similar to: Mixed GLM methodology and execution question

Hi, I am trying to find m breakpoints of a linear regression model. I used the segmented package. It works fine for small number of predicators and breakpoints.(3 r.v. 3 points). However, my model has 14 variables it even would not work even for just one breakpoints!. The error message is always estimated breakpoints are out of range. Since my problem is time related problem. So I

hello I make a subroutine that give-me a (mathematical) function in string format. I would like transform this string into function ( R function ). thanks for any tips. cleber #e.g. fun_String = "-100*x1 + 0*x2 + 100*x3" fun <- function(x1,x2,x3){ return( ############ evaluation( fun_String ) ############ ) True String mathematical function :-( :-( > nomes [1]

Hello there, I am not quite sure how to interpret the output of Rprof (in the following the output I was staring at). I was poking around the web a little bit for documentation but without much success. I guess if I want to figure out what takes so long in my code the 2nd table $by.total and the total.pct column (pct = percent) is the most helpful. What does it mean that [ or [.data.frame is

Hi, R users, I'm trying to transform a matrix A into B (see below). Anyone knows how to do it in R? Thanks. Matrix A (zone to zone travel time) zone z1 z2 z3 z1 0 2.9 4.3 z2 2.9 0 2.5 z3 4.3 2.5 0 B: from to time z1 z1 0 z1 z2 2.9 z1 z3 4.3 z2 z1 2.9 z2 z2 0 z2 z3 2.5 z3 z1 4.3 z3 z2 2.5 z3 z3 0 The real matrix I have is much larger, with more than 2000 zones. But I think it should

On Tue, 12 Feb 2019, 14:32 Paulo Matos <pmatos at linki.tools wrote: > > > On 12 February 2019 18:59:21 CET, Mikhail Ramalho < > mikhail.ramalho at gmail.com> wrote: > >I _think_ there is a problem with the license as well: Z3 is MIT, so > >clang > >would have to be released with Z3's license. > > I don't think that's a problem. You are not

I _think_ there is a problem with the license as well: Z3 is MIT, so clang would have to be released with Z3's license. On Tue, 12 Feb 2019, 09:24 Roman Lebedev via cfe-dev <cfe-dev at lists.llvm.org wrote: > On Tue, Feb 12, 2019 at 4:13 PM Paulo Matos via cfe-dev > <cfe-dev at lists.llvm.org> wrote: > > > > Hello, > > > > I am trying to run scan-build

Hi, I tried this puppet shell command and I''m getting a warning: oracle@z3:/pt/b/puppet$ puppet describe -s user racc/parser.rb:27: warning: already initialized constant Racc_Runtime_Version Here is some info about my setup: oracle@z3:/pt/b/puppet$ oracle@z3:/pt/b/puppet$ ruby -v ruby 1.9.2p318 (2012-02-14 revision 34678) [x86_64-linux] oracle@z3:/pt/b/puppet$ oracle@z3:/pt/b/puppet$

Hello all R-users _question 1_ I need to make a statistical model and respective ANOVA table but I get distinct results for the T-test (in summary(lm.object) function) and the F-test (in anova(lm.object) ) shouldn't this two approach give me the same result, i.e to indicate the same significants terms in both tests??????? obs. The system has two restrictions: 1) sum( x_i ) = 1 2) sum(

Friday I enabled the inlinehint function attribute in the inliner. It mostly affects the performance of -Os compiled code. I have made some measurements on the SPEC test suite to show what it means. I made three runs of then nightly tests. The baseline represents -Os with no inlinehint: make TEST=nightly OPTFLAGS=-Os EXTRA_LOPT_OPTIONS=-inlinehint-threshold=0

Hi Team, Am trying to install libguestfs in my redhat 8.2 version default its installing 1.38.4. Could you please help us with the installation of version 1.50 libguestfs (through command line in RHEL 8.2) and supported RHEL versions of 1.50. Regards, Teja K From: Teja Konapalli Sent: Tuesday, September 5, 2023 8:16 PM To: libguestfs at redhat.com Subject: LIBGUESTFS supported version Hi

