Displaying 20 results from an estimated 10000 matches similar to: "list creation interpolation"
2007 Jan 19
3
if else statement
Hello,
I'm doing some scripting and I've noticed that R doesn't seem to
have an
if (cond){
do
}ifelse (cond) {
do
} else {
do
}
type block.
Is this correct or am I missing something.
THX
Paul
--
Research Technician
Mass Spectrometry
o The
/
o Scripps
\
o Research
/
o Institute
2009 Feb 10
3
summary of a list
Hello,
I'm using the following for loop to find regression curves using a list of functions (formList), a list of starting
values (startList), uppervalues (upperList) and lower values (lowerList).
A sample of the list of function I use in the loop is the following:
FormList <- list(PTG.P ~ fz1(Portata, a, b), PTG.P ~ fz2(Portata, a, b), PTG.P ~ fz3(Portata,a, b, d, e),
PTG.P ~
2006 Nov 29
3
better define: matrix comparison and cbind issue
Hello,
Sorry to all for the lack of communication, and thanks to those with the
suggestions.
So I have two matrixes which are different sizes, same column number but
different row number.
What I would like to do is to compare A to B. In the 6 and 9th column there
are ref numbers (molecular masses to be exact). I would like to check A and
B by these columns. If I find that the number in A[9,x]
2007 Jun 18
2
data type for block data?
Dear All,
I have a matrix with data that is not organised. I would like to go
through this and extract it. Each feature has 2 vectors which express
the data. I also have an index of the places where the data should be cut.
eg.
>class(cc)
"matrix"
>cc
[,1] [,2]
[1,] 1 26
[2,] 2 27
[3,] 3 28
[4,] 4 29
[5,] 5 30
[6,] 6 31
[7,] 7 32
2007 Aug 28
4
Nodes & edges with similarity matrix
Hello,
I apologise if someone has already answered this but I searched and
googled but didn't find anything.
I have a matrix which gives me the similarity of each item to each
other. I would like to turn this matrix into something like what they
have in the graph package with the nodes and edges.
http://cran.r-project.org/doc/packages/graph.pdf . However I cannot find
a method to
2009 Feb 10
2
plotting the result of a nonlinear regression
Hello,
to plot the result of a singular non linear regression (using nls) I usually use the function plotfit, for example:
r.PTG.V<-nls(PTG.P~ fz1(Portata, a,b), data=dati, start=list(a=10, b=10), nls.control(maxiter=200), algorithm='port',
trace=TRUE, na.action=na.omit, lower=list(a=0, b=10), upper=list(a=100, b=100))
plotfit(r.PTG.V)
I tried to use the function plotfit on the
2006 Sep 29
1
linear gradient in nls
Hello,
I hope this doesn't turn into a statistics question but here I
go. I am using the nls function with a Gaussian distribution, see coding
below. When I run the nls I get an error back saying that I have a linear
gradient. I then, of course am unable to do anything else. The data that I
am using are intensity values from some mass spectrometry data. Is there
something I can
2007 Apr 24
2
negative number to positive number
Hello all,
I know this is a pretty easy question but I can't find it in S poetry or
R help.
How can I make a negative number positive. Such as
-5 to be +5
I tried +(-5), but that didn't work.
So no, I don't mean taking a -5^2 just to get a positive number.
This is in a function so it's not just -5 it's x. :)
Thanks,
Paul
--
Research Technician
Mass Spectrometry
o The
2009 Sep 18
1
lapply - value changes as parameters to function?
Hi,
I'm trying to get better at things like lapply but it still stumps
me. I have a function I've written, tested and debugged using
individual calls to the function, ala:
ResultList5 = DoAvgCalcs(IndexData, Lookback=5,
SampleSize=TestSamples , Iterations=TestIterations )
ResultList8 = DoAvgCalcs(IndexData, Lookback=8,
SampleSize=TestSamples , Iterations=TestIterations )
ResultList13
2006 Jun 13
3
if syntax error :(
Umm sorry to bother everyone again but I'm having trouble with my if
statement. I come from a perl background so that's probably my problem! :)
So here is my code:
if (any(lgAB>4) | any(lgAB<-4)){
freq_AB<-hist(lgAB, type="o", plot=F)
else
freq_AB<-hist(lgAB, breaks=br,type ="o", plot=F)
}
And I get
> source("E:/R/GMDA-1.1.R")
Error in
2008 May 08
2
anova p value extraction
hello all,
Quick question, how do I get the p value out of the anova?
