similar to: Heatmap.2 - eliminate cluster and dendrogram

Hi When I give the command: > heatmap.2(as.matrix(d),Rowv=as.dendrogram(hc.gene),Colv=FALSE,scale="row ",trace="none",col=greenred.colors(79)) The resulting heatmap has re-ordered my columns! This is time-course data, and I don't want my columns re-ordered! Note from the help: Rowv: determines if and how the _row_ dendrogram should be reordered.

Dear All: I tried to use heatmap.2 to generate hierarchical clustering using the following command: heatmap.2(datamatrix, scale="row", trace="none", col=greenred(256), labRow=genelist[,1], margins=c(10,10), Rowv=TRUE, Colv=TRUE) datamatrix is subset of a RMA normalized data subset by a genelist. The problem is a lot of times, the z-score in key are from, like -5 to 15 or

Hi, I'm trying to save heatmaps as PDFs. However, the PDF version of the heatmaps (Heatmap_CAFvsTNF_run2.pdf) is blurred when compared to its counterpart, which was saved manually by using the software "Grab" (Heatmap_CAFvsTNF_run2.tiff). -----R code-------- sample_output <- "stroma_run2" filename <-

Hello, I've been clustering my data using hclust and cutting the resulting tree with cutree. Separately, I visualize the clusterings with heatmap. Is it possible to have the dendrogram on the heatmap reflect the cutree results? That is, instead of having one large dendrogram, it would have 4 or 25 in the example below. Any guidance on if that's possible or not, and what kinds of

Hey, I am still working on my heat map (for those who are read my previous post about row.names)… Now, I would like to save my heat map.2 in .png or .tiff in order being able to work on the picture in photoshop, but it doesn't work. I'am using (as I have found on some forum) > png("heatmap.2.png) # and it just doesn't work. when I try doing it with::

Hi Sorry to revisit an old problem, I seemed to solve this in 2004, only for it to resurface :-S I am trying to plot a heatmap, and I don't want the columns of my matrix re-ordered. The function doesn't seem to behave as the help would have you believe: a <- matrix(rnorm(100),nr=20) a.d <- dist(a) a.hc <- hclust(a.d) a.de <- as.dendrogram(a.hc) # columns are re-ordered

Hi, I'm trying to build dendrograms to pass to heatmap(). The dendrograms I build plot properly, but when I pass them to heatmap() I get the error message "row dendrogram ordering gave index of wrong length" (see output log below). I looked in the code of heatmap() and saw that the error was due to a NULL return value from order.dendrogram(), which in turn got a NULL return value

Full_Name: Shane Neph Version: 2.2.1 OS: mac os x Submission from: (NULL) (71.113.43.247) While I found the names of the package authors and maintainer, I was unsuccessful in finding any contact information. The preliminary documentation for heatmap.2 is inconsistent in at least a couple of places when discussing the suppression of one or more dendrograms (and column/row ordering in general).

Hi, I am using heatmap.2 of gplots to make heatmaps of my the attached file. I am giving my code for the same .. library(gplots) x=read.table("1.txt", header=TRUE) mat=data.matrix(x) heatmap.2(mat, col=greenred(75), Rowv=TRUE, Colv=TRUE, distfun = dist, hclustfun = hclust, dendrogram = c("both"), scale = c("row"), na.rm=TRUE, trace="none",

Good afternoon, I ran heatmap and hclust on the same matrix x (strictly, I ran heatmap(x), and hclust(dist(t(x))), and realized that the two dendrograms were slightly different, in that the left-right arrangement of one pair of subclusters (columns) was reversed in the two functions (but all individual columns were grouped correctly). Looking through the code for heatmap as a most definite

I would like to use gridBase to place four separate heatmaps (actually, a stripped-down heatmap.2 from ght gregmisc package that contains only the "image" part) into four different viewports. I can get the placement correct, but I keep 'losing' the previous plot. Any suggestions? Here is some quick example code trying to put a heatmap into the left viewport and then

Hi,   I need to generate a heatmap on a square matrix and wouldn't want to reorder the columns and the rows on the heatmap display.    I have used the options Rowv=NULL and Colv=NULL but doesn't seem to work. Following is a snippet of the heatmap function i am using. args <- commandArgs(); inputfile <- args[2] imgfile   <- args[3] bitmap(imgfile, height=15, width=15, res=100,

Hi I made heatmap of QTL based on Lod score. Where I have traits in columns and marker data (rows). I can not cluster both column and rows as I need the right order for marker data. Can someone suggest me better way of generating heatmaps especially the colour key I want to select to visualize the results which are more interesting to look at. > library(gplots) >

Dear list, I am using heatmap.2(x) to draw a heatmap. Ideally, I want to the matrix x clustered only by columns and keep the original order of rows unchanged. Is there a way to do that in heatmap.2()? Thanks a lot! Any suggestions will be appreciated! Best, Allen [[alternative HTML version deleted]]

Esteemed R-users, heatmap.2() is yielding an inappropriate key based on my colors and break-points. In the reproducible example below, the key is inappropriate (to me) because- 1. 'Orange' is simply not represented in the key, despite its prescence in the heatmap. 2. The proportions of the key are clearly out, ie., my largest bin, (0.1 - 0.2) is half the range, but this bin (colored

Hi, I have a question about the heatmap dendrogram in R. I loaded my data matrix in command heatmap(), and it gave me a heatmap accordingly, and the rows (genes) also were clustered accordingly. But now I don't want the genes clustered in that way, I have a new order of these genes, and want the rows of the heatmap are drawed as the order I give. Could anybody help me on that? Thank you!

Dear list members, I have been using R to create a heatmap where my data has continous variables from 0 to 100. When I create the heatmap, although the branches are correct, they do not order themselves so that the row with the most zeros is at one end and the row with the most 100s is at the other, which is what I would like them to do, so as to create a colour gradient down the graphic. I have

Hi all, By default, the heatmap function gives an image with a dendrogram added to the left side and to the top. Is it possible to only add the dendrogram to the left side and let the order of the columns unchanged ? I tried heatmap(mat, col=rbg,Rowv=res.hclust$order,Colv=1:dim(mat)[[2]]). In this case, the order of the columns are unchanged but a dendrogram is added to the top. How can I

Hello! I have data containing a large number of probabilities (about 60) of nonzero coefficients to predict 10 different independent variables (in 10 different BMA models). i've arranged these probabilities in a matrix like so: (IV1) (IV2) (IV3) ... p(b0) p(b0) p(b0) p(b1) p(b1) p(b1) p(b2) p(b2) p(b2) ... where p(b1) for independent variable 1 is p(b1 !=

Dear all, I've been trying to find how to compare tow different heatmaps but I'm having trouble getting the colors bar to be the same. I'm doing something like the following: library(gplots) dat<-cor(matrix(rnorm(100, m=10), nrow=10)) mat<-cor(matrix(rnorm(100), nrow=10)) dev.new() heatmap.2(mat, Rowv=NA, Colv=NA, col=redgreen(75), symm=TRUE, trace="none",