similar to: How hist() decides breaks?

Hi Group, I've a vector of 1000 numeric values for which I want to draw a histogram. I've read this vector into R with no variable name.I mean only the 1000 values, which makes V1 the name of the variable by default?? Then I tried > hist(V1, breaks = "Sturges", +      freq = NULL, probability = !freq, +      include.lowest = TRUE, right = TRUE, +      density = NULL, angle =

Hi all: As to hist,the help file says:" R's default with equi-spaced breaks (also the default) is to plot the counts in the cells defined by breaks." I wanna know how the break is calculated by R? In other words: break = (max - min)/(number of group) but how the "number of group" is calculated by R? Thanks!

Dear all, I am a newbie in R and could not find help on this problem. I am trying to plot an histogram with probabilities in the y axis. This is the code I am using: #TLC uniform n=30 mi=1; mx=6 nrep=1000 xbar=rep(0,nrep) for (i in 1:nrep) {xbar[i]=mean(runif(n,min=mi,max=mx))} hist(xbar,prob=TRUE,breaks="Sturges",xlim=c(1,6),main=paste("n =",n), xlab="Média",

Hello,<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p></o:p> I would like to create a histogram from a data collumn consisting of 4 classes (0; 0.05;0.5;25;75). Due to the difference in scale the classes 0;0.05 and 0.5 are displayed within one combined bin by default with the code:Hist(x, scale="percent",

Dear list, I'm trying to do a set of generic functions do make contingency tables from data.frames. It is just running "nice" (I'm learning R), but I think it can be better. I would like to filter the data.frame, i.e, eliminate all not numeric variables. And I don't know how to make it: please, help me. Below one of the my functions ('er' is a mention to EasieR,

Hi All, I would like to make an invitation to make a collective package with all functions related to TABLES. I know that there are many packages with these functions, the original idea is collect all this functions and to make a single package, because is arduous for the user know all this functions broadcast in many packages. So, I think that the original packages can continue with its

Full_Name: Reinhold Koch Version: 1.6.1 OS: redhat 8.0 Submission from: (NULL) (131.152.84.111) I came across rather weird behavior of the breaks in hist: hist(1:3) gives the expected result, besides an unnecessary gap between 2nd and 3rd column hist(1:4) always merges up the first two columns, also if I resort to hist.default(1:4,breaks=1:4). hist.default(1:4, include.lowest=F) gives an

Dear All, According to the Sturges rule, the number of classes of a histogram is the closest integer to 1 + logb(n,base=2) where n is the number of observations. The function hist(), by default, uses the Sturges rule. However, the code x <- 1:200 hist(x) produces a histogram with 10 classes and not 9 classes as determined by the Sturges rule. What am I missing? Thanks in advance, Paul

Hey everybody, I try to make a graph with two different plots. First I make a boxplot of my data. It is a collection off correlation values of different pictures. For example: 0.23445 pica 0.34456 pica 0.45663 pica 0.98822 picb 0.12223 picc 0.34443 picc etc. Ok, I make this boxplot and I get for every picture the boxes. After this I want to know, how many correlations per picture exist. So I

Think I'm missing something to understand what is going on with hist(...) http://n2.nabble.com/What-is-going-on-with-Histogram-Plots-td3022645.html For my example I count 7 unique years, however, on the histogram there only 6. It looks like the bin to the left of the tic mark on the x-axis represents the number of entries for that year, i.e. Frequency. I guess it looks like the bin for

Hello everybody, This is a bug involving functions in core R package: graphics::hist.default, grDevices::nclass.FD, and base::pretty.default. It is not yet on Bugzilla. I cannot submit it myself, as I do not have an account. Could somebody else add it for me, perhaps? That would be much appreciated. Kind regards, Sietse Sietse Brouwer Summary ------- Floating point errors can cause a data

Hi all, I'm trying to superimpose a rchisq density line over a histogram with something like: hist(alnlength) lines(density(rchisq(length(alnlength), 4)),col="red") But the rchisq line won't appear anywhere, Anyone knows what I am missing here? Thanks in advance, Albert.

Buenas. Sé que en R hay multitud de datasets y me haría falta alguno que trataran de variables relacionadas con salud, sobre todo para aprender más acerca de cómo realizar una regresión logística binomial o multinomial. Gracias..

Dear all I have a dataset that looks like: fr.wt site 1 4400 glen 2 235 glen 3 225 glen ' ' ' ' ' ' ' ' ' 82 550 glen 83 550 kom 84 550 kom ' ' ' ' ' ' ' ' ' 191 820 kom 192 2000 soet ' ' ' ' ' ' I need to do a series of histograms for each of the codes, levels or factors in

Hi I have recently been analyzing birthweight data from a clinic. The data has obvious defects in that there is digit preference on certain weights making them overrepresented. This shows as spikes in the histogram on certain well rounded weights like 2, 2.5, 3, etc. I would like to show this to government officials but can't figure out how I should present the finding in an easy to

Hello all, I hope someone of you can help me out, I have searched other posts as well but I can't find any solution to the problem I'm dealing with. I want to make a histogram from the data Telephone Lines MDGdataset <-read.csv("MDG_dataset_2010.csv", header=T) MDGdatasetAdapted <- subset(MDGdataset, select = c(Country_Code, Country_Name, Year,

i want to plot the histogram and the curve in the same graph.if i have a set of data ,i plot the histogram and also want to see what distribution it was.So i want to plot the curve to know what distribution it like. -- View this message in context: http://www.nabble.com/how-to-plot-the-histogram-and-the-curve-in--the-same-graph-tp20082506p20082506.html Sent from the R help mailing list archive at

Dear all, I have done further modifications on the histogram functions that I reported earlier this year, and I hope this can be of use and perhaps included in the distribution. I have been using this stuff a couple of months myself, and while it is nothing sophisticated, it has it's applications. :-) I did a few small modifications today to make it a bit more compact. I have modified the

In R0.61, In hist(), should the line rel.freqs <- counts/(sum(x) * diff(breaks)) computing the relative frequencies or height of the rectangles in a histogram not be rel.freqs <- counts/(sum(counts) * diff(breaks)) instead, or do I misunderstand something? Thanks, Philippe -- -------------------------------------------------------- Philippe Lambert Tel:

Hi All, I am a PhD student in forestry science and I am working with LiDAR data set (huge data set). I am a brand-new in R and geostatistic (SORRY, my background it?s in forestry) but I wish improve my skill for improve myself. I wish to develop a methodology to processing a large data-set of points (typical in LiDAR) but there is a problem with memory. I had created a subsample data-base but