similar to: Find all numbers in a certain interval

All: Are there any functions out there for selecting all the points in a region of a plot. I envision something like the identify() function except one could circle a cloud of points (and perhaps a vector would be returned of the same length as the points plotted indicating logical membership in the circled cloud). Perhaps someone has done something with the locator() function that would

Dear R help I was hoping you might be able to show me how to write a loop function take would ccomplish this task. library(prob) { a <- sample ( 1:20, 100, replace=T) b<-sample(5:24,100,replace=T) } dd <- data.frame(a,b) dd # code piece I am looking for if(subset(dd,c(1,23,ordered=F))is found))( print subset) else( continue evaluating subsets) subset(dd,isin(dd,c(1,23), ordered =

Hi there, I'm trying to solve a boxplot problem (should be simple, but I cannot find the solution...): data <- list( "long_name1_xxxxxxxxxxx" = rnorm(100), "long_name2_yyyyyyyyyyyyyy" = rnorm(200)) boxplot(data , las = 2, mar = c(20,4,4,4)) Why does the margin not change whatever I put there??? With other plots it worked for me, why not in this case? I just want to

I am trying to use if...else loop and have included a code snippet which I might like to expand. Maybe you could steer me in the right direction. library(stats) library(prob) { a <- sample ( 1:4,100, replace=T,prob=c(0.1,0.2,0.5,0.3)) b<-sample(3:6,100,replace=T,prob=c(0.2,0.2,0.2,0.4)) } dd <- data.frame(a,b) if (subset finds a vector) ( print that vector) (else

Hi R, Can I convert ISIN numbers into Bloomberg tickers in the RBloomberg package? BR, Shubha [[alternative HTML version deleted]]

Hi there, I am wondering if it is possible to do an xyplot with two y-axes. I'd like to print two parameters in a time series but they both have different scales. Which parameter in xyplot can I add to achieve this result? Thanks a lot for any help. Antje [[alternative HTML version deleted]]

Hello List, I have few installations out there based on 1.6.1 or above. I'm trying to play different voice mail messages based on certain criteria's. For example, I want during office hours to play (in short): "we are not available to take your call, please leave a message", during off-hours and weekends I would play: "we are closed, our opening hours xx:xx-yy:yy, please

Hello, I tried to fit a poisson distribution but looking at the function fitdistr() it does not optimize lambda but simply estimates the mean of the data and returns it as lambda. I'm a bit confused because I was expecting an optimization of this parameter to gain a good fit... If I would use mle() of stats4 package or mle2() of bbmle package, I would have to write the function by myself

Hello, I'm looking for a solution for the following problem: I have two vectors V1 <- c("apple","honey","milk","bread","butter") V2 <- c("bread","milk") now, I would like to know for each element in V1 if it's equal to one of the elements in V2 I could do: which(V1 == V2[1] | V1 == V2[2]) but what if I

Hello, I have a question how to reshape a given matrix to a data frame. # ---------------------------------- > a <- matrix(1:25, nrow=5) > a [,1] [,2] [,3] [,4] [,5] [1,] 1 6 11 16 21 [2,] 2 7 12 17 22 [3,] 3 8 13 18 23 [4,] 4 9 14 19 24 [5,] 5 10 15 20 25 > colnames(a) <- LETTERS[1:5] > rownames(a) <-

Hello, I'm trying to plot a set of barplots like a matrix (2 rows, 10 columns from"reduced_mat") to a pdf. It works with the following parameters: pdf("test.pdf",width=ncol(reduced_mat)*2, height=nrow(reduced_mat)*2, pointsize = 12) par(mfcol = c(nrow(reduced_mat),ncol(reduced_mat)), oma = c(0,0,0,0), lwd=48/96, cex.axis = 0.5, las = 2, cex.main = 1.0) The I get a

Hello, I'm not very experienced with lattice and I was wondering whether I get get some hints from you how to create a pure heatmap (using levelplot), without any axis, title, legend, margin at all... I just want to see the coloured squares, nothing else. Any suggestions? Antje

Should call celt_inner_prod(). --- celt/bands.c | 7 ++++--- celt/bands.h | 2 +- celt/celt_encoder.c | 6 +++--- celt/pitch.c | 2 +- src/opus_multistream_encoder.c | 2 +- 5 files changed, 10 insertions(+), 9 deletions(-) diff --git a/celt/bands.c b/celt/bands.c index bbe8a4c..1ab24aa 100644 --- a/celt/bands.c +++ b/celt/bands.c

Hello, I hope this question is not too stupid. I would like to know how to update levels after subsetting data from a data.frame. df <- data.frame(factor(c("a","a","c","b","b")), c(4,5,6,7,8), c(9,1,2,3,4)) names(df) <- c("X1","X2","X3") my.sub <- subset(df, X1 == "a" | X1 == "b")

Hi there, as I'm not sure to understand the coloring levelplot uses, I'm looking for another easy way to create a heatmap like this: library(lattice) mat <- matrix(seq(1,5, length.out = 12), nrow = 3) mat[1,2] <- 3.5 my.at <- seq(0.5,5.5, length.out = 6) my.col.regions <- rainbow(5) graph <- levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions = my.col.regions)

Hi there, assume that you have data with different sampling like d1 <- rnorm(100) d2 <- rnorm(150) now, I'd like to create two boxplots in one graph but each plot located at the sampling number at the x-axis. This, I can do with "at" l <- list(d1,d2) boxplot(l, at=c(length(d1), length(d2)), xlim=c(0,200) ) but both plots are very thin and I'd like to increase the

Dear list, I'd like to access the elements of a list within another list with the help of a variable. dict <- list( "24" = c(1,2,3,6,12,24,48,72,96,120,144,168,720), "168" = c(1,12,24,48,72,96,120,144,168,336,504,672), "8760" = c(1,24,168,730,4380,8760) ) dict$"24" works fine, but a <- "24" dict$a returns

Hei R Users, i have the following dataframe: Datetime Temperature and many more collumns 1 2008-6-1 00:00:00 5 2 2008-6-1 02:00:00 5 3 2008-6-1 03:00:00 6 4 2008-6-1 03:00:00 0 5 2008-6-1 04:00:00 6 6 2008-6-1 04:00:00 0 7 2008-6-1 05:00:00 7 8 2008-6-1 06:00:00

Hi there, I though there has been a possibility to force the output on the console with one element per line. Instead of this: > 1:10 [1] 1 2 3 4 5 6 7 8 9 10 something like this > 1:10 [1] 1 [2] 2 [3] 3 [4] 4 [5] 5 [6] 6 [7] 7 [8] 8 [9] 9 [10] 10 Can anybody help? Antje

Hi folks, I've just discovered that the following code leads to boxplot (surprisingly to me). Can anybody explain to me why? Is this documented somewhere? I've never consider this option before. x <- rnorm(300) l <- c(rep("label1",100), rep("label2",50), rep("label3",150)) df <- data.frame(as.factor(l), x) plot(df) Thank you! Antje