Thanks,
Paul
> pb<-aov(as.numeric(diff[5,16:33]) ~ grF)
> summary(pb)
Df Sum Sq Mean Sq F value Pr(>F)
grF 3 2.7860e+10 9.2867e+09 4.2236 0.02534 *
Residuals 14 3.0783e+10 2.1988e+09
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 '
2012 Apr 25
2
Accessing a list
Hi,
I have the following problem- I want to access a list whose elements are
imp1, imp2, imp3 etc I tried theusing the paste comand in a for loop see
the last for loop below. But I keep calling it df but df = imp1 (for the
first run). Any ideas on how I can access the elements of the list?
Isaac
require(Amelia)
library(Amelia)
data.use <- read.csv("multiplecarol.CSV", header=T)
2006 Aug 28
7
Time plots
Hello all and thank you,
I will try to make this as clear as I can. I have a matrix, at the
top of the matrix are 4 time points, the first col describes the sample,
then under each time point I have the intensity values of that sample.
So :
Samples 0 10 30 120 <- time
A 200 300 400 1000 <- data
B 100 400 200 100
C 500 400 200 1000
^
| samples
I would like to plot these however, all I
2007 May 25
1
3D plots with data.frame
Dear all,
Thank you for any help. I have a data.frame and would like to plot
it in 3D. I have tried wireframe() and cloud(), I got
scatterplot3d(xs)
Error: could not find function "scatterplot3d"
> wireframe(xs)
Error in wireframe(xs) : no applicable method for "wireframe"
> persp(x=x, y=y, z=xs)
Error in persp.default(x = x, y = y, z = xs) :
(list)
2007 Aug 07
1
S4 methods: unable to find an inherited method
Hello all,
I consider myself pretty new to the whole OO based programming so
I'm sorry if I'm doing something stupid.
> xml<-read.metlin(url)
Error in function (classes, fdef, mtable) :
unable to find an inherited method for function "read.metlin",
for signature "url"
>read.metlin
standardGeneric for "read.metlin" defined from package
2007 Oct 16
2
histogram labels
Dear all,
Just a quick one, hopefully. I have a histogram made from the method
'hist()'. How do I get labels on the bars? Such that the bars will have
the x axis on the bar, not the frequency of the point but the number of
the point itself. To make a quick summary, I want the the numbers from
'losses' (below) to be on the bar's.
Thanks,
Paul
2006 May 23
2
nls: formula error?
So thanks for the help,
I have a matrix (AB) which in the first column has my bin numbers so -4 - +4
in 0.1 bin units. Then I have in the second column the frequency from some
data. I have plotted them and they look roughly Gaussian. So I want to fit
them/ find/optimize "mu", "sigma", and "A".
So I call the nls function :
nls_AB <- nls(x ~ (A/sig*sqrt(2*pi))*
2012 Feb 08
2
Split dataframe into new dataframes
Hi,
I want to split a dataframe based on a grouping variable (in one column). The resulting new
dataframes should be stored in a new variable. I tried to split the dataframe using split() and
to store it using a FOR loop, but thats not working so far:
df <- data.frame(A=c("A1","A1","A2","A2"),B=seq(1:4))
Fsplit <- function(x,y){
ls <-
2006 Mar 02
3
Custom SQL Question
Hello,
can search with following SQL Statement:
def execute_search
@result = Search.find_by_sql ["SELECT * FROM customers WHERE
firstname LIKE ? LIMIT 10",params[:firstname]]
render :template => "search/resultlist", :layout => false
end
My question is, how do I use 2 or more Parameters - and with the "%"? (I
Like to use SQL-Statements because
2009 Feb 03
3
non linear regression with nls
Hello,
I'm a beginner with R and it's the first time I'm using the R-help list... I hope I'm in the right place, if not:
Sorry!!
I need to do non linear regressions on a data set which columns are:
"river.name" "Portata" "PTG.P" "PO4.P" "NT.N" "NH4.N" "NO3.N" "BOD5" "SiO2"