similar to: help! a urgent question

I wish to perform brain surgery this afternoon at 4pm and don't know where to start. My background is the history of great statistician sports legends but I am willing to learn. I know there are courses and numerous books on brain surgery but I don't have the time for those. Please direct me to the appropriate HowTos, and be on standby for solving any problem I may encounter while

Hi, I have an array of 2d node locations and an array triangles, and would like to plot something like a image or persp. An example of doing it with rgl is: library(ncdf) library(rgl) # wget http://www.maplepark.com/~drf5n/extras/teapot.nc teapot<-open.ncdf("teapot.nc") z<-get.var.ncdf(teapot,"tris") l<-get.var.ncdf(teapot,"locations")

Hi, I'd like to partition a 2d probability density function into regions of equal probability. It is straightforward in the 1d case, like qnorm(seq(0,1,length=5)) but for 2d I'd need more constraints. Any suggestions for how to approach this? Is seems like a spatial sampling problem but I'm not sure where to look. Thanks for your time, Dave -- Dr. David Forrest drf at

Hello all, It seems that the next improvement to the R Graph Gallery is categorization of the graphics, that way each graph will be easier to find. That step should be done *carefully* if we want to avoid the opposite side-effect : graph not reachable through the categories. That's why the wisdom of the R community is required. Graphics will be classified in : - categories -

The following code produces an eps file with the tops of each of the ylabs clipped off. par(mfrow=c(2,2)) plot(runif(10), ylab="Function(Lengthy Expression)",xlab="Prediction") plot(runif(10), ylab=expression(Delta * Beta^2),xlab="Prediction") plot(runif(10), ylab="Function(Lengthy Expression)",xlab="Prediction")

My friend Veslot proposed me the Raven ! http://www.teteamodeler.com/allopass/images/corbeau.jpg As a matter of fact the intelligence of this bird is comparable to one of a monkey, although its brain is close to a reptile brain. R is quite the same : small, compact, but so clever. This is a canadian website explaining (in french) the R-aven intelligence

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I have a problem when using nnet to predict the negative values. For example : X = matrix(c(1,1,0,0,1,0,1,0),4,2) X Y = matrix(c(0,1,1,0)) - 0.5 # XOR - 0.5 Y nn = nnet(X,Y,size=3) val = predict(nn,X) val # this is expected to be close to Y, but it's not ! The 'val' is always positive. I tried to change the options, but the result isn't much better. Could someone give me an

Hi, I failed to search for R package providing random number generator of "Park and Miller". Anyone know any R package supporting this kind of function? Thanks, Grace -- View this message in context: http://www.nabble.com/Random-Number-Generator-of-Park-and-Miller-tf3636501.html#a10154554 Sent from the R help mailing list archive at Nabble.com.

even for people who didn't like the outcome of the US elections this year, it must have been a joy to see all the nice (and not so nice) graphs that were shown. As an exercise, I recreated the map shown on the NY-Times website [ http://www.nytimes.com/packages/khtml/2004/11/03/politics/ 20041103_px_ELECT_GRAPHIC.html ] If you're interested,

Hi, According to help(sub), the ^ should match the zero-length string at the beginning of a string: sub('^','var',1:3) # "1" "2" "3" sub('$','var',1:3) # "1var" "2var" "3var" # This generates what I expected from the first case: sub('^.','var',11:13) # "var1" "var2"

Is there an element-by-element multiplication in R, like the .* operator in Matlab? eg: A (2x3) B (2x3) C=A.*B C (2x3) C = [[a11*b11 a12*b12 a13*b13]; [a21*b21 a22*b22 a23*b23]] I can't find one... Thanks -Mike Gates

Hi All, I am new to post question on this list. I apologize if this question is too easy or irrelevant. I am doing a simulation study and I need to read a data file that can be easily read by SAS. So, what I try to do is to execute SAS in R and then read the output of SAS to R. I try the following code but it didn't work. system("c:\\program files\\sas institute\\v8\\sas.exe

Hello, I don't know if the result of acos(0.5) == pi/3 is a bug or not. It looks strange to me. Inaki Murillo

Hi: I am doing some work that involves plotting points of interest superimposed on photographs and maps. I can produce the plots fine in R, but so far I have had to do the superimposition externally, which makes it tedious to do exploratory work. I have looked to see if there is some capability to put a background picture on a plot window, but I have not found anything. Advice, anyone? Cheers

Within an R dataset, I have a date field called “date_”. (The dates are in the format “YYYY-MM-DD”, e.g. “1995-12-01”.) How can I add or subtract “1 month” from this date, to get “1996-01-01” or “ “1995-11-01”. --------------------------------- [[alternative HTML version deleted]]

>>>>> "David" == David Forrest <drf5n@maplepark.com> >>>>> on Tue, 22 Mar 2005 15:02:20 -0600 (CST) writes: David> According to help(sub), the ^ should match the David> zero-length string at the beginning of a string: yes, indeed. David> sub('^','var',1:3) # "1" "2" "3"

Is there a tool for reading a graphics file into an object? I might not be looking with the correct vocabulary, but I'm finding lots of references to producing graphics from R, but not any for inputting graphics into R. I'd like to use a jpeg image and have the data available in R for analysis. I could convert the image to another format, PPM perhaps, and parse that in, GRASS seems like

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Dear R users: I have a problem about catch the value from function. I have following two functions (part): fbolus1 <- function() {......... par<-data.frame(Parameter=c("kel","Vd"),Initial=c(0)) check(par) .....} check<-function(par) { if (par[ ,2] <= 0){ cat("\nEnter again (y/n) ?\n\n") ans<-readline() if (ans == "n" ){