similar to: Problem with very old dates

Hello: I have some trouble making a prediction from an AR(p) model. After I have the AR(p) model fitted , I want to use a new data set to make predictions. But I get the error: Error in newdata - object$x.mean : non-numeric argument to binary operator. A small version of my original data looks like: X1 X2 X3 X4 40813.65 1 10 41.86755 40813.65 1 8 41.86755 40813.66 1 8 41.86755

Dear R-Helpers: I'm having a problem getting dates into the correct format. I have a data frame, which is based on a .csv file that I imported into R via read.table. R has converted my date variables to factors; when I use the as.Date command, most of the values are converted "correctly" (and by this I guess I mean converted "as I wish them to be") but some have not been.

I have a working dialplan for our phone system with Mon-Fri, business hours identification, etc. But what I'm lacking right now is support for company holiday dates. What I'd like to do is to create a database of these dates and just update them as new years rollover. I suspect others have done this sort of thing with Asterisk before, but I've not found any resources so far.

Hi I have many excel files were the Date field was not declared as date, so the dates look like this: 1/2/1978 I know that the format is day/month/year How can I make R change this to Date format? If I use strftime, I get wrong dates: dataset=c("1/2/1978") strftime(dataset,"%d/%m/%Y") "19/02/0001" Thanks in advance.

Hello all, I am having a little trouble working with "strptime" and I was hoping someone might be able to give me a hand. I have an instrument that outputs an ordinal date and time in two columns something like this: day.hour min.sec 1 12525 2050 2 12518 2029 3 12524 2023 4 12524 2028 5 12507 2035 Now the problem I am having is converting these numbers

I have trouble with this: as.Date("Sep-1981", format="%b-%Y") Returns "NA" >From documentation for strftime '%b' Abbreviated month name in the current locale. (Also matches full name on input.) '%Y' Year with century. What am I doing wrong? cheers Worik [[alternative HTML version deleted]]

Hi, I have the following data in two columns. The first column is the date, the second is data. Date Data 3-Jan-95 459.21 4-Jan-95 459.13 5-Jan-95 460.73 6-Jan-95 460.38 9-Jan-95 460.67 10-Jan-95 460.9 11-Jan-95 461.68 12-Jan-95 461.64 13-Jan-95 461.64 16-Jan-95 465.97 17-Jan-95 469.38 18-Jan-95 470.05 19-Jan-95 469.72 20-Jan-95 466.95 23-Jan-95 464.78 24-Jan-95 465.81 25-Jan-95 465.86 I would

Hallo, I am trying to plot dates in x-axis. The format of my dates are in dd/mm/yyyy. At first I install zoo package. After R reads my file, I change the default format of dates to the format that I have, >myfile<-read.csv >DATE<-as.Date(DATE,format="%d/%m/%Y") up till now everything goes ok; when however I go and plot for example >plot(DATE, Discharge) in the x-axis I

How do I sum 15 years to my dataset? original dataset dates val 1 2001-01-12 1.2 2 2001-02-12 1.2 3 2001-03-12 1.2 result dates val 1 2016-01-12 1.2 2 2016-02-12 1.2 3 2016-03-12 1.2

Hi, I have dates in this kind of format (day, month, year): > dput(head(dates, 10)) c("6.4.7", "29.12.98", "19.10.91", "20.6.92", "2.9.3", "23.6.3", "13.7.93", "23.3.7", "26.6.95", "15.2.10") So, as you can see, there is no century. How can I change this character data into dates? Any help

I have two collections of dates and I want to figure out what dates they have in common. This is not giving me what I want (I don't know what it is giving me). What is the best way to do this? Tom > data1 [1] "1948-02-24 EST" "1949-04-12 EST" "1950-05-29 EDT" "1951-05-21 EDT" [5] "1951-12-20 EST" "1953-01-22 EST"

Proper calendar dates in R are great for plotting and calculating. However for the non-wonks among us, they can be very frustrating. I have recently discussed the pains that people in my lab have had with dates in R. Especially the frustration of bringing date data into R from Excel, which we have to do a lot. Please find below a simple analgesic for R date importation that I discovered over

Hi, I am constructing a contingency table using xtabs. The function works great: mo yr Sep Oct Nov Dec 1950 -7.164486e-02 3.152674e-02 -1.283389e-02 1.570382e-01 1951 3.054293e-02 4.665234e-02 -2.445499e-04 8.720204e-02 1952 3.937034e-02 -4.790636e-02 5.022616e-02 1.180279e-01 but I wonder if there is an argument I can pass to xtabs

It seems that you have load the "survival" package date.mdy is a function from this one. In this function the "origin" of the time is the first day of 1970 in the base package the origin is the first day of 1960 it's very curious... Benjamin Esterni France From: "Vegard Andersen" <vegard.andersen@ism.uit.no> Subject: [R] Date conversion problem using

Hi, I have a few dates coming from the datebase in the format ''DD-MM-YYYY'' How can I change this in to a more human readable format? such as 1st July 2006 Thanks Scott -- Posted via http://www.ruby-forum.com/.

I have used the RODBC package to read in data I have stored in an Access file. When I am using data from files other than ACCESS I have no problem using the survival package to work with dates; however, with the ACCESS data the dates are reading-in in the following format: "2004-02-11 Pacific Standard Time". How do I remove the "Pacific Standard Time" part in ACCESS or R so

I'm looking for library which let mi convert dates for example like this: 00-06-05 00:00 00-08-06 00:00 00-08-16 00:00 00-05-23 00:00 00-01-14 00:00 00-10-28 00:00 and as a result I want to get a 3 levels -- View this message in context: http://www.nabble.com/library-which-convert-dates-tp23295853p23295853.html Sent from the R help mailing list archive at Nabble.com.

Dear list, This is a bit of an off-topic question, but I'm hoping to get some advice from more experienced people. I've used the website "Web of Science" to manually collect publication counts responding to several keywords as a function of date, since the 1960s. http://apps.isiknowledge.com/RAMore.do?product=UA&search_mode=&SID=P1g9lFJp9 at

Hi, I am using aggregate() to add up groups of data according to year and month. It seems that the function aggregate() automatically sorts the levels of factors of the grouping elements, even if the order of the levels of factors is supplied. I am wondering if this is a bug, or if I missed something important. Below is an example that shows what I mean. Does anyone know if this is just the way

Hi r-helpers... Why do I get this strange huge jump of 36524 days when changing "origin" from 1969-01-01 to 1968-12-31. It should still be close to zero! This really messes up my calculations of follow-up times in my analyses. > julian(strptime("010169", format = "%d%m%y"),origin = as.Date("1969-01-01")) > Time difference of -0.04166667 days >