similar to: difference between 2 dates: IN MONTHS the way Mothers compute it

Hi R Community: I want to take the difference in two dates: dt2 - dt1. But, I want the answer in months between those 2 dates. Can you advise me? Please respond to: pzs6 at cdc.gov Thank you! Phil Smith Centers for Disease Control and Prevention

Hi R-help: I'm just an old guy and new to this list... But have been using R for years now. I want to make a map of counties in the US with shaded colors that depend on the level of variable "Y" that I want to map. I have the US county and state fips codes and the Y variable. How do I do this? Please reply to pzs6@cdc.gov Thanks, Phil Smith pzs6@cdc.gov [[alternative HTML

Hi R-Help: I want to produce a map of the US with different colors for selected states. I installed the map package, and then used: library(maps) I can see that by using map( 'state' ) you get the state boundaries, also. How do I fill in different colors for the different states? I see there is a col parameter for map, but can't see how to get it to work! Please reply

Here is a question from an old guy: I want to use the boxplot function as follows: boxplot( p.prop ~ R + bins ) This command makes nice boxplot for the factor "R" crossed with the factor "bins". I am having alot of trouble getting control of the labels on the X axis. I want to control it more by specifying what the labels are, controling the 'size' of those

Hi R people: I'm trying to set the dimnames of a data frame called "ests" and am having trouble! First, I check to see if "ests" is a data.frame... > is.data.frame( ests ) [1] TRUE ... and it is a data frame! Next, I try to assign dimnames to that data frame.... > dimnames( ests )[[ 1 ]] <- as.character( ests$stfips ) Error in

HI, R-Users: I got a questions. have been struggling so long time.... I have this data: > m1$Year_Month 201009 201010 201011 201101 201102 > min(m1$Year_Month) 201009 I want to calculate the following two answers, how do I program it? > difference in Month????? [1] 0 1 2 4 5 >difference in Days????? 0 31 61 .... Thank you in advance!!! Tammy [[alternative

Hello! I'd like to take Dates and extract from them months and years - but so that it sorts correctly. For example: x1<-seq(as.Date("2009-01-01"), length = 14, by = "month") (x1) order(x1) # produces correct order based on full dates # Of course, I could do "format" - but this way I am losing the "Date" quality of the data:

Dear useRs and developeRs, In my diploma thesis I work with a daily time series of glacier runoff data. I did already aggregate them to monthly means etc. Now i want to use just the summer values (I am indecisive by now what that means, but let's make it easy and use months like June). Is there a way to extract the data off this zoo into another zoo with frequency=1 ? Do you have

Dear R-people: François Michonneau's method to obtain the special character plus/minus works on Windows 2000 professional. Many Thanks to François for his work! Phil Smith Centers for Disease Control and Prevention Atlanta, GA _____ From: François MICHONNEAU [mailto:francois.michonneau@gmail.com] Sent: Monday, March 20, 2006 1:58 PM To: r-help@stat.math.ethz.ch; Smith, Phil

We are constructing growth charts (age/weight and age/length) for children with diagnosis that impacts weight/length. But we we don't know how to use R for producing growth charts. We are collection data of Age, Weight and Length. The data are used to produce diagnosis-specific Growth charts (like the CDC Growth Charts:

Hello everyone I use zoo objects and I need to find a date 6 months before today's date. Example, today we have 3rd March 2010, I need to find the date 3rd September 2009. How could I do that, please? Regards, Sergey -- Simplicity is the last step of art./Bruce Lee The more you know, the more you know you don't know.

Hi all, can anyone please guide me how to create a sequence of months? Here I have tried following however couldn't get success > library(zoo) > seq(as.yearmon("2010-01-01"), as.yearmon("2010-03-01"), by="1 month") Error in del/by : non-numeric argument to binary operator What is the correct way to do that? Thanks for your time.

Hello! I have a data frame with dates. I need to create a new "month" that starts on the 20th of each month - because I'll need to aggregate my data later by that "shifted" month. I wrote the code below and it works. However, I was wondering if there is some ready-made function in some package - that makes it easier/more elegant? Thanks a lot! # Example data:

I have a vector of dates. I wish to find the month end date for each. Any suggestions? e.g. For 12/15/05, I want 12/31/05, For 10/15/1995, I want 10/31/1995, etc __________________________________________________ [[alternative HTML version deleted]]

Dear Users, I have a monthly data for a number of years(1960-2007) for a number of stations and i wish to extract sesonal time-series for the months of March-May and October-November for very station. I have read this data with read.table in R with stations as columns and time (months) as rows. My attempt to aggregate with the zoo package using the function as.yearqtr failed since this sums

Hello! If I have in my data frame MyFrame a variable saved as a Date and want to translate it into years, I currently do it like this using "zoo": library(zoo) as.year <- function(x) as.numeric(floor(as.yearmon(x))) myFrame$year<-as.year(myFrame$date) Is there a function that would do it directly - like "as.yearmon" - but for years? Thank you! -- Dimitri

Dear R gurus, I am currently using the chron package for date manipulation in R and I am able to control the date which take the format - 1998/07/03, and - 2006-09-15 (date without time) Library(chron) As.Date(2006-09-15, format = '%Y-%m-%d') However I have a problem with the date containing only the year and month (i.e. 2006-09, 2007/08, 200609).

Dear R Help, I am trying to get fields showing the last day of each month for a monthly closing project. In order to find the last day of the previous month, I subtract the number of days from the current month. For all months my code works; however, for October, my code doesn't work...it returns 2010-09-*29* instead of 2010-09-*30*. format(strptime("2010-10-31",

Dear R users: I have a data set that looks something like this: ID time y 1 2/01/2008 4 1 2/09/2008 12 1 9/01/2008 8 2 1/06/2008 3 2 3/01/2008 4 2 3/09/2008 9 2 6/03/2008 4 3 1/02/2008 3 3 1/10/2008 8 3 2/02/2008 7 3 2/10/2008 3 I'd like to sum up the weekly data to the monthly level, so that it looks something

Hi R-ers: I'm drawing a plot and have used different line types (lty) for different race/ethnicity groups. I want a legend that explains what line types correspond to the different race/ethnicity groups. I used the following code: legend( 1992 , 42 , c("Hispanic" , "non-Hispanic white (NHW)" , "non-Hispanic black" , "AI/AN" , "Asian" ) ,