problem is that predict is not able to find my object
2004 Nov 24
2
confidence interval of a average...
I have a sample of lung capacities from a population measured against
height. I need to know the 95% CI of the lung capacity of a person of
average height.
I have fitted a regression line.
How do I get a minimum and maximum values of the 95% CI?
My thinking was that this has something to do with covariance, but how?
My other thinking was that I could derive the 0.975 (sqrt 0.95) CI for the
2009 Jan 14
1
Help with Plot/Legend
Dear R-Users
I have 2 questions:
Firstly, If I create a matplot and legend for multiple vectors and then tag
another vector on using matlines (e.g. a 'total' of all vectors), is there
anyway to add the new line to the legend without recreating it? I have
created the plot this way because I would like to define the lty and lwd for
the 'total' vector so that it can be
2004 Jun 03
5
Confidence intervals for predicted values in nls
Dear all
I have tried to estimate the confidence intervals for predicted values of a
nonlinear model fitted with nls. The function predict gives the predicted
values and the lower and upper limits of the prediction, when the class of
the object is lm or glm. When the object is derived from nls, the function
predict (or predict.nls) gives only the predicted values. The se.fit and
interval aguments
2010 Sep 28
1
95% confidence intercal with glm
Hi
I had to use a glm instead of my basic lm on some data due to unconstant
variance.
now, when I plot the model over the data, how can I easily get the 95%
confidence interval that sormally coming from:
> yv <- predict(modelVar,list(aveLength=xv),int="c")
> matlines(xv,yv,lty=c(1,2,2))
There is no "interval" argument to pass to the
2018 Feb 06
2
Inconsistent results while attempting to preset a computer with a one-time-password
On Tue, 06 Feb 2018 12:43:20 -0500
Dan Oriani via samba <samba at lists.samba.org> wrote:
> Quoting Dan Oriani via samba <samba at lists.samba.org>:
>
> There seems to be an open bug open about this issue,
> https://bugs.debian.org/cgi-bin/bugreport.cgi?bug=858981, however
> the FQDN of this machine is already in /etc/hostname, which seemed to
> be the
2008 Sep 09
6
plotting group means
Hi all,
I want to plot the grouped means of some variables. The dependent variables
and the grouping factor are stored in different columns. I want to draw a
simple line-plot of means, in which the x-axis represents the variables and
y-axis represents the means. The means of the groups should be connected by
lines. So far, the only function that I could find comes closest to what I'm
2006 Sep 28
1
help on plots
Dear friends,
I met a problem on plotting.
My dataset is :
year MHBC LHBC MHRC LURC
1993 11.75 4.50 0.43 0.46
1994 7.25 1.25 0.35 0.51
1995 8.67 2.17 0.54 0.44
1996 2.67 1.33 0.78 0.47
1997 3.42 4.92 0.69 0.48
1998 1.92 3.08 0.72 0.54
1999 2.33 2.58 0.74 0.41
2000 5.75 4.50 0.45 0.50
2001 3.75 4.42 0.52 0.47
2002 2.33
2018 Feb 06
2
Inconsistent results while attempting to preset a computer with a one-time-password
On Tue, 06 Feb 2018 14:09:08 -0500
Dan Oriani via samba <samba at lists.samba.org> wrote:
>
> I'm not opposed to the idea. Does 'net ads join' support supplying
> the machine name as the user, and the one-time-password given to it?
> The only reason I'm using adcli at all is the preset-computer option
> which I couldn't find an analogue to in 'net
2006 Oct 16
2
set linetype with plotCI
Dear R-list,
I'm iterating several calls to plotCI [gplots], like so:
plotCI(
x = xvals.f[sorted],
y = yvals.f[sorted],
xlim = c(xmin, xmax), ylim = c(ymin, ymax),
pch = plot_symbols[graph_idx], type = "b",
lty = plot_linetypes[1],
col = plot_colors[graph_idx],
barcol = plot_colors[graph_idx], uiw = NA,
xlab = "", ylab = "",
add =
2018 Feb 01
2
Inconsistent results while attempting to preset a computer with a one-time-password
Hello all, I'm kind of pulling my hair out over here.
I'll preface this by saying that I'm using the latest version of Samba
packaged in Debian Stretch as my domain controller. Currently, I'm trying to
build an infrastructure where I can deploy a new virtual machine, then have
it automatically join the domain so that users can log in to it without very
much (if any)
2009 Nov 03
3
Weird operator behaviour
Hi,
I have a dataset called 'fish'. fish$Species returns extract 1. When I use
fish$Species != c("CRA","PHC"), i.e. I want all species except "CRA" and
"PHC", I get extract 2 which is blatantly wrong. Can anyone see what I'm
doing wrong?
Regards,
James
EXTRACT 1
> fish$Species
[1] ALB ALB ALB ALB ALB ALB ALB ALB ALB ALB ALB ALB ALB
2024 Jul 16
2
Automatic Knot selection in Piecewise linear splines
>>>>> Anupam Tyagi
>>>>> on Tue, 9 Jul 2024 16:16:43 +0530 writes:
> How can I do automatic knot selection while fitting piecewise linear
> splines to two variables x and y? Which package to use to do it simply? I
> also want to visualize the splines (and the scatter plot) with a graph.
> Anupam
NB: linear splines, i.e. piecewise
2009 Jul 14
5
plotting confidence intervals
Hi R People:
If I have a fitted values from a model, how do I plot the
(1-alpha)100% confidence intervals along with the fitted values,
please?
Also, if the intervals are "shaded" gray, that would be nice too, please?
I check confint, but that doesn't seem to do what I want.
Thanks in advance,
Sincerely,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and
2005 Jul 07
2
Brewer colours
Anyone who is interested in using optimal colour palettes should
look at the work of Cindy Brewer: www.colorbrewer.org
I have written code to use her colour schemes in R. It is
included below. Perhaps someone may find this interesting enough
to work into a package.
Included also is a function showpalette, which was posted here a
while back. I don't remember who wrote it.
I have copied all
2013 Mar 29
1
multiple plots and looping assistance requested (single plot)
HI Irucka,
Please check this:
temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L,
2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342,
12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA,
-4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L,
3L, 4L, 5L, NA), Data1 = c(1.52,