similar to: Problems with heatmap.2 in the gregmisc package

Hi When I give the command: > heatmap.2(as.matrix(d),Rowv=as.dendrogram(hc.gene),Colv=FALSE,scale="row ",trace="none",col=greenred.colors(79)) The resulting heatmap has re-ordered my columns! This is time-course data, and I don't want my columns re-ordered! Note from the help: Rowv: determines if and how the _row_ dendrogram should be reordered.

Full_Name: Shane Neph Version: 2.2.1 OS: mac os x Submission from: (NULL) (71.113.43.247) While I found the names of the package authors and maintainer, I was unsuccessful in finding any contact information. The preliminary documentation for heatmap.2 is inconsistent in at least a couple of places when discussing the suppression of one or more dendrograms (and column/row ordering in general).

Hi,   I need to generate a heatmap on a square matrix and wouldn't want to reorder the columns and the rows on the heatmap display.    I have used the options Rowv=NULL and Colv=NULL but doesn't seem to work. Following is a snippet of the heatmap function i am using. args <- commandArgs(); inputfile <- args[2] imgfile   <- args[3] bitmap(imgfile, height=15, width=15, res=100,

Using the heatmap.2 function, I am trying to generate a heatmap of a 2 column x 500 row matrix of numeric values. I would like the 1st column of the matrix sorted from the highest to the lowest values - so that the colors reflected in the first column of the heatmap (top to bottom) go from red to green. After sorting the matrix (z), I tried the following command, but the data remains

Hi, I'm trying to build dendrograms to pass to heatmap(). The dendrograms I build plot properly, but when I pass them to heatmap() I get the error message "row dendrogram ordering gave index of wrong length" (see output log below). I looked in the code of heatmap() and saw that the error was due to a NULL return value from order.dendrogram(), which in turn got a NULL return value

Good afternoon, I ran heatmap and hclust on the same matrix x (strictly, I ran heatmap(x), and hclust(dist(t(x))), and realized that the two dendrograms were slightly different, in that the left-right arrangement of one pair of subclusters (columns) was reversed in the two functions (but all individual columns were grouped correctly). Looking through the code for heatmap as a most definite

Hello, I've been clustering my data using hclust and cutting the resulting tree with cutree. Separately, I visualize the clusterings with heatmap. Is it possible to have the dendrogram on the heatmap reflect the cutree results? That is, instead of having one large dendrogram, it would have 4 or 25 in the example below. Any guidance on if that's possible or not, and what kinds of

Dear all, I've been trying to find how to compare tow different heatmaps but I'm having trouble getting the colors bar to be the same. I'm doing something like the following: library(gplots) dat<-cor(matrix(rnorm(100, m=10), nrow=10)) mat<-cor(matrix(rnorm(100), nrow=10)) dev.new() heatmap.2(mat, Rowv=NA, Colv=NA, col=redgreen(75), symm=TRUE, trace="none",

Esteemed R-users, heatmap.2() is yielding an inappropriate key based on my colors and break-points. In the reproducible example below, the key is inappropriate (to me) because- 1. 'Orange' is simply not represented in the key, despite its prescence in the heatmap. 2. The proportions of the key are clearly out, ie., my largest bin, (0.1 - 0.2) is half the range, but this bin (colored

Under Details, the documentation says "[if Rowv or Colv] is 'NULL', _no reordering_ will be done for the corresponding side." In fact, as explained elsewhere in the documentation, 'NA' is required, not 'NULL'. An anonymous expert suggested that I should attach an svn diff file to this report, so I will. JD -------------- next part -------------- Index:

Hi all, By default, the heatmap function gives an image with a dendrogram added to the left side and to the top. Is it possible to only add the dendrogram to the left side and let the order of the columns unchanged ? I tried heatmap(mat, col=rbg,Rowv=res.hclust$order,Colv=1:dim(mat)[[2]]). In this case, the order of the columns are unchanged but a dendrogram is added to the top. How can I

Hello! I have data containing a large number of probabilities (about 60) of nonzero coefficients to predict 10 different independent variables (in 10 different BMA models). i've arranged these probabilities in a matrix like so: (IV1) (IV2) (IV3) ... p(b0) p(b0) p(b0) p(b1) p(b1) p(b1) p(b2) p(b2) p(b2) ... where p(b1) for independent variable 1 is p(b1 !=

Hello, I have two questions. I'd like to visualize data with a heatmap and I have the following testcase: x <- rnorm(256) nx <- x + abs(min(x)) nnx <- 255/max(nx) * nx x <- matrix(nnx, 16, 16) rownames(x) <-

I'm trying to display the probability space of a function and wanted to see specifically where the maximum posterior probability is. data=read.table("PosteriorData",header=F) mat=as.matrix(data) heatmap.2(mat/max(mat,na.rm=T),dendrogram=c("none"),trace=c("none"), Rowv=F,Colv=F,labRow=3*c(10:-10),labCol=3*c(-10:10),symm=T,col=rainbow(100)) As the

Hi, I'm trying to save heatmaps as PDFs. However, the PDF version of the heatmaps (Heatmap_CAFvsTNF_run2.pdf) is blurred when compared to its counterpart, which was saved manually by using the software "Grab" (Heatmap_CAFvsTNF_run2.tiff). -----R code-------- sample_output <- "stroma_run2" filename <-

I would like to use gridBase to place four separate heatmaps (actually, a stripped-down heatmap.2 from ght gregmisc package that contains only the "image" part) into four different viewports. I can get the placement correct, but I keep 'losing' the previous plot. Any suggestions? Here is some quick example code trying to put a heatmap into the left viewport and then

Dear list members, I have been using R to create a heatmap where my data has continous variables from 0 to 100. When I create the heatmap, although the branches are correct, they do not order themselves so that the row with the most zeros is at one end and the row with the most 100s is at the other, which is what I would like them to do, so as to create a colour gradient down the graphic. I have

Dear list, I am using heatmap.2(x) to draw a heatmap. Ideally, I want to the matrix x clustered only by columns and keep the original order of rows unchanged. Is there a way to do that in heatmap.2()? Thanks a lot! Any suggestions will be appreciated! Best, Allen [[alternative HTML version deleted]]

I have used heatmap to visualize my microarray data. I have a matrix of M-values. I do the following. #The distance between the columns. sampdist <- dist(t(matrix[,]), method="euclidean") sclus <- hclust(sampdist, method="average") #The distance between the rows. genedist <- dist(matrix[,], method="euclidean") gclus <- hclust(genedist,

Hello! I looked for help through google and the help-files and spend several hours with trial and error, but didn't find a correct way. It's all about lines in a heatmap to separate different data block from each other to underline the significance of the found clusters! The heatmap is build like that: heatmap(X, Rowv=NA, Colv=NA, symm=TRUE, cexRow=0.3, cexCol=0.3) I switched the