similar to: Date conversion

Hi List, Does anybody know what function I need to use for a simple regression? Here is the data: I want to find the value for x1=3.5 data<-data.frame(x=c(1:30),Value=c(31:60)) x1<-3.5 Regards, Alireza [[alternative HTML version deleted]]

I am trying to plot some data, but have got some difficulties with labels on the tick marks on the x-axes. There are 20 data points. All I want to do is to plot the Loss versus Lines. When I use xyplot, the first tick mark starts from 2 rather than 1, and also there is a NA as the final tick mark. Here is the R code you code give it a try: Would any body be able to fix this, please?

Hi List, Would you please send me a good link to talk me through on how to write a R package? thanks Alireza [[alternative HTML version deleted]]

Hi List, Is anybody aware of any R console available for Android mobile? I know that there is one for Iphone. thanks, Alireza [[alternative HTML version deleted]]

Hi list, I have a real problem with plotting US state map. When I try to plot the northern state, there will be some blank space in the top of graph (see case 1 example), and when I plot southern states, there will be a blank space in the bottom of plot (see case 2). I spent almost 2 days to figure out a solution, but could not. Would you help me if you know what the problem is? Regards, Alireza

Hello, I'm trying to plot a fitted lm() line on a plot when the one explanatory variable is log transformed and log="x". I get different lines using abline and predict.lm(). #Example x <- 1:100 y <- rnorm(100) plot(y ~ x, log="x") abline(lm(y ~ log(x))) lines(x, predict(lm(y ~ log(x))), lwd=2) I'm sure I'm missing something but could someone tell me which

Hello, I use t.test for normal distributed and wilcox.test for non-normal distributed samples. It is easy to write a function for t.test that calculates the effect size, because all parts of the formula are available from the t.test result: r = sqrt(t*t / (t*t + df)) However, for Wilcoxon tests, the formula for effect sizes is: r = Z / sqrt(N) I wonder how I can calculate the Z-score in R for

Hi, I just started with R and I found that there are many options to rearrange the data to do mixed models. I want to use the reshape function. I have 2 between subject variables and one within. I was able to change the data structure but still - the result of the aov functions are calculating everything as a within subject. the table looks like this: SerialNo breed treatment distance_1

Full_Name: Erich Neuwirth Version: 2.3.1 OS: Windows XP, Linux Submission from: (NULL) (131.130.135.167) Converting Sys.Date() to a POSIX compliant time type in different ways produces inconsistent results: > Sys.date() [1] "2006-09-01" > as.POSIXct(Sys.Date()) [1] "2006-09-01 02:00:00 CEST" > as.POSIXlt(Sys.Date()) [1] "2006-09-01" >

Full_Name: Stefan Raberger Version: 2.8.1 OS: Windows XP Submission from: (NULL) (213.185.163.242) Hi there, I recently noticed some strange behaviour of the command "type.convert", depending on the startup mode used. But there also seems to be different behaviour on different PCs (all running the same OS and the same version of R). On PC1: When I start R in SDI mode (RGui --no-save

Hi list, Does anyone know the code behind rlnorm(n, meanlog = 0, sdlog = 1)? I am going to write it in c#. thanks Alireza [[alternative HTML version deleted]]

Hi list, Does any one know how I can make the red colour transparant? ######################### par() #Set up blank plot to remove plot border type lty="n" xvalue1<- c(1,2,2,1) xvalue2<- c(1,3,3,1) yvalue1<- c(0,0,22,22) yvalue2<- c(0,0,44,44)

Hi List, Does any one know what package I need to use in order to fetch/get a large sized dataframe from SQL? I have already used sqldf package which is good for fetching large sized csv files. Thanks Alireza [[alternative HTML version deleted]]

Hi list, I have code which reads data from sql server using RODBC in R version 2.12.1. The code used to be ok, till today when I get the following error. The data does not have any problem, but if I run the code in differnt pc, it runs till different number of trial then it fails, for example on one pc, it runs up to 30 times, other pc up to 66 times, then it fails. Any help please? [1] "so

Dear all, Is there a less cumbersome way to rename a column by name (as opposed to index) than -- names( X)[ names[ X] == "bob"]<-"sue" ? A semi-related question: how does one get the index of a column by name, something along the lines of col.index( X, "sue") ? Chip Barnaby --------------------------------------------------------- Chip Barnaby

Hi, Quick question: Say I have a date variable in a data frame or matrix, and I'd like to preserve the date format when using write.table. However, when I export the data, I get the generic number underlying the date, not the date per se, and a number such as 11323, 11324, etc are not meaningful in Excel. Is there any way I can preserve the format of a date on writing into a text-file? TIA

Hi I had observed the following problem in R (also C, Matlab, and Python). sprintf('%1.2g\n', 3.15) give 3.1 instead of 3.2 whereas an input of 3.75 gives 3.8. Java's System.out.printf is ok though. > round(3.75,1) [1] 3.8 > round(3.15,1) [1] 3.1 Similar outcome with sprintf in R. However, the right answer should be 3.2 Regards Teckpor [[alternative HTML version

Hi, The following function works, but is there a neater way to write it? f = function(x,...) { # return a character vector of the arguments passed in after 'x' gsub(" ","",unlist(strsplit(deparse(substitute(list(...))),"[(,)]")))[-1] } > f(x,a,b,c*d) [1] "a" "b" "c*d" > Thanks. [[alternative HTML

Full_Name: Richard Reed Version: 2.6.2 OS: MS Windows XP Pro Submission from: (NULL) (76.121.170.35) Pressing Alt-M+s doesn't search path. It just generates another ">". It does this in "vanilla" too. However, Alt-M+click "list search path" does work. Note that when I press Alt-M (and the "Misc" menu drops down) the second "s" in

Hi list, I want to plot state Texas using map function. I wrote the following code to plot the grid boundary for Texas: ################################ library(maps) require("mapproj") longlatLimit<-c(-106.65, -93.53 , 25.93 , 36.49) par(plt=c(0,1,0,1),cex=1,cex.main=1) #Set plotting parameters map(projection="azequalarea",