Displaying 20 results from an estimated 20000 matches similar to: "documentation mistake"
2016 Mar 04
0
R 3.2.4 rc issue
Thanks for the info, Dirk.
The tarball builds don't run make check (because of a policy decision that it is better to have the sources available on all platforms for testing than to have none if it breaks on a single platform). However the build as of tonight has no problem with make check on the build machine. Did you by any chance forget that Matrix is a recommended package and expected to
2016 Mar 04
2
R 3.2.4 rc issue
I generally run 'make; make check' (with more settings) when building the
Debian package. Running 3.2.4 rc from last night, I see a lot of package
loading issues during 'make check'. Here is splines as one examples:
checking package 'splines'
* using log directory '/build/r-base-3.2.3.20160303/tests/splines.Rcheck'
* using R version 3.2.4 RC (2016-03-02 r70270)
*
2016 Mar 04
1
R 3.2.4 rc issue
On 4 March 2016 at 09:11, peter dalgaard wrote:
| Thanks for the info, Dirk.
|
| The tarball builds don't run make check (because of a policy decision that it is better to have the sources available on all platforms for testing than to have none if it breaks on a single platform). However the build as of tonight has no problem with make check on the build machine. Did you by any chance forget
2011 Mar 28
2
mgcv gam predict problem
Hello
I'm using function gam from package mgcv to fit splines. ?When I try
to make a prediction slightly beyond the original 'x' range, I get
this error:
> A = runif(50,1,149)
> B = sqrt(A) + rnorm(50)
> range(A)
[1] 3.289136 145.342961
>
>
> fit1 = gam(B ~ s(A, bs="ps"), outer.ok=TRUE)
> predict(fit1, newdata=data.frame(A=149.9), outer.ok=TRUE)
Error
2006 Dec 13
2
caching frequently used values
Hi,
I am trying to find an elegant way to compute and store some
frequently used matrices "on demand". The Matrix package already uses
something like this for storing decompositions, but I don't know how
to do it.
The actual context is the following:
A list has information about a basis of a B-spline space (nodes,
order) and gridpoints at which the basis functions would be
2008 Jul 29
1
tensor product of equi-spaced B-splines in the unit square
Dear all,
I need to compute tensor product of B-spline defined over equi-spaced
break-points.
I wrote my own program (it works in a 2-dimensional setting)
library(splines)
# set the break-points
Knots = seq(-1,1,length=10)
# number of splines
M = (length(Knots)-4)^2
# short cut to splineDesign function
bspline = function(x) splineDesign(Knots,x,outer.ok = T)
# bivariate tensor product of
2012 Mar 12
1
Fwd: Re[2]: B-spline/smooth.basis derivative matrices
--- On Mon, 3/12/12, aleksandr shfets <a_shfets at mail.ru> wrote:
> From: aleksandr shfets <a_shfets at mail.ru>
> Subject: Fwd: Re[2]: [R] B-spline/smooth.basis derivative matrices
> To: "Vassily Shvets" <shv736 at yahoo.com>
> Received: Monday, March 12, 2012, 5:15 PM
>
>
>
> -------- ???????????? ?????????
> --------
> ?? ????:
2005 Jun 14
0
bs() function of the splines package
Laurent 14 juin 12:02 afficher les options
De : "Laurent" <eddy_l... at hotmail.com> - Rechercher les messages de cet
auteur
Date : Tue, 14 Jun 2005 03:02:37 -0700
Local : Mar 14 juin 2005 12:02
Objet : bs() function of the splines package
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2012 Aug 02
2
Rd] Numerics behind splineDesign
On 08/02/2012 05:00 AM, r-devel-request at r-project.org wrote:
> Now I just have to grovel over the R code in ns() and bs() to figure
> out how exactly they pick knots and handle boundary conditions, plus
> there is some code that I don't understand in ns() that uses qr() to
> postprocess the output from spline.des. I assume this is involved
> somehow in imposing the boundary
2005 Jun 14
0
bs() function of the splines package with intercept=FALSE
Hello,
I'm implementing a function using non uniform B-Splines. Looking at the
code of the bs() function, I realized that if the intercept was set to
FALSE, the behavior of the function was the following (df is the number
of degrees of freedom that I believe can be interpreted as the number
of control points):
- Compute df- ord + 1 _internal_ knots (ord is the order of the spline)
- Add ord
2006 Nov 15
1
splineDesign and not-a-knot conditions
Hi,
I would like to fit an (interpolating) spline to data where the
derivatives at the endpoints of the interval are nonzero, thus the
natural spline endpoint-specification does not make sense. Books (de
Boor, etc) suggest that in this case I use not-a-knot splines.
