similar to: beginner question - effective way to chart sleep habits

A year ago I had posted this code https://stat.ethz.ch/pipermail/r-devel/2005-June/033508.html and the associated discussion was that there would be a print.trellis argument that could be used to eliminate the need for with.vpPath or with.viewport there. I assume that that is what draw.in= in print.trellis is for. When I try it I get an error. I did notice that ?print.trellis says draw.in=

I am setting up base plots -- one in viewport A and and one in B. This part works fine. But if I go back to A after having done B and add horizontal lines it seems to not use the correct coordinates. How do I tell it to resume using A's coordinates? I am already using par(fig = gridFIG()) but it seems that that's not enough to reestablish them. What happens is that when I go back to

I am setting up base plots -- one in viewport A and and one in B. This part works fine. But if I go back to A after having done B and add horizontal lines it seems to not use the correct coordinates. How do I tell it to resume using A's coordinates? I am already using par(fig = gridFIG()) but it seems that that's not enough to reestablish them. What happens is that when I go back to

I'm trying to create a layout with named viewports that I can use for other functions. I create the viewport tree that I want, and a list of grobs with the viewports describing where they should go. library(grid) vp <- vpTree( viewport(layout=grid.layout(2,2), name="layout"), children=vpList( viewport(layout.pos.col = 1, layout.pos.row=1, name="tl"),

I have two chromatograms I want plotted on the same axes. I would like the plots to be transparent, so the first chart is not obscured. I have tried adjustcolor(..., alpha.f=0.3), the problem is that my chromatogram is so dense with datapoints that they overlap and the entire graph just ends up a solid color. The second histogram still obscures the first. Consider this example: col1 <-

## This example runs in R 2.3.1 and does not run in R 2.4.1. I am ## raising it here for two questions: one on how to debug functions ## inside a namespace, the other on how to control clipping. tmp <- data.frame(x=1:5, y=1:5, a=factor(c(1,1,1,1,1), levels=1:4)) xyplot(y ~ x, data=tmp, ylim=c(1.5,4.5), panel=function(x,y, ...) { cpv <- current.viewport()

Hi, I am fairly new to DTrace, and wanted to ask something regarding synchronization objects. I have a multithreaded C++ program in which I use semaphores (POSIX version) for synchronization. I was interested in using DTrace to figure out the total time for which each thread in my application sleeps, blocked on a semaphore, i.e., as a result of sem_wait() call. In order to measure this, I

I like the functionality provided by outer=TRUE, but when it comes time to place separate xlabs or ylabs, I always end up 'eyeballing' it on a case-by-case basis. For example, ##begin example require(lattice) cars.lo <- loess(dist ~ speed, cars) print(xyplot(cars.lo$residuals+cars.lo$fitted~cars.lo$x, strip=FALSE, outer=TRUE, layout=c(1,2),

Hi everyone. I want to solve the following problem. I have a data.frame and I create a dotplot using lattice. Then I want to use the grid-package to create a combined graphic which contains the dotplot as well as a textplot() (using package gplots) of the data.frame next to the dotplot. Example code: library(lattice) library(grid) library(gplots) xx <- data.frame(f=factor(rep(1:5, each=5)),

Hi, after updating R 2.5.0 devel yesterday we today observed many new unexpected failures in our daily package build and test system runs, which can be traced to recent changes in the implementation in try() (as noted in NEWS). Investigating this new implementation I come across an issue in conjuntion with using S4 classes and methods. try(expr) does not return an object with attribute

The code below displays three graphs in three rows and one column but: 1. I want to remove the space between the graphs (I tried playing with position= arg to print.trellis but it seems quite difficult to get the right values and all my attempts had space between them or had overlapping graphs. Is there a better way to do this? 2. the widths of the plots are not the same even though I specified

list(...) I can not get at the grid viewports in a ggplot2 plot. I know there is supposed to be a viewport called "panel_1_1" but downViewport() can't find it. Has the viewport been popped? I had a quick look at the functions involved (eg ggplot_plot) but there is no obvious problem there. > library(ggplot2) > qplot(1:10, 1:10) > current.viewport() viewport[ROOT] >

Hello all, I'm trying to write a function using the gridBase package. I'd like to push several base subplots to a larger plot constructed with grid. However, I'm having trouble getting consistent results when running the function when the plotting window (quartz) is closed, when it is left open and the plot function is repeated to the same window, and when the output is saved to a

Hi, I am having trouble plotting a series of dendrograms using lattice and grid code as found in Paul Murrells book R Graphics. This is the error message I recieve: Error in downViewport.vpPath(vpPathDirect(name), strict, recording = recording) : Viewport 'plot1.panel.1.1.off.vp' was not found I have attached the code and also my data file. Should anyone have any suggestions then

hello, the example below does not work. (i know it's not supposed, but it makes it clear what i'm trying to achieve) par(mfrow=c(2,1)) xyplot(y~x2|x1,data=dataframe1,pch=20) xyplot(y~x2|x1,data=dataframe2,pch=20) i know i could probably merge the two datasets and do something like xyplot(y~x2|x1+dataset,data=merged) any other suggestion? thanks. [[alternative HTML version deleted]]

dear R group: I have the probably fairly common problem that I would like to have one code.R file do different things if it is invoked from a symbolic link, which should be easy to uncover. $ ln -s code.R code-0.R $ ln -s code.R code-1.R $ R CMD BATCH code-1.R what needs to be in code-1.R to put code-1.r into a character vector? help appreciated. regards, /ivo welch PS : I read

I recommend instead of no border, that you use a border with the same color as the fill. I do this in the likert functions in the HH package. Rich On Mon, May 21, 2018 at 10:59 AM, Martin Batholdy via R-help <r-help at r-project.org> wrote: > Dear R-users, > > I want to draw a barplot with beside=TRUE. > One halve of the bars are drawn with a border, while the other halve are

Dear list, I need to align two plots on top of each other for comparison (they only have the x-axis in common). When the y-labels have a different extent, I cannot find a way to align the x-axes, as illustrated below, > library(grid) > library(lattice) > x <- seq(0, 10, length=100) > y <- sin(x) > y2 <- 10*sin(x) > f <- rep(c("1", "2"),

Why does the seekViewport at the bottom give an error? > xyplot(Sepal.Length ~ Sepal.Width, iris, group = Species, col = 11:13, + auto.key = TRUE) > grid.ls(view = TRUE) ROOT GRID.rect.89 plot1.toplevel.vp plot1.xlab.vp plot1.xlab 1 plot1.ylab.vp plot1.ylab 1 plot1.strip.1.1.off.vp GRID.segments.90 1 plot1.strip.left.1.1.off.vp

Hi, Why does the upper left panel (in the plot below) not have a gray background? Cheers, Marius require(grid) require(gridBase) pdf(file="Rplot.pdf", width=8, height=8, onefile=FALSE) ## set up the grid layout gl <- grid.layout(5, 5, widths=unit(c(1.8, 8, 0.8, 8, 0.8), "cm"), heights=unit(c(0.8, 8, 0.8, 8, 1.5), "cm")) if(FALSE) grid.show.layout(gl)