similar to: add string to a list

Hi R users, is there any possibilty that a while loop is working like that: z <- c(0,1,2,3,4,5,6,7,8,9) r <- 7 while(w == T) { for ( i in 1:10 ){ w <- r == z[i] print(w) } } The loop should stop if w == TRUE best regards -- View this message in context:

hello R users, I didn't find a solution for a special problem. I have two dataframes. dataframe1: X value row col ID 1 8.973498062 5512625 3460000 1 2 11.656658570 5501625 3464000 2 3 11.121777570 5495625 3473000 3 4 9.310465964 5508625 3477000 4 5 8.883483845 5515625 3496000 5 dataframe2: X value

Hello R-users, I have a little problem. I compare each row of a matrix with each row of another matrix. testmat1 <- matrix(c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16), nrow=4) testmat2 <- matrix(c(1,2,3,5,5,6,7,8,9,10,11,12,13,14,15,16), nrow=4) Both matrix differs in the last row. Now I create a loop: for (i in (1:4)){ for (j in (1:4)){ b <- (c(setequal(testmat1[j,],testmat2[i,])))

Hi R users, I want to colored points by their value for example: x <- c(1,2,3,4) y <- c(1,2,3,4) z <- c(2,3,4,9) y and x are coordinates z is the value of the coordinates points(x,y,col= rainbow(z)) something like that But haven't found any solution at the moment. Thanks. Chris -- View this message in context:

Hello R users, I want to readout the row and column postion from a certain matrix value into a csv file. I have only found this syntax "which(a == b, arr.ind = T)" so I get a = matrix [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 1 1 2 2 2 1 1 2 [2,] 1 2 3 3 3 4 4 3 [3,] 3 3 3 5 5 6 5 4 [4,] 4 4 4 3

Hello R users, I have a little problem with a for loop. Below there is an simple example of my problem. I want to delet the commas in the character string. Fore this reason I create a for loop to unpick the string and rebuild him without the commas. The problem is, that "paste" does not work in the loop as I expected. text <- "aaa,bbb,ccc,ddd" characterseq <-

Hi R users, I have mentioned that R is getting slower if a process with a loop runs for a while. Is that normal? Let's say, I have a code which produce an output file after one loop run. Now after 10, 15 or 20 loop runs the time between the created files is stongly increasing. Is there maybe any data which fill some memory? Chris -- View this message in context:

Dear R users, I guess, I have a quit simple problem, but I'm not getting the solution. I create a matrix like this: test <- matrix(seq(1,3,1),ncol=5,nrow=3) then I want to create one vector, consisting of every row of the matrix. My first idea was to do this with a for loop. op <- vector() for (o in 1:3){ op[o] <- as.vector(test.id[o,]) } The results should be like this: [1]

Hello R users, is there a possibility to get the relativ maximum of a matrix? To get the absolut maximum I use max(matrix) For example: The absolut maximum of this matrix is 6[3,6], but the relativ maximum is 6[3,6] and 4[7,6], because both values are the highest value in comparison to their eight neighbours values. [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 1 1 2 2 2

Hello, I have a problem to flip a 200x200 matrix, which is imported by a .asc file. I want to flip the matrix like in a created example below: > b <- matrix(1:9,3,3,byrow=T) > b [,1] [,2] [,3] [1,] 1 2 3 [2,] 4 5 6 [3,] 7 8 9 > b1 <- apply(t(b),1,rev) > b1 [,1] [,2] [,3] [1,] 7 8 9 [2,] 4 5 6 [3,] 1 2 3 but my

Prof. Tierney, Thanks very much for the info. Why does the loop work if I move the assignment out of the condition? E.g., the following works: i <- 0 while(i < 5) { i <- i + 1 if(i < 3) next print(i) } Regards, Andy > -----Original Message----- > From: Luke Tierney [mailto:luke at nokomis.stat.umn.edu] > Sent: Tuesday, October 02, 2001 3:36 PM > To: Liaw, Andy

Dear R-help, I think I have kinda isolated the problem I had to the following: i <- 0 while( {i <- i + 1} < 5) { if(i < 3) next print(i) } This seems to go into an infinite loop. After I break the execution, i has the value 1. At the R prompt, if I start from i <- 0 and keep typing {i <- i + 1} < 5, it eventually evaluate to TRUE. So why does the while loop not work?

> On Jul 19, 2017, at 5:38 AM, Michael Friendly <friendly at yorku.ca> wrote: > > It was suggested to quote your string with *backticks* (` ... `) rather than single quotes. > > String <- `<html> > <head> > ... > ` That failed for me. The parser considered it a language object, an R name. Here's what I needed to do: > string <-

R version: 2.13.1 OS X Colleagues, I am working with a CSV file; for testing purposes, I created an XLS version of the file. When I read these files using read.xls (gdata) or read.csv, I encounter an error: Error in type.convert(data[[i]], as.is = as.is[i], dec = dec, na.strings = character(0L)) : invalid multibyte string at '<b0>C' The error occurs whether or not I invoke

Hi all, I'm getting the following error from substring: > substr("<I>Jens Oehlschl\xe4gel-Akiyoshi", 1, 100) Error in substr("<I>Jens Oehlschl\xe4gel-Akiyoshi", 1, 100) : invalid multibyte string at '<e4>gel-A<6b>iyoshi' Is that normal / intended? I've tried setting the Encoding/locale to Latin-1/UTF-8 but that does not help. nchar

Thanks for the quick response Ivan. readLines with encoding='latin1' works for me (on Ubuntu). However I was more concerned with the inconsistency in results between substr and regexpr. I was expecting that if one of them errors because of an unknown encoding then the other should as well. Even better, if regexpr works, why shouldn't substr work as well? Incidentally the analogous

Because my problem involves the RdbiPgSQL package, I sent a message similar to this one to the Bioconductor list. But while awaiting moderator approval of my message (because I am not a member of that list), it occurred to me to send it to R-help as the problem may be more general than just RdbiPgSQL. Here's my situation: I have been using RdbiPgSQL successfully for a year or two. I

I think the whole premise of this question is flawed. If you want to work with this string as data, then read it in from a separate file using readLines. If it is fixed data that you want to be part of your program, then invest the effort to escape the odd characters and be done with it. But using backticks is a bad idea because they ate not just another kind of quote. -- Sent from my phone.

I noticed an issue where readChar does not return the correct value after a call to readline. It appears that readChar is not aware of the buffering, so it reads from the end of the buffer, rather than the current position in the file. This is a significant change of behavior from R-3.4.4. Below is a test case that I used to home in on the problem. --- p<-"test2.txt"

... Both readLines() and scan() produce a number_of_lines x 1 vector; trying paste(s, collapse = NULL) leaves it unaffected. How can I concatenate vector elements (lines) into a single string? Thank you. -- View this message in context: http://r.789695.n4.nabble.com/How-to-read-contents-of-a-text-file-into-a-single-string-tp2069303p2069303.html Sent from the R help mailing list archive at