Displaying 20 results from an estimated 200 matches similar to: "Question about plot.mona {cluster}"
2005 Jan 27
2
cluster, mona error
Hi
I have a problem using the package cluster on my binary data. I want to
try mona at first. But i get the an error.
hc<-read.table("all.txt", header=TRUE, sep="\t", row.names=1)
srt(hc)
`data.frame': 51 obs. of 59 variables:
$ G1p : int 2 1 1 1 1 1 1 1 1 1 ...
$ G1q : int 1 1 1 1 1 1 1 1 1 1 ...
$ G2p : int 1 1 1 1 1 1 1 1 1 1 ...
$ G2q : int 1 1 1 1 1 1
2008 Mar 24
7
FYI about my Mona Vie business venture
Asterisk work does not pay all of my bills, so I have joined up with a company that has a very good payment plan.
I have recently become a Mona Vie Independent Distributor.
I am not going to go into a sales pitch.
This is just an FYI to this opportunity.
The company has grown into a Billion dollar company in just 2 years.
This company's compensation plan is the best and quickest that I have
2007 Mar 31
0
Amazing art work - Paint Mona Lisa on MS Pint
How to Paint Mona Lisa with MS Paint
<http://arts-artists.blogspot.com/2007/03/how-to-paint-mona-lisa-with-ms-paint.html>
Amazing
Art work<http://arts-artists.blogspot.com/2007/03/how-to-paint-mona-lisa-with-ms-paint.html>
http://arts-artists.blogspot.com/2007/03/how-to-paint-mona-lisa-with-ms-paint.html
--~--~---------~--~----~------------~-------~--~----~
You received this message
2003 May 21
1
cluster- binary data.
Hi!
I am trying to calculate a dissimilarity matrix using daisy.
The matrix vectver is binary as i test with:
> levels(as.factor(vectver))
[1] "0" "1"
But the call to daisy gives me the following error message.:
> dfl1 <- daisy(vectver, type = list(asymm = c(1:length(vectver[,1]))))
Error in daisy(vectver, type = list(asymm = c(1:length(vectver[, 1])))) :
at least
2009 Nov 10
0
Plotting Mona clustering result
Hi all,
Is there a way of plotting a 'decision tree' from the results of Mona in the cluster package. The default bannerplot is not quite what I'm after - I would like a plot of the binary decision tree.
Thanks
Zoƫ
[[alternative HTML version deleted]]
2010 Oct 18
1
make error for R 2.13.0 (and 2.12.0)
Regarding Tengfei Yin's post about an error trying to install
"cluster" in 2.13.0, I have gotten an error with this package when
trying to install the released version of 2.12.0. Here is the output
on an Ubuntu Linux system:
begin installing recommended package cluster
* installing *source* package 'cluster' ...
** libs
make[3]: Entering directory
2007 Mar 08
1
Tracking when an object/function was modified
Dear R-users,
If I would like to track the date when an R-object (specifically an R-
function) was modified, how can I achieve that? Furthermore, how can I
sort these objects based on date modified?
Your help is greatly appreciated
All the best
Mona
--
*****************************************************
*Dr. Mona Kanaan *
*Department of Epidemiology
2011 Sep 22
3
How make a x,y dataset from a formula based entry
Hello all,
So I am using the (formula entry) method for randomForests:
randomForest(y~x1+x2+...+x39+x40,data=xxx,...) but the issue is that some of
the items in that package dont take a formula entry - you have to explicitly
state the y and x vector:
randomForest(x=xxx[,c('x1','x2',...,'x40')],y=xxx[,'y'],...)
Now my question is whether there is a function/way
2008 Mar 26
2
ggplot2 argument handling odd
Hello there,
I'm trying to do lots of plots in one for-loop. But somehow ggplot does
not evaluate arguments as expected. Here is an example:
library(lattice)
library(ggplot2)
pl <- list()
pl2 <- list()
cDat <- as.data.frame(cbind(x1=0:100,x2=0:10,x3=1:20))
for(obs in c("x1", "x2")) {
pl[[obs]] <- xyplot(cDat[,obs] ~ cDat[,"x3"], main=obs)
2008 Dec 23
2
beginner data.frame question
I need some help understanding how on of the example data sets is
formatted in the basic R installation. If I load the Mona Loa CO2
data, with the command:
> data(co2)
I can view the data with:
> co2
And the data are in the form of 11 rows labeled as years (1994-2004)
and 12 columns labeled (Jan - Dec). This structure appears to be a
dataframe, however, if I type the command
2004 Jun 16
2
subset and lme
I'm puzzled by the following problem, which appears when
attempting to run an analysis on part of a dataset:
If I try:
csubset <- dat$Diagnosis==0
cont <- lme(fixed=cform,
random = ~1|StudyName,
data=dat,subset=csubset,na.action=na.omit)
Then I get:
Error in eval(expr, envir, enclos) : Object "csubset" not found
But if I do
2007 Mar 12
0
Tracking when an object/function was modified (Mona Kanaan)
You might find this useful.
