similar to: convert decimals to fractions - sorted

In the 'me too' vein, I also have an untested 3624 here on the shelf and am waiting on a shipment of T100 cards to play with. Documentation is very hard to come by. Alcatel are certainly the owners of the Mainstreet product line but, without a support contract, any documentation they may have is essentially unavailable as their per-incident fees for support cost more than most of the

I intend to draw a plot of y against x. In the background of this graph I wish to creat a histogram of the horizontal variable x. Does any expert know how to produce such a plot? [[alternative HTML version deleted]]

In the below code fragment, print(arg) always prints the last element of rekeningen$rekening. Is this because of lazy evaluation? I.e. arg is evaluated at the time the button is pressed? And, if so, how can I avoid this? I tried function() {force(arg); print(arg)} but that didn't work either. Thanks, Jeebee. for(rek in seq(1,nrow(rekeningen))) { arg <- rekeningen$rekening[rek]

Can anyone tell me how I can supply more than one graph to plotCI (gplots) at once? Below is what I tried, also with rbind instead of cbind. What is the way to do this (in general, I think)? Problem is that lines of 1-st and 2-nd series are mixed, while they have nothing to do with each other. I also tried calling plotCI with argument add=TRUE, which didn't seem to work (that is actually

I've found several similar issues with write.table/read.table with Dates on this list, but trying to follow this advice I still get an error. First, I read in data from several files, constructing several date/time columns using ISOdatetime > str(Tall$Begin) 'POSIXct', format: chr [1:40114] "2005-10-02 00:00:00" "2005-10-02 00:00:00" ... > length(Tall$Begin)

Dear R-list, I'm iterating several calls to plotCI [gplots], like so: plotCI( x = xvals.f[sorted], y = yvals.f[sorted], xlim = c(xmin, xmax), ylim = c(ymin, ymax), pch = plot_symbols[graph_idx], type = "b", lty = plot_linetypes[1], col = plot_colors[graph_idx], barcol = plot_colors[graph_idx], uiw = NA, xlab = "", ylab = "", add =

Hello, Being new to R, I am completely stuck with the following problem. Please help to find a general solution to the following matrix task: Given: N<-4 input_mat<-matrix(c(1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0),ncol=N)

Hello! The IWigdets::combobox has an option "selectioncommand" to specify a procedure which is called when an item in the combobox is selected. Does ComboBox from Bwidgets have an equal option or is there a simple method to do thi? I haven't found one but i would like to use Bwidgets instead of Iwidgets. Another question which should not be a problem, but at the moment I just

Dear R-members, Suppose I have a vector with the following strings: V = c("Welfare_Group_1024", "Welfare_Group_1536", "Welfare_Group_160") I want to 'automatically generate a nice y-axis label for this data. A good candidate is something close to "Welfare Group". Is there an easy way to compute something close to the greatest common

Hi List, Is it possible to tell R to use tcl/tk 8.5? My R package seems to depend on libtcl8.4.so. However, in Windows it seems to be possible to set TCL_LIBRARY and MY_TCLTK. Is there something similar possible in Linux? I have installed: $ rpm -q R R-2.3.1-1.fc5 $ locate libtcl8 /usr/lib/libtcl8.4.so /usr/local/lib/libtcl8.5.so

Hi, Does anyone know an R function to impute hamming distance? Thanks Ana O@@@@@ &nb @@@O@@O@ Centro de Gen?mica @O@@@@O@ Instituto Valenciano de Investigaciones Agrarias (IVIA) @@@O@@@@ Carretera Moncada - Naquera, Km. 4,5 @@@@O@ 46113 Moncada (Valencia) SPAIN || & || &

Hi, Given a frame with calendar date's: "2005-07-01", "2005-07-02","2005-07-03","2005-07-04","2005-07-05",etc. I want to extract the following from these dates: week number month number year number Any ideas how to accomplish this? Many thanks. Regards, Richard

Please, I??d like to store this sample matrix as a new object. How can I do this ? pulse <- c(67, 67, 68, 68, 68, 69, 69, 69, 69, 69, 70, 70, 70, 70, 71, 71, 72, 72, 73, 74) m <- NULL x <- 0 for (i in 1:5) { x <- sample(pulse,3) m <- mean(x) cat(x,m,"\n") } Thanks, Mauricio

I'm trying to make more compact the definition of a function as for example: f <- function(x) 2/x+3/x by simply defining the array of coefficients arr = c(2,3) and setting: g <- function(x) sum((arr/x)) Everything seems to work fine because the values returned by f and g result coincident for different values of their argument, but when I try to plot the function g using: x =

Hi All, I need your help in NA handling. I've following data series. x<-c(1,4,5,8,NA,4,NA,5,5,1,2,7,8,9,NA,NA,NA,15,6,8) Now i want to interpolate where NA value persists. Like, between 9 and 5 there are three NA's. So, that should be interpolated like, 1st NA-> (15-9)/4 2nd NA-> 1st NA value + (15-9)/4 Can i get help on this using a 'for' loop. Actually i have huge

I am running the following command. for( i in 1:378){ for (j in 1:5) { *********Year [((i-1)*5)+j,1]<- yearly[i,2];********* Year [((i-1)*5)+j,2] <- j; Year [((i-1)*5)+j,3] <- yearly[i,(j+2)]; j <- (j+1); } i <- (i+1) } The array referenced yearly[i,2] contains conference names i.e. BIG12, SEC, BIG10. The loop executes fine except for the fact that

Dear R-user I have 100 lists. Each list has several components. For example, >data1 $a [1] 1 2 $b [1] 3 4 $c [1] 5 There are data1, data2,...., data100. All lists have the same number and the same name of components. Is there any function I can use for applying to only a specific component across 100 lists? (e.g., taking mean of $c acorss 100 lists) or do I need to write my own

Hi all, I have a matrix with each column containing a large number of integers (0 and above). in each column beyond a certain row (say row 120 in column 1, row 134 in column 2, 142 in column 3...) there are only 0's. I want to find, for each column the row number of the last row which contains a positive integer beyond which there are 10 or more 0's. so in the following example (single

I'd like to convert a two-dimensional function f(x,y) to a matrix m, so that m[x,y] = f [x,y]. How can I achieve this? Thanks, Lothar

Hi everyone, I have different listboxes in the same toplevel window. The problem is, if I select (by left clicking) one of those listbox elements, the current selection in the other listboxes is cleared! Anybody knows how I can prevent this? Thanks, --------------------------------------------------- Rita Sousa DME - ME: Departamento de Metodologia Estatística - Métodos Estatísticos INE -