similar to: Bootstrap a GLM model with Poisson family

Hi List,   I’ m analysing the selectivity of resting site use by forest carnivores through mixed modelling techniques and I wonder which will be the best r package to deal with several aspects simultaneously: -          binomial variable response; -          possible spatial and/or temporal correlation; I have tried nlme (lme function) and lme4 (lmer function) packages, however I realize that the

Dear R_help list members!   I’m studding forest carnivores and I have data on resting site selection and use!   I’m trying to model the probability that a forest carnivore might have in be located in a tree hollow (1) (the main resting site selected) rather than elsewhere (0) (other resting site types, dens, nests, etc.). The model should be related with several variables such as for instance:  

Hi, I live in Portugal. I have a Windows 2000 server with file sharing activated in my company. I have a linux box with a 200Gb disk for backups with rsync. I make an smbmount to /mnt/w2kbox then I use rsync like this: rsync -ar /mnt/w2kbox /200gb_disk The problem is that we use accents and cedillas and those files are not copied to the backup directory. Rsync says: file has vanished:

Dear all can anyone tell me how to mark packet''s DSCP value using tc? Thanks. Regards, philip -- Hong Kong IP Multicast Initiative (HKIPMI) Department of Information Engineering The Chinese University of Hong Kong Phone : 2603 5240 Fax : 2603 5032 _______________________________________________ LARTC mailing list / LARTC@mailman.ds9a.nl

Hola a todos   Estoy haciendo graficos con R pero no puedo guardarlos para utilizarlos en una presentacion   png("C:/Users/padiazor/Pictures/Graficos/G1.jpg",height=100,width=80)   ejecuto esta linea y no me da error pero cuando voy a ver el grafico me sale el siguiente mensaje   Visualizador de fotos de Windows no puede abrir esta imagen porque se está editando en otro programa y no me

Hello, I have a problem when doing gam (from gam library; I am using R 2.4.0, windows xp platform) When doing: example(gam) There is this error message (which also happens when using my data) .... Warning: a final empty element has been omitted the part of the args list of 'list' being evaluated was: (coefficients = fit$beta, residuals = fit$y - fit$eta, fitted.values = fit$eta,

I either play a male character named Mancow or a female character named Joana. I have been first to 60 now on 6 different servers, one of my goals with World of Warcraft is to get to 60 on new servers with the least amount of /played time possible, this means each time I went to 60 in WoW I have been revising my routes in order to achieve a better /played time. So far my best time is 4 days 20

Did anyone ever answer this one? THIS is what I am trying to do: >[LARTC] cbq+sfq and DSCP marking >Maria Joana Urbano stmaria@dei.uc.pt >Thu, 13 Feb 2003 19:29:42 +0000 > > * Previous message: [LARTC] Monitoring.... > * Next message: [LARTC] two routes 1 network card > * Messages sorted by: [ date ] [ thread ] [ subject ] [ author ] >

Hi I have a list with several data.frames, all with the same number of colunms but different number of rows, and I'd like to transform this list into a single dataframe. I need to mimic an rbind of all dataframes ... Transform doesn't seem to work :-( Thanks EJ -- Ernesto Jardim <ernesto at ipimar.pt> Bi?logo Marinho/Marine Biologist IPIMAR - Instituto Nacional de Investiga??o

Hi, I've just put together a new R syntax highlighting file for Nedit 5.3. I've borrow the "base" functions of Jedit (thanks to Tobias Elze and Zed A. Shaw) so now NEdit highlights a little more than before :) You can download the file here: http://ernesto.freezope.org/cmf/starthere/r/R-5.3.pats Just import it into NEdit with > nedit -import R-5.3.pats and save your

Hi, I dont know if this a coding rule or a program bug. When I write this function below it work: a <- c(1,2) for(i in a){ print(i) } [1] 1 [1] 2 But if I write this function with line space it dont work. a <- c(1,2) for(i in a){ print(i) } Error: unexpected '}' in "}" I remember that in early R version this limitation dont exist. This is a bus, a rule or a

H i, all! First of all, I'd like to apologize for my poor English. It's for years I don't use it. This is a R-version of a function I wrote a long ago for my HP48 calculator. It works with the binary expression of the power and just need to duplicate the mem used by X. Hope this helps. mtx.exp<-function(X,n) #Function to calculate the n-th power of a matrix X; { phi <-

Hola a todos. Un problema dos pasos. Quiero desde RStudio trabajar con dos versiones de R (pongamos R2.13 y R2.15) desde Linux, Ubuntu 10.04 (lucid). Ya tengo instalada la R.2.15.1. Por defecto trabajo con ella. Pasos que creo he de dar: 1º. Instalar dos versiones de R en la misma maquina. ¿Como se hace?. Me estoy metiendo con el PATH y tal... hay algún protocolo clarito por ahí? 2º.

Hola eRReros, Necesito extraer datos de un dataframe según uno de los factores. La cosa sería algo así: df.nuevo <- iris[iris$Species=="setosa"|iris$Species=="virginica",] Que me crea un df nuevo solo con las filas en que Species es setosa o virginica. El problema es que mi factor de interés tiene 22 niveles y a veces he de seleccionar 13, 10, 8 niveles o números así.

Hello all, I am new to the list so bear with me. I am testing dovecot out on a test server running RHEL ES 3, I have installed 0.99.14-1.1.el3 and 1.0-0_20.rc7.el3. This server is using the mbox mailbox format, running sendmail, procmail, and using PAM to do authentication to an LDAP server. I get varying results between the two version. 0.99.14-1.1.el3 : Upon installing this I leave

Hola eRReros. Os lo explico con un ejemplo: # Cargamos los paquetes y el ejemplo install.packages("SPEI") library("SPEI") data(wichita) # los primeros 12 datos head(wichita,12) # mi subset de los primeros 12 datos meu<-wichita[c(1:12),] meu # como veis los valores de TMED son iguales en ambos dataframes. # ahora viene el problema # calculamos

Dear R colleagues, This seems pretty straight forward but I have been banging my head on this for some time and can't seem to find a solution suppose I have something like a1<-1; a2<-2; a3<-3; a4<-4; b1<-3; b2<-4 I would like to quickly assign to objects with a certain pattern, e.g., those in ls(pattern="a") a specific value, e.g., "99", without

I am using the loglin function of the base package to fit log-linear models. I am interested in obtaining the parameter values and their standard errors. Parameters are easily obtained, but I haven't found the way of obtaining their standad errors. Is this possible with the loglin function? If not, is there any other function to get them? Many thanks, -- Vicente Piorno Departamento de Ecolox?a

Included 3 patches that updates documentation. This completes a 5 patches set. If you prefer me to resend all of then as one patch, attached, discussing or whatever, your're welcome. Best regards, vicente >From 7cec3ad78c8454408c8b6a1950d441e02d56d138 Mon Sep 17 00:00:00 2001 From: Vicente Jimenez Aguilar <googuy at gmail.com> Date: Fri, 23 Jan 2009 00:57:48 +0100 Subject: [PATCH]

Hola a tod en s. Realizando el calculo de encontrar la raíz quinta de -0.5, la cual dígito de la siguiente manera (-0.5)^(1/5) El resultado que me arroja R es NaN. Averiguando un poco entre las ayuda de las funciones aritméticas encuentro el siguiente comentario Users are sometimes surprised by the value returned, for example why (-8)^(1/3) is NaN. For double inputs, R makes use of IEC 60559