similar to: Left/right hand side characters

Someone can help me? I tried several things and always don't converge # Model library(sem) dados40.cov <- cov(dados40,method="spearman") model.dados40 <- specify.model() F1 -> Item11, lam11, NA F1 -> Item31, lam31, NA F1 -> Item36, lam36, NA F1 -> Item54, lam54, NA F1 -> Item63, lam63, NA F1 -> Item65, lam55, NA F1 -> Item67, lam67, NA F1 ->

Hi All, Apologies if this has been answered somewhere else, but I have been searching for an answer all day and not been able to find one. I am trying to plot a path diagram for a CFA I have run, I have installed Rgraphviz and run the following: pathDiagram(cfa, min.rank='item1, item2, item3, item4, item5, item6, item7, item8, item9, item10, item11, item12', max.rank='SMP,

Dear R people, I have a couple of questions about post-doc analyses for 2 by 2 within subjects ANOVA. I conducted a psycholinguistic study that combined a 2 by 2 design and a latin square design. Specifically, I had 32 items each of which generated 4 conditions. Participants saw each of the 32 items only once: 8 in Condition A, 8 in B, 8 in C, and 8 in D. The table below serves as an example.

Hi all, I have a data.frame I received with data that look like this (comma separated strings in last row): ID Shop Items ID1 A1 item1, item2, item3 ID2 A2 item4, item5 ID3 A1 item1, item3, item4 But I would like to unbind the strings in col(2) items so that it will look like this: ID Shop Items ID1 A1 item1 ID1 A1 item2 ID1 A1 item3 ID2 A2 item4 ID2 A2 item5 ID3 A1 item1 ID3 A1 item3 ID3 A1

Suppose I have a data frame like "dat" below. For some context, this is the format that represents student's taking a computer adaptive test. first.item is the first item that student was administered and then score.1 is the student's response to that item and so forth. item.pool <- paste("item", 1:10, sep = "") set.seed(54321) dat <- data.frame(id =

Dear users, I would like to process all the lists from all *.rda files that I have in one folder. Up to now, I can load all the *.rda files without any problem. The problem is when I want to access the list saved within each *.rda file (only one list per rda file). Here is my code: fpath <- "D:/R" listnames <- list.files(path=fpath, pattern=glob2rx("*.rda"),

List: Thank you for the replies to my post yesterday. Gabor and Phil also gave useful replies on how to improve the function by relying on mapply rather than the explicit for loop. In general, I try and use the family of apply functions rather than the looping constructs such as for, while etc as a matter of practice. However, it seems the mapply function in this case is slower (in terms of CPU

Folks, It has been a whole day spent on this but I still can''t get my mind around the most probably very stupid/basic mistake here... First, the code I use: <h3>List A</h3> <ul id="lista" > <li id="item1"> Item 1</li> <li id="item2"> Item 2</li> <li id="item3"> Item 3</li> </ul>

Hello R folks. 1) The question that generated the data, which I call Qx: Which of the following 5 items have you performed in the past month? (multipe response) 2) How the data is coded in my current dataframe: The first item that a person selected is coded under a field called Qxfirst; the second selected under Qxsecond, etc. For the first Person, the NAs mean that that person only selected

Dear R-users, I would like to construct a list of arguments for a function in a format function (list(item1=c("A","B"), item2=c("B","C")), item3=...): The individual vectors in the list are permutations of colnames of a dataframe. The trouble is that I am not able to handle escaping of parentheses correctly. I was trying the following: library(gregmisc)

Hello- I have rather a messy SPSS file which I have imported to R, I've dput'd some of the columns at the end of this message. I wish to get rid of all the labels and have numeric values using as.numeric. The funny thing is it works like this: as.numeric(mydata[,2]) # generates correct numbers however, if I pass the whole dataframe at once like this: apply(mydata, 1:2, function(x)

Hello, I have a nested named list structure, like the following: x <- list( list( list(df1,df2) list(df3, list(df4,df5)) list(df6,df7))) with df1...d7 as data frames. Every data frame is named. Is there a way to get a specific named element in x? so, for example, x[[c("df5")]] gives me the data frame 5? Thank you in advance! Best, Friedericksen

Hi , For our production package i need to create a dataframein C . So I wrote the following code SEXP dfm ,head,df , dfint , dfStr,lsnm; *SEXP valueVector[2];* char *ab[3] = {"aa","vv","gy"}; int sn[3] ={99,89,12}; char *listnames[2] = {"int","string"}; int i,j; //============================= PROTECT(df = allocVector(VECSXP,2));

All - Each time through a loop I create a new dataset, which I would like to append to a list object. Each item of the list should be the data matrix created in that step of the loop; I would like the NAME (or tag) of that list item to be assigned the value of a character string: I've tried something like this: running.list <- numeric(0) for(i in 1:num.files){ ..... running.list

Hi , I am trying to create a dataframe in C and sebd it back to R. Can anyone point me to the part of the source code where it is doing , let me explain the problem I am having . -------------------------------------------------------------------- My simple implementation is like this SEXP formDF() { SEXP dfm ,df , dfint , dfStr,lsnm; char *ab[3] =

I have constructed the function mml2 (below) based on the likelihood function described in the minimal latex I have pasted below for anyone who wants to look at it. This function finds parameter estimates for a basic Rasch (IRT) model. Using the function without the gradient, using either nlminb or optim returns the correct parameter estimates and, in the case of optim, the correct standard

Hi all, I looked for a function that would retrieve all(!) names of an arbitrary deeply nested named list. Also, names should optionally be arranged in a way that reflects the list's hierarchy structure (i.e. 'a$a.1$a.1.1' etc.) Also, there should be a recursive index linked to a respective list branch that could be used to index a list by names (as you would do with named vectors,

> From: Gary Stainburn <gary.stainburn@ringways.co.uk> > To: "Samba Mailing List (E-mail)" <samba@samba.anu.edu.au> > Subject: smbtar multiple machines > Message-ID: <01BDDD6E.ABFF0580@garys.computer.leeds> > > Hi all, > > I'm just looking at using smbtar to backup the Win95 PC's on my network, and would like usability ideas please. >

>> I am trying to compile rseries from Whit Armstrong and a colleague of mine found a problem with using GCC4 I get the following error when compiling rseries g++-sjlj -Ic:/R/include -O2 -Wall -c Rutils.cpp -o Rutils.o Rutils.cpp: In function 'double* getColPointer(SEXPREC*, int)': Rutils.cpp:406: warning: deprecated conversion from string constant to 'char*'

Dear R-users, I keep getting an ERROR saying " Error in model.matrix.default(formula, mframe) : model frame and formula mismatch in model.matrix() " when i fit poLCA with more than 63 variables. Below are the details. I am trying to do a Latent Class Analysis using poLCA. My data set contains binary scores of, for instance, 200 students on 100 items. These numbers could even be more