Dear all, I am interested in solving a MIP problem with binary outcomes and continuous variables, which ARE NOT RESTRICTED TO BE NEGATIVE. In particular, Max {z1,z2,z3,b1} z1 + z2 + z3 (s.t.) # 7 z1 + 0 z2 + 0 z3 + b1 <= 5 # 0 z1 + 8 z2 + 0 z3 - b1 <= 5 # 0 z1 + 0 z2 + 6 z3 + b1 <= 7 # z1, z2, z3 BINARY {0,1} # -5<= b1 <=5 (i.e. b1 <= 5; -b1 <= 5 ) Using

I have the joint distribution of three discrete random variables z1, z2 and z3 which is captured by "z" and "prob" as described below. For example, the probability for z1=0.46667, z2=-1 and z3=-1 is 2.752e-13. Also, the probability adds up to 1. > head(z) z1 z2 z3 [1,] -0.46667 -1.0000 -1.0000 [2,] -0.33333 -0.9333 -0.9333 [3,] -0.20000 -0.8667 -0.8667

Hi Kostya & Yury, Thanks for the advice. On 9 February 2016 at 22:48, Kostya Serebryany <kcc at google.com> wrote: > Hi Dan, > > On Tue, Feb 9, 2016 at 10:57 AM, Dan Liew <dan at su-root.co.uk> wrote: >> >> Hi, >> >> # TL;DR >> >> I've been building an application with and without the address >> sanitizer (with gcc 5.3 and

Most likely, previous computations have ended up giving slightly different values of say 0.13333. A pragmatic way out is to round to, say, 5 digits before applying unique. In this particular case, it seems like all numbers are multiples of 1/30, so another idea could be to multiply by 30, round, and divide by 30. -pd > On 28 Jul 2017, at 17:17 , li li <hannah.hlx at gmail.com> wrote:

On 4/5/13 3:16 PM, Giacomo Tagliabue wrote: > I created a loadable optimization following the tutorial at > http://llvm.org/docs/WritingAnLLVMPass.html. I want to use the Z3 > library, installed in my system, in my optimization. When I include > z3++.h (the name of the library) in the code and use its classes, it > compiles well, but when I try to run it it says: > >

I am currently attempting to split a long list of strings (let's call it "string.list") that is of the format: "1234567.z3.abcdef-gh.12" I have gotten it to: "1234567" "z3" "abcdef-gh" "12" by use of the strsplit function. This leaves me with each element of "string.list" having a split string of the above format. What

Hi, I am new to R for solving optimization problems, I have set of communication channels with limited capacity with two types of costs, fixed and variable cost. Each channel has expected gain for a single communication. I want to determine optimal number of communications for each channel maximizing ROI)return on investment) with overall budget as constraint.60000 is the budget allocated.

Hello everybody I am trying to extract some observations from a data frame, ie the subjects that belong to a given group, and although t-test etc work if I try to obtain the number of subjects in the subgroup i get some funny numbers. All the subjects with NA for group are included in the subgroups 'group==1' etc. Is this a bug? for example in Windoze R : Copyright 2001, The R

Dear All, I am a research student in environment. I have only little programming knowledge. I am currently doing the last project about rainfall impact on ground water quality in an area. It happens that I have to use R to read rainfall data (3 dimension) from ASC file (*.asc), and then write them into one NCDF file (*.nc). I have been working very hard on study R, but I

I think I am in the first case, but I don't understand something, the -load option during which command? opt? and which file should I load? libz3.so? On 5 April 2013 15:32, John Criswell <criswell at illinois.edu> wrote: > On 4/5/13 3:16 PM, Giacomo Tagliabue wrote: > > I created a loadable optimization following the tutorial at >