similar to: Adding columns to dataframe

Hi, I have two dataframes one with 144 rows and 160 columns (SDF1) and one with 12 rows and 160 columns (SDF2). Now I'm trying to divide rows 1:12 with SDF2, rows 13:24 with SDF2, rows 25:36 with SDF 2, . In S-Plus the following code works fine: DFS = SDF1[1:144,1:60] / as.vector(SDF2[1:12,1:160]) but in R when I try to implement the formula I get the following error: "/

HI Team, I am currently working on problem and stumped on "for" loop. Data: structure(list(Coutry = structure(c(3L, 3L, 3L, 3L, 2L, 2L, 1L, 1L), .Label = c("J", "M", "U"), class = "factor"), State = structure(c(1L, 1L, 4L, 2L, 5L, 5L, 3L, 6L), .Label = c("A", "C", "K", "O", "S",

I have a function that manipulates a list of numeric and character components of equal length and wants to return a data.frame. EG, f<-function() { a<-list(Int1=1:5,Char1=letters[1:5],Char2=letters[6:10]) b<-data.frame(a) } How can I get the columns Char1, Char2, (...CharN) returned coerced to character and not factor? It appears that I could coerce individual columns by

Hi all, there appears to be something strange with the plotting of tables of 1 dimension; if I attempt to make a plot of a table of characters with only 1 value I get an error (Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ). With more than one value I don't get errors, neither with integers (even if only 1 value): tbl.char1 <-

Hi all, there appears to be something strange with the plotting of tables of 1 dimension; if I attempt to make a plot of a table of characters with only 1 value I get an error (Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ). With more than one value I don't get errors, neither with integers (even if only 1 value): tbl.char1 <-

Thank you Jeff. Your code works, as usual , perfectly. I am just wondering why if i put the whole code in one line, i get an error message. sdf2 <- lapply( sdf, function(z){z$Value <-ifelse(is.na(z$Value),z$Value[!is.na(z$Value)][1],z$Value)z}) error. unexpected symbol in sdf2 Thanks again EK On Mon, Jan 8, 2018 at 3:12 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: >

Why do you want to modify df1? Why not just reassemble the parts as a new data frame and use that going forward in your calculations? That is generally the preferred approach in R so you can re-do your calculations easily if you find a mistake later. -- Sent from my phone. Please excuse my brevity. On January 7, 2018 7:35:59 PM PST, Ek Esawi <esawiek at gmail.com> wrote: >I just came

I don't know. You seem to be posting in HTML so your code is mangled. Can you post plain text and use the reprex package to make sure it produces the errorin a clean R session? -- Sent from my phone. Please excuse my brevity. On January 8, 2018 8:03:45 AM PST, Ek Esawi <esawiek at gmail.com> wrote: >Thank you Jeff. Your code works, as usual , perfectly. I am just >wondering why

OPS! Sorry i did indeed posted the code in HTML; should have known better. ifelse(is.na(z$Value),z$Value[!is.na(z$Value)][1],z$Value)z}) error. unexpected symbol in sdf2 On Mon, Jan 8, 2018 at 11:44 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > I don't know. You seem to be posting in HTML so your code is mangled. Can you post plain text and use the reprex package to

Upon closer examination I see that you are not using the split version of df1 as I usually would, so here is a reproducible example: #---- df1 <- read.table( text= "ID ID_2 Firist Value 1 a aa TRUE 2 2 a ab FALSE NA 3 a ac FALSE NA 4 b aa TRUE 5 5 b ab FALSE NA ", header=TRUE, as.is=TRUE ) sdf <- split( df1, df1$ID ) # note the extra [ 1 ]

Hello! I need some help with the linear discriminant analysis in R. I have some plant samples (divided into several groups) on which I measured a few quantitative characteristics. Now, I need to infer some classification rules usable for identifying new samples. I have used the function lda from the MASS library in a usual fashion: lda.1 <- lda(groups~char1+char2+char3, data=xxx) I'd

Hi With the example, na.locf seems to be the easiest way. > library(zoo) > na.locf(df1) ID ID_2 Firist Value 1 a aa TRUE 2 2 a ab FALSE 2 3 a ac FALSE 2 4 b aa TRUE 5 5 b ab FALSE 5 Cheers Petr > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Jeff > Newmiller > Sent: Monday, January

You can enforce these assumptions by sorting on multiple columns, which leads to na.locf(df1[ order(df1$ID,df1$Value), ]) On Mon, Jan 8, 2018 at 4:19 PM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > Yes, you are right if the IDs are always sequentially-adjacent and the > first non-NA value appears in the first record for each ID. > -- > Sent from my phone. Please

Yes, you are right if the IDs are always sequentially-adjacent and the first non-NA value appears in the first record for each ID. -- Sent from my phone. Please excuse my brevity. On January 8, 2018 2:29:40 AM PST, PIKAL Petr <petr.pikal at precheza.cz> wrote: >Hi > >With the example, na.locf seems to be the easiest way. >> library(zoo) > >> na.locf(df1) > ID

Hi, I am reading a large space-delimited text file into R (41 columns and many rows) and need to do run each row's values through another R object and then write to another text file. So, far using readLines and writeLines seems to be the best bet. I've gotten the data exchange working except each row is read in as one 'chunk', meaning the row has all values between two quotes

"Enforce" is overstating it... results will differ if there are no non-NA values for a given ID, and there is a potential further discrepancy if there are multiple non-NA values. But these issues were not identified by the OP, so may not be relevant in their case. -- Sent from my phone. Please excuse my brevity. On January 8, 2018 6:41:33 AM PST, Eric Berger <ericjberger at

Hello everyone, I am attempting to use the %in% operator with the ! to produce a NOT IN type of operation. Why does this not work? Suggestions? > data2[data1$char1 %in% c("string1","string2"),1]<-min(data1$x1) > data2[data1$char1 ! %in% c("string1","string2"),1]<-max(data1$x1)+1000 Error: unexpected '!' in "data2[data1$char1

Here are 3 patches to avoid undesired aborts of mkfs.btrfs. These are based on top of Chris''s btrfs-progs.git: git://git.kernel.org/pub/scm/linux/kernel/git/mason/btrfs-progs.git Thanks, H.Seto Hidetoshi Seto (3): btrfs-progs: error if device for mkfs is too small btrfs-progs: error if device have no space to make primary chunks btrfs-progs: calculate available

First some history. This is an Intel MB and processor some 6 years old, initially running CentOS 6. It has 4 x 1TB sata drives set up in two mdraid 1 mirrors. It has performed really well in a rural setting with frequent power cuts which the UPS has dealt with and auto shuts down the server after a few minutes and then auto restarts when power is restored. The clients needed a Windoze server

Full_Name: Ruskin Chow Version: R 2.0.1 OS: Windows 2000 Submission from: (NULL) (203.169.154.66) Data imported from SAS using read.xport() in package foreign are converted to <NA> when the SAS data field consists of character strings that are only one character long. This is apparently a previously reported bug and perhaps fixed in some platform other than Windows (rw2001).Some