similar to: Plotting Multiple lines on one plot

I have a long list of numbers [3.4,5.4,3.67,....], and I basically want to find the index of the number closest to this number that I have, let's say 5.43. How would I do this without writing a for loop (I have to do this many times for several lists)? Is there a "lookup" function in R? Thanks! -- View this message in context:

raw <- read.csv(file=filename, head=TRUE,sep=",") I've read in a csv file, and I'm looking to access a column whose name is held in a string. For example, I want to access raw$one or raw$two, but this will depending on the string. Let's say that the string is decision<-"one". How would I access raw$one? The following doesn't work:

I'm trying to control the number of labels in the x-axis of my plot. My code is the following: graph1<-barplot(total_skew) axis(1,at = graph1,labels=raw_date[1:length(total_skew)], las=2) however, the length of my "total_skew" parameter is a few thousand elements, and all the labels on the x-axis are overlapping and cluttered. How do I specify the frequency or number of labels

Hello, this is probably a recurrent question, but I couldn't find any answers that didn't involve the expression "data frame"... so perhaps I'm looking for something new here. I wanted to find a code equivalent to > x=sqrt(1:10) > y=log(1:10) > plot(1:10, x, type="lines", col="darkgreen") > lines(1:10, y, col="red") to use with

Hello, I have a question about how to plot a series of data. The folloqing is my data matrix of n > n 25p 5p 2.5p 0.5p 16B-E06.g 45379 4383 5123 45 16B-E06.g 45138 4028 6249 52 16B-E06.g 48457 4267 5470 54 16B-E06.g 47740 4676 6769 48 37B-B02.g 42860 6152 19276 72 35B-A02.g 48325 12863 38274 143 35B-A02.g 48410 12806 39013 175 35B-A02.g 48417 9057 40923

Hi, I cannot figure out how to draw a certain plot: could someone help me out? I have this data.frame from a survey my.data that looks like something like this: col1 col2 col3 col4 1 5 5 4 5 2 3 5 3 1 3 2 3 4 5 4 3 1 1 2 5 5 5 4 5 6 4 2 5 5 .... Each row represents a single questionnaire

Dear R-Users, I would like to know whether it is possible to draw several stacked barplots (i.e. side by side on the same sheet)... my data look like : Cond1 Cond1' Cond2 Cond2' Compartment 1 11,81 2,05 12,49 0,70 Compartment 2 10,51 1,98 13,56 0,85 Compartment 3 1,95 0,63 2,81 0,22 Compartment 4 2,08 0,17

Hi Folks, I have data that looks like this: freq gender xBar 1000 m 2.32 1000 f 3.22 2000 m 4.32 2000 f 4.53 3000 m 3.21 3000 f 3.44 4000 m 4.11 4000 f 3.99 I want to plot two lines (with symbols) for the two groups "m" and "f". I have tried the following: plot(xBar[gender=="m"]~freq[gender=="f"]) followed by

Hello, Below is the code for a basic bar graph. I was seeking advice regarding the following: (a) For each time period there are values from 16 people. How I can change the colour value so that each person has a different colour, which recurs across each of the three graphs/tie epriods? (b) I have seen much more sophisticated examples using lattice (e.g each person has a separate

Hello everyone I have some data of the following type. 100 200 300 400 500 1.1 1.2 1.3 1.4 1.5 600 700 800 900 1000 1.5 1.7 1.9 2.0 2.4 With plot() and points functions I can plot these 4 lines of data. But I dont know how to do it with qplot or ggplot functions. The scenario is something like this: the hundreds should appear on x-axis and the fractional values of y axis. Thanks alot. MEMON

Hi, i'm using this lines of code: dodge <-position_dodge(width=0.9) ggplot(dfm,aes(x = X,y = value)) + geom_bar(aes(fill = variable), position=dodge, stat="identity") + geom_errorbar(aes(ymin=value-er, ymax=value+er),width=0.25, position=dodge,stat="identity") to plot this data frame X variable value er 1 A X4 58.74 9.44 2 B X4

Thank you all for the useful suggestion. I did some of my homework. library(data.table) DFM <- read.table(header=TRUE, text='obs start end 1 2/1/2015 1/1/2017 2 4/11/2010 1/1/2011 3 1/4/2006 5/3/2007 4 10/1/2007 1/1/2008 5 6/1/2011 1/1/2012 6 10/5/2004 12/1/2004',stringsAsFactors = FALSE) DFM DFM$D =as.numeric(difftime(as.Date(DFM$end,format="%m/%d/%Y"),

Thank you Jeff and All, Within a given time period (say 700 days, from the start day), I am expecting measurements taken at each time interval;. In this case "0" means measurement taken, "1" not taken (stopped or opted out and " -1" don't consider that time period for that individual. This will be compared with the actual measurements taken (Observed-

# read.table is NOT part of the data.table package #library(data.table) DFM <- read.table( text= 'obs start end 1 2/1/2015 1/1/2017 2 4/11/2010 1/1/2011 3 1/4/2006 5/3/2007 4 10/1/2007 1/1/2008 5 6/1/2011 1/1/2012 6 10/5/2004 12/1/2004 ',header = TRUE, stringsAsFactors = FALSE) # cleaner way to compute D DFM$start <- as.Date( DFM$start, format="%m/%d/%Y" ) DFM$end

Since the number of choices is small (6), how about this? Starting with Jeff's initial DFM: DFM <- structure(list(obs = 1:6, start = structure(c(16467, 14710, 13152, 13787, 15126, 12696), class = "Date"), end = structure(c(17167, 14975, 13636, 13879, 15340, 12753), class = "Date"), D = c(700, 265, 484, 92, 214, 57), bin = structure(c(6L, 3L, 5L, 1L, 3L, 1L), .Label

I suspect there may be a bug in base::rbind.data.frame Below there is minimal example of the problem: m <- matrix (1:12, 3) dfm <- data.frame (c = 1 : 3, m = I (m)) str (dfm) m.names <- m rownames (m.names) <- letters [1:3] dfm.names <- data.frame (c = 1 : 3, m = I (m.names)) str (dfm.names) rbind (m, m.names) rbind (m.names, m) rbind (dfm, dfm.names) #not working rbind

In my main R program, I have source("retaanalysis/Functions/doAirport.R") .... stuff to read data and calculate ads sapply(ads, function(x) {doAirport(x, base)} ) And doAirport has # analyze the flights for a given airport doAirport = function(df, base) { # Get rid of unused runway factor levels (from other airports) df$lrw <- drop.levels(df$lrw) # In gdata package #

Hi R users, I still have the problem about plotting. I wanted to put the datasets on one figure, x-axis represents values B, y-axis represents values C, while different colors label column A. Each record uses a circle on the figure, while hollow circles represent DF=1 and solid circles represent DF=2. I put my code below, but the A labels do not correspond to the true record, so I don't know

Hi Jim, For true color, I meant that the points in the figure do not correspond to the values from the dataframe. Also, why to use rainbow(9) here? And the legend is straight in the middle, is it possible to reformat it to the very bottom? Thanks again. On Sun, Jul 16, 2017 at 2:50 AM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi lily, > As I have no idea of what the "true

Hi lily, As I have no idea of what the "true record" is, I can only guess. Maybe this will help: # get some fairly distinct colors rainbow_colors<-rainbow(9) # this should sort the numbers in dfm$A dfm$Acolor<-factor(dfm$A) plot(dfm$B,dfm$C,pch=ifelse(dfm$DF==1,1,19), col=rainbow_colors[as.numeric(dfm$Acolor)]) legend("bottom",legend=sort(unique(dfm$A)),