similar to: looking for a plot function

Dear useRs, Given this code I end up with a list of class "by": a <- sample(1:5,200,replace=TRUE) b <- sample(c("v1","v2","v3"),200,replace=TRUE) c <- sample(c(11,22,33),200,replace=TRUE) data <- runif(200) grouped <- by(data,list(a,b,c),function(x) {c(min=min(x),max=max(x), median=round(median(x),digits=2),mean=round(mean(x),digits=2))})

Dear R users, I'm interested in a combination of a scatterplot and an image graph. I have two large vectors. Because in the scatterplot some areas are sparsely and others densely populated, I want to see the points, and I also want their color to be changed based on their density (similar to a heat map). Is there a function that can do that? Thank you, b.

Dear useRs, I have a function that creates several global objects with assign("obj",obj,.GlobalEnv), and which I need to run iteratively in another function. The code is similar to f <- function(...) { assign("obj",obj,.GlobalEnv) } fct <- function(...) { for (i in 1:1000) { ... f(...) ...obj... rm(obj) #code fails without this line } } I don't understand

Dear R users, I have a column with dates (character) in a data frame: 12-Jan-01 11-Jan-01 10-Jan-01 9-Jan-01 8-Jan-01 5-Jan-01 and I need to convert them to (Julian) dates so that I can sort the whole data frame by date. I thought it would be very simple, but after checking the documentation and the list I still don't have something that works. 1. as.Date returns the error below. What am I

Dear R users, I have a function (below) which encompasses several tests. However, when I run it, only the output of the last test is displayed. How can I ensure that the function root(var) will run and display the output from all tests, and not just the last one? Thank you, b. root <- function(var) { #---Phillips-Perron PP.test(var, lshort = TRUE) PP.test(var, lshort = FALSE)

Dear R users, This is a KDE beginner's question. I have this distribution: > length(cap) [1] 200 > summary(cap) Min. 1st Qu. Median Mean 3rd Qu. Max. 459.9 802.3 991.6 1066.0 1242.0 2382.0 I need to compute the sum of the values times their probability of occurence. The graph is fine, den <- density(cap, from=min(cap), to=max(cap), give.Rkern=F)

Dear useRs, How come the first attempt to sort a POSIXt vector fails (Error: non-atomic type in greater), while the second succeeds? (Code inserted below.) The documentation says that POSIXt is used to allow operations such as subtraction, so I'd expect sorting to work. Is this perhaps an OS issue? (I run R 2.0.1 on Win xp.) Thank you, b. #------------code test <- c("2005-02-08

Hello, Please forget me if I am asking something that is well documented. I have read documentation but there are points that are not clear for me. I am not expert in R nor Databases, but if someone direct me to a tutorial, I will appreciate it.. 1. In my understanding, I can install and use RMySQL withouth having to install MySQL in my PC, to have access to and to create new tables . Is this

Dear useRs, I timed the same code (simulation with for loops) on the same box (dual Xeon EM64T, 1.5 Gb RAM) under 3 OSs and was surprised by the results: Windows XP Pro (32-bit): Time difference of 5.966667 mins 64-bit GNU/Linux (Fedora Core 4): Time difference of 6.966667 mins 32-bit GNU/Linux (FC4): Time difference of 9.2 mins (R 2.1.0 binaries downloaded from CRAN) I searched the

Hi, I encountered a booting problem with memdisk 2.83, USB and IBM Thinkpad T61, apparently the same issue as described here: http://syslinux.zytor.com/archives/2008-April/009850.html The boot process always stops after "Loading boot sector... booting...". With debug tracers enabled, the last few output lines are: Loading boot sector... FR<p>Dbooting...

Dear R community, I tried to optimized my R code by using Rprof. In my R code I'm using MySQL database connections intensively. After a bunch of queries R fails with the following error message: Error in .Call("RS_MySQL_newConnection", drvId, con.params, groups, PACKAGE = .MySQLPkgName) : RS-DBI driver: (could not connect mylogin@mydatabase on dbname "myDB"

Classification: UNCLASSIFIED Caveats: NONE Thanks for your quick response. The program you mentioned below available from R is based on number of runs (up or down) not based on a longest length of runs of same events. To be more specific, for example, from a series, HHTHTTTTHHH, the number of runs are 5, and the longest length of runs of the same events is 4. I'll check for the website you

Full_Name: Glenn Stone Version: 1.5.1 and 1.6.0 OS: win2000 Submission from: (NULL) (168.140.227.9) The following code produces incorrect fitted values in version 1.5.1 and an error in 1.6.0 Error in "contrasts<-"(*tmp*, value = "contr.treatment") : contrasts apply only to factors In addition: Warning message: variable ihalf is not a factor in:

Dear R users, I need to rename the columns of a series of data frames. The names of the data frames and those of the columns need to be pulled from some vectors. I tried a couple of things but only got errors. What am I missing? #---create data frame dframes <- c("a","b","c") assign(dframes[2],data.frame(11:20,21:30)) #---rename the columns cols <-

A loose idea for *post*-0.50 development I've been giving a some (but not all that many) thoughts to whether some of the conceptual difficulties facing newcomers could be avoided by having simplified functions for common operations. We already have parts of this, e.g. in Kurts ctest routines. Specifically, I was thinking about data frames: How about

Dear R users, I have a data frame which I create with read.csv and then order by date: d <- na.omit(read.csv(...)) d <- d[order(as.Date(as.character(d$Date), format="%d-%b-%y"), decreasing=F, na.last=F),] My problem is that even though the data frame is ordered as requested, the old row numbers are preserved. For example: * Before sorting: > d[1:3,] Date Amt 1

dear professor: thank you for your help,witn your help i develop the nomogram successfully. after that i want to do the internal validation to the model.i ues the bootpred to do it,and then i encounter problem again,just like that.(´íÎóÓÚerror to :complete.cases(x, y, wt) : ²»ÊÇËùÓеIJÎÊý¶¼Ò»Ñù³¤(the length of the augment was different)) i hope you tell me where is the mistake,and maybe i have

Dear useRs, I want to simulate a time series (stationary; the distribution of values is skewed to the right; quite a few ARMA absolute standardized residuals above 2 - about 8% of them). Is this the right way to do it? #-------------------------------- load("rdtb") #the time series > summary(rdtb) Min. 1st Qu. Median Mean 3rd Qu. Max. -1.11800 -0.65010 -0.09091

Hi R-users, I have a simple question for R heavy users. If I have a data frame like this dfr <- data.frame(id=1:16, categ=rep(LETTERS[1:4], 4), var3=c(8,7,6,6,5,4,5,4,3,4,3,2,3,2,1,1)) dfr <- dfr[order(dfr$categ),] and I want to score values or points in variable named "var3" following this kind of logic: 1. the highest value of var3 within category (variable named

Dear useRs, When I use coplot() and output to png/jpeg/bmp, the grid lines from the scatter plots disappear. If I output to pdf() the grid lines are there, however I can't use it - I have many points, and the resulting PDF file is large and very slow to open and scroll through. (By the way, if I click File-Save As-png/jpeg/bmp from Rgui.exe, the grid lines are preserved - but I need to use