similar to: give all combinations

Hi Ruser I'm trying to replicate some SAS code. I have to add a spline to my longitudinal spaghetti plot. I have the plot, but I can't add the spline, a overall trend line. In the SAS code they use the command 'I=SM50S' and I would prefer something similar. I?m using R 2.10.1 on windows XP? I have made this working example. tolerance.pp <-

I am sorry, I'd like to split my column ("names") such that all the beginning of a string ("X..") is gone and only the rest of the text is left. x<-data.frame(names=c("X..aba","X..abb","X..abc","X..abd")) x$names<-as.character(x$names) (x) str(x) Can't figure out how to apply strsplit in this situation - without using a

Suppose, 'fr' is data.frame with columns 'Y', 'A' and 'B'. 'A' has levels 'Aa' 'Ab' and 'Ac', and 'B' has levels 'Ba', 'Bb', 'Bc' and 'Bd'. 'Y' columns are numbers. I tried the following three sets of commands. I understand that A*B is equivalent to A+B+A:B. However, A:B in A+B+A:B is

Hi, I've got a question regarding the restructering of a data set. What I have are municipality zip-codes and the names of 5'000 built-up areas within municipalities. The following example shows, what I would like to do: Input (Zip-Codes and Names): # CODE NAME #1 3 aaa #2 3 aab #3 3 aac #4 4 bba #5 4 bbb #6 4

Dear all, I have a piece of code along the lines of f <- function(x) { clipname <- "LK" # but is in real determined based on info in data.frame x # other manipulations return( list(clipname=list(....))) } My intention is to do out <- f(dat) and then (in this example) having/getting out$LK which is a list in itself. Of course, it doesn't work like this, but

Hi I want to enumerate all vectors of length "J", whose elements are integers in the range 1 to S, without regard to ordering. With J=S=3, the combinations are as follows: [,1] [,2] [,3] [1,] 1 1 1 [2,] 1 1 2 [3,] 1 1 3 [4,] 1 2 2 [5,] 1 2 3 [6,] 1 3 3 [7,] 2 2 2 [8,] 2 2 3 [9,] 2

https://bugzilla.mindrot.org/show_bug.cgi?id=1213 --- Comment #43 from Daniel Richard G. <skunk at iSKUNK.ORG> --- And a year later, this issue still afflicts OpenSSH 6.1p1 (as packaged by Ubuntu). Aab's patch still applies, if fuzzily, and still hardens up ssh-keyscan so that it can deal with my company's network. -- You are receiving this mail because: You are watching the

https://bugzilla.mindrot.org/show_bug.cgi?id=1213 aab at purdue.edu changed: What |Removed |Added ---------------------------------------------------------------------------- Attachment #2021|0 |1 is obsolete| | --- Comment #34 from aab at purdue.edu 2011-06-14 14:43:42 EST --- Created attachment

Hello! I'm trying the hard way to use a formula, in a function, to specify the names of several important columns in a data.frame. Maybe I'm just battling to figure out the right search terms :-( This is on XP, R 1.8.1. So, for instance, wery[1:5,] V1 V2 V3 V4 V5 congr V7 V8 V9 ok RT 1 1 1 960 520 1483 c 1 r r 1 760 2 1 2 1060 450 3753 c 1 r r 1 555

https://bugzilla.mindrot.org/show_bug.cgi?id=1213 aab at purdue.edu changed: What |Removed |Added ---------------------------------------------------------------------------- Attachment #2008|0 |1 is obsolete| | --- Comment #31 from aab at purdue.edu 2011-03-18 17:36:09 EST --- Created attachment

https://bugzilla.mindrot.org/show_bug.cgi?id=1213 --- Comment #3 from aab at purdue.edu 2010-11-23 12:00:50 EST --- Created attachment 1961 --> https://bugzilla.mindrot.org/attachment.cgi?id=1961 One attempt at getting the rsa key from a remote server that was having a number of problems. -- Configure bugmail: https://bugzilla.mindrot.org/userprefs.cgi?tab=email ------- You are receiving

Hi! Apologies for sending the mail without any code. Apparently somewhere along the way the .R attachments got filtered out. I have included the code below as clean as possible. My original mail is below the code. Thank you again for your time. regards, Paul vincentize <- function(data, bins) { if ( length(data) < 2 ) { stop("The data is really short. Is that ok?"); }

https://bugzilla.mindrot.org/show_bug.cgi?id=1213 Andreas Kotes <count-mindrot at flatline.de> changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |count-mindrot at flatline.de Severity|normal |major --- Comment #6 from

A user asked me about this and I can't figure it out. tmt% R R Under development (unstable) (2018-04-09 r74565) -- "Unsuffered Consequences" Copyright (C) 2018 The R Foundation for Statistical Computing Platform: x86_64-pc-linux-gnu (64-bit) > library(survival) > data(cgd0) Warning message: In data(cgd0) : data set ?cgd0? not found ---- The data set is present and can be

Dear friends, How do I stop partial matching of list names? e.g., x <- list(AAAA="aaaaa", BBBBB="bbbbb") is.null(x$A) #returns FALSE even though there is no element A. if(is.null(x$A)) {result <- x$BBBB} else {result <- x$A} result #is aaaa even though there is no x$A element x <- list(CCCC="aaaaa", BBBBB="bbbbb") if(is.null(x$A))

Hi all, I am just curious how to sort the groups in a categorical box plot chart bwplot here is the example: d<-data.frame(sample(rep(month.abb,20), 100), runif(100,1,10)); colnames(d) <- c("Month", "Value"); bwplot(d$Month ~ d$Value); as you can see Months are not sorted alphabetically. Does anybody know ho to sort those on the chart level? Thank you Jan

Hello! I'm not grasping why cbind (in the code below) warns that Warning message: number of rows of result is not a multiple of vector length (arg 2) in: cbind(z, p) when I do sections <- function(length, parts) { p <- 1:parts q <- length %/% parts z <- array(p, dim=c(parts,q)) r <- length %% parts if ( r > 0 ) { p[r+1:length(p)] <- NA z <-

Hello! If I read ?subset, the workings of the argument drop (to me) seem to imply equivalence of A and B (R 1.9.0): #A dd <- data.frame(rt=rnorm(10), c=factor(gl(2,5))) dd <- subset(dd, c==1) dd$c <- dd$c[, drop=TRUE] table(dd$c) 1 5 #B dd <- data.frame(rt=rnorm(10), c=factor(gl(2,5))) dd <- subset(dd, c==1, drop=TRUE) table(dd$c) 1 2 5 0 So to lose the second level of

Hi, I have two issues with my puppet. *1*- When I change the config the service on the agent side implement the configuration change but the restart/reload gets scheduled and after 15 or 20 minutes it is executed, however the agent time to get conffig from server is 180 seconds. Followings are the logs *(/Stage[main]/Nginx/Service[nginx]) Triggered ''refresh'' from 2 events*

I think I'm missing something tonight in the usage of 'legend': plot(0, type="n") legend(locator(1), month.abb[1:5], pch=15, col=1:5) gives me something similar to what I want. But legend(locator(1), month.abb[1:5], fill=T, col=1:5) gives me 5 black boxes. What am I doing wrong? Thank you, > version _ platform i686-pc-linux-gnu arch i686 os