similar to: Order of boxes in boxplot()

Quite a simple one really! When I run boxplot(), the labels on the X axis are horizontal, and I want them vertical. So I did: par(las=3) boxplot(...) And my labels just aren't there anymore.... Any help???

Hi All I am having 2 very long character strings (550chars) and I want to put them as expressions together with c(). The problem is that I also get these double-quotes, as seen below in 'fct'. How can I remove these double-quotes? I tried as.name() but it did not work (because of size?). These are creating trouble with subsequent programs, which I tested with strings that for some

I subscribed to this list for about two months before I began posting, so I've got a buttload of email to sift through ... I'm doing this BEFORE I flood the list with my inane questions ... But here goes: I read a reply from one guy to another about recording. The message included this context from extensions.conf: [recordings] exten => 500,1,Festival('Please record your

Dear R-Representative: I am very new to R and I have to admit that I am not the cleverest of users. So, please bear with me. I have installed R on my Mac OS 8.6. I am interested in eventually using the packages -- many useful ones have been downloaded with the basic R software. I have looked through some of the manuals, however, I have not yet found how to access the commands in these packages.

I had added a vignette to the coxme package and all worked well locally, but it failed at CRAN.???? The issue is that the vignette involves using coxme for pedigree data, it doesn't work without the kinship2 package, and I hadn't put in the necessary "if (require(...." logic. The question is, how do I make the entire vignette conditional? If the package isn't available,

Hi Thanks once again for your help, I do appreciate it..... however.... Here is what I get with your test.... (under tcsh - i normally use bash, but I will keep everything the same) users/mwatson> env http_proxy=http://wwwcache.bbsrc.ac.uk:8080/ R >options(internet.info=0) >update.packages() trying URL `http://cran.r-project.org/src/contrib/PACKAGES' unable to connect to

Hello everyone, I want to transform a data.frame into an array (lets call it mydata), where: mydata[[1]] is the first imputed dataset...and for each mydata[[d]], the first p columns are covariates X, and the last one is the outcome Y. Lets assume a simple data.frame: Imputed = data.frame( X1 = c(1,2,1,2,1,2,1,2, 1,2,1,2,1,2,1,2), X2 =

Hi When I use plot(hclust(dist..)...)...) etc to create a dendrogram of a hierarchial cluster analysis, I end up with a vertical tree. What do I need to do to get a horizontal tree? Also, my users are used to seeing trees who's leaves all "end" at the same place (eg. Like in minitab). Is this possible in R? Thanks Mick Michael Watson Head of Informatics Institute for Animal

Hi I did a google search on this and came up with nothing. OK, in the latest release of R for windows, I want to change the gui to SDI mode. Edit -> GUI preferences Choose SDI Apply I get the message about properties not being able to be changed on a running console, and that I need to save. So I click Save, and am met with a "Save As" dialogue box with the default file called

This is one of those instances where a less superficial knowledge of R's technical details comes in really handy. What you need to do is convert the data frame to a single (numeric) vector for, e.g. a matrix() call. This can be easily done by noting that a data frame is also a list and using do.call(): ## imp is the data frame: do.call(c,imp) X11 X12 X13 X14 X15 X16 X17 X18 X19

Hi Forgive my ignorance. I am selecting a column of a data.frame using the column name, and I want to know what the resulting column "is". My data frame is called "submin" and the column name is held in a variable called "display.gname" Eg: > is.data.frame(submin) [1] TRUE > is.data.frame(submin[,display.gname]) [1] FALSE >

Hi When I give the command: > heatmap.2(as.matrix(d),Rowv=as.dendrogram(hc.gene),Colv=FALSE,scale="row ",trace="none",col=greenred.colors(79)) The resulting heatmap has re-ordered my columns! This is time-course data, and I don't want my columns re-ordered! Note from the help: Rowv: determines if and how the _row_ dendrogram should be reordered.

Hi Sorry to ask such a basic question. I have a list, each element of which is a vector of two values. What I actually want is a matrix with two columns, and one row per element of the list. Obviously I have tried as.matrix(), and as.vector() but I didn't expect the latter to work. I feel so lame asking this. Any suggestions? Mick

OK, I really am struggling with this one! Forgive me if I am being stupid.... I am running R 1.7.1 on Suse Linux 8.1. I connect to the internet through a proxy so I have: IAHC-LINUX03:~ # echo $http_proxy wwwcache.bbsrc.ac.uk:8080 IAHC-LINUX03:~ # echo $HTTP_PROXY wwwcache.bbsrc.ac.uk:8080 just in case ;-) SO, i go into R and I get: >

Hi I have data from 12 subjects. The measurement is log(expression) of a particular gene and can be assumed to be normally distributed. The 12 subjects are divided into the following groups: Infected, Vaccinated, Lesions - 3 measurements Infected, Vaccintaed, No Lesions - 2 measurements Infected, Not Vaccinated, Lesions - 4 measurements Uninfected, Not Vaccinated, No Lesions - 3 measurements

> From: "Kevin Bartz" <kbartz at loyaltymatrix.com> > Date: Thu, 1 Jul 2004 10:18:36 -0700 > > Dr. Ripley, you are the master. That fix worked like a charm! All the way to > 50, with no problems. Thanks again, > And all while I was asleep! I'll submit a corrected maps package in a couple of weeks, when I return from China (no guaranteed connection where

OK, dumb question, and it is probably in the docs somewhere, but after 12 months working with R and quite a while looking at the docs, I still don't know (or have forgotten) how to replace all NA values in a matrix at once with some other value. I can do it column by column using is.na(), but I can't figure out how to do it for the whole matrix. My apologies, I am ashamed ;-) Michael

I think that title makes sense... I hope it does... I have a data frame, one of the columns of which is a factor. I want the rows of data that correspond to the level in that factor which occurs the most times. I can get a list by doing: by(data,data$pattern,subset) And go through each element of the list counting the rows, to find the maximum.... BUT I can't help thinking there's

I just ran a test of icecast to see how much cpu it uses. I set 500 instances of wget downloading from the mount point over loopback, and the cpu usage of the server was still barely reaching 0.3% on a 1.4G machine. The total bandwidth was 15Mbit/s. Each stream was 64 kbit/s. (I think some of the downloads weren't running fully - 15M/64k=240). I haven't tested over ethernet yet. What I

I've been searching for a solution to this problem for a few hours now, but google searches are coming up empty. I have 3 Linux boxes all running Suse 9.1 and samba 3.0.2a. The 3 systems are: Novi - the samba server Newberry - mounting novi Sagola - mounting novi This work great, until "mount -a" is run. Each time mount -a is run, we get another mount of novi. When I type