similar to: misleading output after ordering data frame

Hello, I'm working in adding support for 64-bit integers to my target. I'm using LLVM to decompose the 64-bit integer operations by using 32-bit registers wherever possible and emulating support where not. When looking at the bit shift decomposition I saw what seems to be a bug in the implementation. The affected function is ExpandShiftWithUnknownAmountBit in LegalizeIntegerTypes.cpp.

Hi Javier, > The problem is the implementation of the expansion. Perhaps an example > can help illustrate better. Take the case of a 64-bit integer shifted > left by say 6 bits and is decomposed using 32-bit registers. Because 6 > is less than the 32 (the register size) the resulting low part should be > equal to the source low part shifted left by 6 bits. The current >

I was trying to write a wrapper for number_to_currency to return currency in pounds. I used a helper class to do this. def number_to_pounds(amt) number_to_currency(amt, :unit => "£") end This works fine, but I am trying to understand why I can''t use a symbol to pass the values. I thought symbols were like pointers. (you now know I am a newbie). def

Hi all, I have problems in a dataframe variables types. Look: from a loop function: for(...){ ... dados.fin <- rbind(dados.fin, c(L=j, A=j^2, Nsp=nsps, N=length(amosfin$SP), AmT="am",NAm=nam, AMST=amst)) dados.fin <- rbind(dados.fin, c(L=j, A=j^2,

Dear list, This may sound silly. What is the right way to change the names of a dataframe? Let's say I have this data frame (dose) with four columns with names "ID", "DOSE", "TIME" "CMT". I want to change "DOSE" to "AMT". So I did names(dose[2])<-'AMT' But nothing happened. The name of the second column is still

On Dec 16, 2008, at 7:57 PM, Eli Friedman wrote: > On Tue, Dec 16, 2008 at 3:36 PM, Daniel M Gessel <gessel at apple.com> > wrote: >> I'm working on a Target that only uses the 5 lsbs of the shift >> amount. > > Okay, that's quite common... x86 is the same. > Thanks - yes, I'd heard rumors that x86 operates the same way. >> I only have 32

I buy flowers at a local market on a fairly regular basis. The flower vendors post their prices and if I want to buy only one or two flowers I will generally get the posted price. From time to time I want to buy large quantities of flowers, and sometimes a vendor will give me a better price than their posted price for the bulk order, but more often I have to offer them a higher price than the

See the bug for a reduction and the gimple trees. validate_arglist definately is rejecting the arglist in EmitBuiltinAlloca. (try: bool TreeToLLVM::EmitBuiltinAlloca(tree exp, Value *&Result) { tree arglist = TREE_OPERAND(exp, 1); if (!validate_arglist(arglist, INTEGER_TYPE, VOID_TYPE)) { debug_tree(arglist); return false; } Value *Amt = Emit(TREE_VALUE(arglist), 0); Amt =

Hi Duncan, I don't know if the optimization would help us much. Our architecture performs integer shifts and subtractions at the same speed. I think the optimization is limited to the case where NVBits is a power of two. That is the case for all current value types but there's a separate thread where someone is proposing adding i20 as a native type. In your previous email you mentioned

Dear useRs, I have a function that creates several global objects with assign("obj",obj,.GlobalEnv), and which I need to run iteratively in another function. The code is similar to f <- function(...) { assign("obj",obj,.GlobalEnv) } fct <- function(...) { for (i in 1:1000) { ... f(...) ...obj... rm(obj) #code fails without this line } } I don't understand

On Tue, Dec 16, 2008 at 5:20 PM, Daniel M Gessel <gessel at apple.com> wrote: > The problem here is that it looks like LLVM is introducing an expansion that > assumes 32 bit shifts use more than 5 bits of the shift value. > I created a simple test function: > u64 mebbe_shift( u64 x, int test ) > { > if( test ) > x <<= 2; > return x; > } > I compile using

Hi, i have the following data.frame : > Data[1:3,] dt amt geoTree merTree ref 1 0.71002484 3.334570 A2b B2b 0 2 0.49074936 2.544464 A2b B1a 0 3 0.06223433 3.617133 A1b B2a 0 i want to convert it to a list, like this: list(Data[1,],Data[2,],Data[3,]) [[1]] dt amt geoTree merTree ref 1 0.07333459 0.969585 A2a

Hey all; I'm a beginner++ user of R, trying to use it to do some processing of data sets of over 1M rows, and running into a snafu. imagine that my input is a huge table of transactions, each linked to a specif user id. as I run through the transactions, I need to update a separate table for the users, but I am finding that the traditional ways of doing a table lookup are way too slow to

Hi all, building current llvm-gcc-4.0 TOT(Revision: 42128) with current llvm (Revision: 42128) on 8.10.1 Darwin (x86) fails with the following message. Is that a just a temporary inconsistency or should i file a bug? /Users/arnold/Desktop/testing/vanilla-gcc-4.0/obj/gcc/xgcc -B/Users/ arnold/Desktop/testing/vanilla-gcc-4.0/obj/gcc/ -B/Users/arnold/

PS: For a small optimization, in the case where Amt is bigger than 32 (or whatever NVTBits is) you might want to use an "and" to mask off the top bits of Amt rather than subtracting 32 (if Amt is 64 or greater then the result of the shift was undefined anyway, so it is ok to mask off all the upper bits).

I have a model with quant vars only and the error message does not make sense: (mod1 <- coxph(Surv(time=strt,time2=stp,event=(resp==1))~ +incpost+I(amt/1e5)+rate+strata(termfac), subset=dt<"2010-08-30", data=inc,method="efron")) Call: coxph(formula = Surv(time = strt, time2 = stp, event = (resp == 1)) ~ +incpost + I(amt/1e+05) + rate + strata(termfac),

Dear useRs, I have a data frame and I want to plot all rows. Each row is represented as a line that links the values in each column. The plot looks like this: dfr <- data.frame(A=sample(1:50,10),B=sample(1:50,10), C=sample(1:50,10),D=sample(1:50,10)) xa <- 10*1:4 plot(c(10,40),c(0,50)) for (i in 1:nrow(dfr)) { lines(xa,dfr[i,],pch=20,type="o") } Things get more complicated

Dear all: I have been thinking to import below one data file (.txt)into R by read.table(..,skip=1, header=T). But How can I deal with the repeated rows of TABLE NO.1 and names of data variables in the middle of this data file. The similar block will be repeated 100 times, here only show 4 of them and within each block, data records also can vary, here only paste 4 rows for example. I appreciate

Dear all: I have been thinking to import below one data file (.txt)into R by read.table(..,skip=1, header=T). But How can I deal with the repeated rows of TABLE NO.1 and names of data variables in the middle of this data file. The similar block will be repeated 100 times, here only show 4 of them and within each block, data records also can vary, here only paste 4 rows for example. I appreciate

Dear R users, I'm interested in a combination of a scatterplot and an image graph. I have two large vectors. Because in the scatterplot some areas are sparsely and others densely populated, I want to see the points, and I also want their color to be changed based on their density (similar to a heat map). Is there a function that can do that? Thank you, b.