I have modified the R 'edit' function by adding
attr(x,"date.modified") <-
substring(Sys.time(),1,19)
before the last line.
I then changed to ls() to sort functions, paste function name and time
stamp from the contents of the "date.modified" attribute before output.
Not particularly tidy but functional.
2008 Mar 24
0
FYI about my Mona Vie business venture - apology and rethink
I feel the need to apologize for my previous email to the list.
I was thinking that I was sharing something that I am currently exited with, with my associates.
I now realize that I was sooo... off-topic, it's ridiculous.
Sorry for the improper post to the list.
Feel free to keep any further comments, concerning my improper use of the list, off-list.
Thank You,
Steven B
TeamVie at
2010 Jul 21
1
Get distribution of positive/negative examples for each cluster
Dear R experts,
I have a labeled data set. Each data is assigned a binary label 0 or 1.
Assume that I use some clustering algorithm to group the data by clusters
(using some features of the data). Now I want to know how many data are
labeled as 0/1 in each cluster.
For example, assume that I have 9 labeled data grouped into three clusters.
The ids of the clusters are 1, 2, and 3. The dataset is
2012 Oct 31
3
expand.grip for permutations
if i were to have a block size of 4 people and i want to assign a treatment
combination to the entire block, there would be 16 different treatment
combinations (TTTT, TTTP, TTPP, PTTP, etc.)
i am trying to get all 16 permutations and i am able to use this code below.
drugs=c('P','T');
comb=expand.grid(drugs,drugs,drugs,drugs)
for a block size of 3 the code would be
2010 Oct 17
0
make error for R 2.13.0
Hi dear all
It's the first time for me to install a developmental version of R, I came
across following errors, my system is
DISTRIB_ID=Ubuntu
DISTRIB_RELEASE=10.04
DISTRIB_CODENAME=lucid
DISTRIB_DESCRIPTION="Ubuntu 10.04.1 LTS"
I downloaded the dev version of R in cran R source, and downloaded the
recommended packages by using wget as described in R manual, and run
2005 Jun 18
1
Fedora Core 4
I had installed R from source on Fedora Core 3. Then I upgraded
to Fedora Core 4, but left R alone. R worked fine, until I trued
to update.packages(). Even then, many packages updated just
fine, but two of them, cluster and mgcv, failed with the
following error message (using cluster as an example):
gcc -shared -L/usr/local/lib -o cluster.so clara.o daisy.o
dysta.o fanny.o meet.o mona.o pam.o
2004 Sep 24
1
Cannot build cluster_1.9,6 under R 2.0.0 beta Sep 21
Doing the normal build process [1] for a first time with a R 2.0.0 snapshot
-- the Sep 21 version I uploaded to Debian's 'experimental' section two days
ago, ended in failure. The package in question is cluster 1.9.6 which should
be 2.0.0-ready.
The (partial) log follows:
-----------------------------------------------------------------------------
[...]
g77 -mieee-fp -fPIC -g -O2
2010 Apr 19
6
comparing attitudes of 2 groups / likert scales?
Hi,
I have just found this forum, and it looks like a great place to get some
help (I hope)
For my dissertation, which is due way too soon, I am doing a survey,
comparing attitudes of 2 independent groups, with 5 scale likert questions.
Basically I want to show if they have similar or different attitudes. I am
testing 4 hypotheses, and have in total about 20 questions.
I have to say my
2011 Apr 12
1
2-parameter MLE problems
Hi all,
Sorry for the re-post, I sent my previous e-mail before it was complete. I
am trying to model seroprevalence using the differential equation: dP/dt =
beta*seronegative*.001*(seropositive)-0.35*(0.999)*(seropositive)-r*seropositive.
I would like to estimate my two parameters, beta and r, using maximum
likelihood methods. I have included my code below: