similar to: placing multiple rows in a single row

Dear R-help subscribers, I have a quite stupid question about using lapply. I have the following function: create.gradient <- function(i){ colorgrad01<-color.scale(seq(0,1,by=0.01), extremes=c("red","blue")) tree1$edge[i,1] -> x tree1$edge[i,2] -> y print(x) print(y) all2[x] -> z all2[y] -> z2 round(z, digits = 2) -> z round(z2, digits = 2) -> z2

Dear R-help subscribers; I have a question regarding making gradients in R. I've searched on the web, but was only able to find functions that make a gradient between color X and Y, which is not what I want. I want to 'pick out' individual, smaller pieces of a gradient based on a range of numbers. Say that I have a range of numbers, leading from 0 to 1. Then I want 0 to refer to

On Tue, May 3, 2016 at 12:11 AM, Nux! <nux at li.nux.ro> wrote: > ----- Original Message ----- >> From: "Akemi Yagi" <amyagi at gmail.com> >> To: "CentOS mailing list" <centos at centos.org> >> Sent: Tuesday, 3 May, 2016 01:32:55 >> Subject: Re: [CentOS] C6 Firefox 45.1 segmentation faults > >> On Mon, May 2, 2016 at 5:07

Dear listmembers, I have a little question: I have my data organized as follow sic level area a 211 2.4 b 311 2.3 b 322 0.2 b 322 0.5 c 100 3.0 c 100 1.5 c 242 1.5 d 222 0.2 where levels and sics are factors. I'm trying to obtain a matrix like this: level 211 311 322 100 242 222 sic a 2.4 0 0

Ok, managed to rebuild most the stuff; had to retire gstreamer-vaapi though. yum --enablerepo=nux-dextop-testing update Should fix the Firefox issue, let me know if it causes any problems or other requests. -- Sent from the Delta quadrant using Borg technology! Nux! www.nux.ro ----- Original Message ----- > From: "Nux!" <nux at li.nux.ro> > To: "CentOS mailing

On Tue, May 3, 2016 at 9:34 AM, <m.roth at 5-cent.us> wrote: > Akemi Yagi wrote: >> To add to your fun, let me present my wish list: >> >> mplayer-gui and libquicktime (latest version from PUIAS) and >> mlt >= 0.9.4 >> > Ummm, NO. NOT the latter, under any circumstance... or hadn't you missed > the huge announcements that Apple would no longer

Hello! I posted a feature request at lattice page on r-forge at https://r-forge.r-project.org/tracker/index.php?func=detail&aid=1127&group_id=638&atid=2570 , but I decided to duplicate it here to make sure that I understand everything correctly. I would like to slightly change the way my plot axis labels look alike based on custom extra arguments to xyplot and bwplot. Right now these

Hello! I'd like to have a function to draw correct grid while using log axis with xyplot from lattice package. Right now I have the following code inside of my panel function: lim <- current.panel.limits() v <- latticeExtra:::logTicks(2^lim$xlim, loc=1) h <- latticeExtra:::logTicks(2^lim$ylim, loc=1) panel.abline(h=log2(h), v=log2(v), col="LightGray") Is there an easy way

Hello! I?m having stacked data in a data.frame with 2 factors, ordered POSIXct, and actual value as numeric (as if for lattice::xyplot). I would like to calculate first difference using ?diff? function within corresponding subsets/partitions. Since data.frame is organized by factors and has sorted dates, it seems like "by" is a good candidate for the job. However it returns just a dumb

On Mon, May 2, 2016 at 5:07 PM, Akemi Yagi <amyagi at gmail.com> wrote: > On Mon, May 2, 2016 at 4:27 PM, Nux! <nux at li.nux.ro> wrote: > >>> What I'm intending to do is to rebuild ffmpeg from PUIAS/springdale >>> (see my earlier post). Specifically, ffmpeg-2.1.1-1.sdl6.src.rpm. It >>> requires a lot of other packages though. :-) > >>

On Wed, Apr 10, 2019 at 5:06 AM, Tomas Kalibera <tomas.kalibera at gmail.com> wrote: >> This is my first post here. I came across the very same problem. >> It can be reproduced within modified tests/Embedding/RParseEval.c > > Please check https://www.r-project.org/posting-guide.html and update > your post if you still need to get help here - from your current post >

Despite a long search on the archives, I couldn't find how to do this. Thanks in advance for what is likely a simple issue. I have a data set where the first column is name (i.e., 'Joe Smith', 'Jane Doe', etc). The following columns are data associated with that person. I have many people with multiple rows. What I want is to get a new data frame out with only the people who

Hi List, I have a problem with auth for just one user: dovecot: Sep 30 09:56:16 Info: auth(default): new auth connection: pid=3809 dovecot: Sep 30 09:56:17 Info: auth(default): client in: AUTH 1 PLAIN service=IMAP secured lip=127.0.0.1 rip=127.0.0.1 resp=AGoucnVpc0BtZXJreC12ZXJrZXJrLm5sAGJsb2VtMDEh dovecot: Sep 30 09:56:17 Info: auth(default): pam(j.ruis at

Analysis of Repeated Measurements By Dr. Ronald Geskus April 27, 2007 Amsterdam, The Netherlands http://www.can.nl/events/details.php?id=31 This course is aimed at everyone who is working with data that contain repeated measurements on persons or otherwise related data and who wants to analyse such data in a proper way. In many situations one may have data that show some

Hello R-Group I found how to fill the data.frame -> http://finzi.psych.upenn.edu/R/Rhelp02a/archive/70843.html N1 <- rnorm(4) N2 <- rnorm(4) N3 <- rnorm(4) N4 <- rnorm(4) X1 <- LETTERS[1:4] ################### nams <- c(paste("N", 1:4, sep = ""), "X1") dat <- data.frame(lapply(nams, get)) names(dat) <- nams dat But I need also to create

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I have a rectangular matrix of size 920 by 85. I'd like to coerce it into a square matrix such that all row/col names are present in the new matrix and the additional values are zero. As an example: A B C D A 1 2 3 4 E 5 6 7 8 F 9 10 11 12 Would be coerced to: A B C D E F A 1 2 3 4 5 9 B 2 0 0 0 6 10 C 3 0 0

does anyone know how to get ksh to use tab completion? -- Andrew Rice Jr Systems Analyst Carrier Management Systems, Inc. 500 Chestnut Street, Suite 500 Abilene, TX 79602 USA support: (325) 672-0975 office: (325) 677-5900 fax: (325) 676-0529 http://www.nams.net NAMS III, NAMS 2000 Centralized, NAMS BMX

using vsftpd, I know its possible to specify what directory you want a user to be dropped into when he ftps in...but I dont remember where to go to change that. any suggestions? -- Andrew Rice Jr

HI Folks, I'm trying to create a list with named elements. Only, I don't know the names of the elements a priori (they come from the data being calculated). Currently, my approach is to create an environment, then assign things to the environement, then as.list the environment to get a list. Running the code gives, for example: > e2 <- new.env(FALSE, NULL) >

Dear R helpers, I have a data.frame as given below - dat1 = data.frame(date = as.Date(c("3/30/12","3/29/12","3/28/12","3/27/12","3/26/12", "3/23/12","3/22/12","3/21/12","3/20/12", "3/30/12","3/29/12","3/28/12","3/27/12",