similar to: svychisq

Hello, I?m hoping you have a few minutes to help out someone very new to R. I?ve done some searching, but cannot find this particular issue. I have survey data from two different time periods (years). Both years are stratified samples and have the same variables (and variable names), but are different people in the community answering in the different years. Everything loads into the survey

Dear Forum I a running svychisq from the survey package and get errors with the number of dimensions, errors that I do not understand and do not know how to fix. I ask you kindly to help me out. The eror message follows with some information below. I hope there are enough information to help me to fix the problem if not please let me know what is needed Best Stefan Hrafn Jonsson > QHISQ2

Hello forum, I want to do a test of independence with svychisq, but I get an error, then this my code: am18 <- read.spss("C:/Users/diana/Dropbox/Semestre 10/Tesis 10/Tesis Diana/AMcomuna18-29MAR2012.sav", use.value.labels=TRUE, max.value.labels=Inf, to.data.frame=TRUE) b<-matrix(c(am18$N6_MANZANA),ncol=1) c<-matrix(c(am18$PM1_1_PONDEMUESTRA),ncol=1)

I have some output from a survey shown below and would like to insert total rows for each category to then be able to use it as a data set for further analysis. Is it possible to do this in R. In this example I would like to insert a row between rows 5 and 6, 10 and 11, 15 and 16, 20 and 21 and put in the sum of the rows 1-5, 6-10, 11-15, 16-20 and to delete row 21 which has NA in it. I would

Hi R-help, I posted about this late yesterday but got no response. I may have put TMI in the original request. Not to mention I couldn't cut and paste yesterday because I was working R off a non-network computer while asking for help on a network computer. Essentially, I have this user-defined function: test <- function(X){ chisq <- svychisq(~X

Dear Md Kamruzzaman, To answer your second question first, you could just use the svychisq() function. The difference-of-proportion test is equivalent to a chisquare test for the 2-by-2 table. You don't say how you computed the confidence intervals for the two separate proportions, but if you have their standard errors (and if not, you should be able to infer them from the confidence

Hello Everyone, I was analysing big survey data using survey packages on RStudio. Survey package allows survey data analysis with the design effect.The survey package included functions for all other statistical analysis except two-proportion z tests. I was trying to calculate the difference in prevalence of Diabetes and Prediabetes between the year 2011 and 2017 (with 95%CI). I was able to

Dear Md Kamruzzaman, I've copied this response to the r-help list, where you originally asked your question. That way, other people can follow the conversation, if they're interested and there will be a record of the solution. Please keep r-help in the loop See below: On 2024-01-17 9:47 p.m., Md. Kamruzzaman wrote: > > Caution: External email. > > > Dear John >