I know what not-a-knot splines are (so if I were solving for the
coefficients directly I knew how to do this), but I don't
2010 Jun 11
1
Documentation of B-spline function
Goodmorning,
This is a documentation related question about the B-spline function in R.
In the help file it is stated that:
"df degrees of freedom; one can specify df rather than knots; bs() then chooses df-degree-1 knots at suitable quantiles of x (which will ignore missing values)."
So if one were to specify a spline with 6 degrees of freedom (and no intercept) then a basis
2002 May 02
1
splines
I've got a problem with the R function spline.des.
I use the following arguments:
x_seq(0,1,length=200)
knot_quantile(x,(1:8)/9)
ord_3
k_sort(c(rep(range(x),ord,knot)))
derivs_rep(2,200)
When I do spline.des(k,x,ord,derivs)$design on Splus and on R, I don't
have the same results.
However, if I take an order ord=4 (ie a spline of degree 3), then, I
have the same
2010 Apr 19
0
Natural cubic splines produced by smooth.Pspline and predict function in the package "pspline"
Hello,
I am using R and the smooth.Pspline function in the pspline package to
smooth some data by using natural cubic splines. After fitting a
sufficiently smooth spline using the following call:
(ps=smooth.Pspline(x,y,norder=2,spar=0.8,method=1)
[the values of x are age in years from 1 to 100]
I tried to check that R in fact had fitted a natural cubic spline by
checking that the resulting
2007 Dec 07
1
Make natural splines constant outside boundary
Hi,
I'm using natural cubic splines from splines::ns() in survival
regression (regressing inter-arrival times of patients to a queue on
queue size). The queue size fluctuates between 3600 and 3900.
I would like to be able to run predict.survreg() for sizes <3600 and
>3900 by assuming that the rate for <3600 is the same as for 3600 and
that for >4000 it's the same as for
2009 Sep 30
1
rcs fits in design package
Hi all,
I have a vector of proportions (post_op_prw) such that
>summary(amb$post_op_prw)
Min. 1st Qu. Median Mean 3rd Qu. Max. NA's
0.0000 0.0000 0.0000 0.3985 0.9134 0.9962 1.0000
> summary(cut2(amb$post_op_prw,0.0001))
[0.0000,0.0001) [0.0001,0.9962] NA's
1904 1672 1
2013 Feb 27
1
Finding the knots in a smoothing spline using nknots
Hi r-helpers.
Please forgive my ignorance, but I would like to plot a smoothing spline
(smooth.spline) from package "stats", and show the knots in the plot, and I
can't seem to figure out where smooth.spline has located the knots (when I
use nknots). Unfortunately, I don't know a lot about splines, but I know
that they provide me an easy way to estimate the location of local
2024 Jul 16
2
Automatic Knot selection in Piecewise linear splines
>>>>> Anupam Tyagi
>>>>> on Tue, 9 Jul 2024 16:16:43 +0530 writes:
> How can I do automatic knot selection while fitting piecewise linear
> splines to two variables x and y? Which package to use to do it simply? I
> also want to visualize the splines (and the scatter plot) with a graph.
> Anupam
NB: linear splines, i.e. piecewise
2024 Jul 26
1
Automatic Knot selection in Piecewise linear splines
dear all,
I apologize for my delay in replying you. Here my contribution, maybe
just for completeness:
Similar to "earth", "segmented" also fits piecewise linear relationships
with the number of breakpoints being selected by the AIC or BIC
(recommended).
#code (example and code from Martin Maechler previous email)
library(segmented)
o<-selgmented(y, ~x, Kmax=20,
2005 Jul 24
1
Buglet in src/appl/splines.c (PR#8030)
--AZaLVt6Pw+
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Dear all,
I was looking at "splinefun" and the underlying C code and believe
that there is a memory access error in the C routine "spline_eval".
Specifically, on line 368 and following the following code appears:
if(ul < x[i] || x[i+1] < ul)