similar to: R2PPT - Insert data.frame

Dear R-help, I managed (thanks to the R2PPT package) to create a PowerPoint presentation and create a table in it but for the life of me I can't find a way to populate the table with values and text. I'm aware of the function 'PPT.AddDataFrame' which creates an Excel object from a data frame, but the excel object is not nearly as nice looking and easy to manipulate (and apply

Hola tengo q hacer un trabajo, donde me piden q todas las salidas q haga sean en Power Point (graficos, tablas, etc). Para eso habia empezado a leer algo del paquete R2PPT, pero la verdad es q hay cosas q no entiendo de este paquete. Queria saber si alguien estuvo trabajando con el y obtuvo buenos resultados o si han usado otro paquete para hacerlo. Por ultimo una pregunta: desde Sweave se

Hello list, I have a linear regression ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) group <- gl(2,10,20, labels=c("Ctl","Trt")) weight <- c(ctl, trt) reg <- lm(weight ~ group) sreg <- summary(reg) and I would like to dump exactly what I see on the console with

Hi, I am trying to extract the coefficients matrix from a gls summary. Contrary to the lm function, the command fit$coefficients returns only the estimates of the model, not the whole matrix including the std errors, the t and the p values. example: ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) group <-

Hi, I'm newbie with R and don't really know how to add a median line to each of the groups that is not all the plot long. Here is a small working code that i have adapted for my purpose. If somebody could tell me how to draw median lines on each group and not all plot long. ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <-

Dear Everyone in list: I am writing some codes to automate the process of fitting linear models where the names of variables of models are produced and stored in character vectors. But I have problems to pass the vectors to the lm( ) because I don't know how to strip the quotation marks automatically. Here are the codes of the example of lm( ): ## Annette Dobson (1990) "An Introduction

<r-help@r-project.org> Hi, R users, How can I export an R object as a .txt file? As an example I have the result from a regression and I need to save this object in a .txt file ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) group <- gl(2,10,20, labels=c("Ctl","Trt")) weight <- c(ctl,

Hi, I tried to replicate the values of critical probabilities reported from lm() function in R as below ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) group <- gl(2,10,20, labels=c("Ctl","Trt")) weight <- c(ctl, trt) model_coed <- summary(lm(weight ~ group))[[4]] print(pt(abs(model_coed[,

Hi, perhaps this question was answered previously however I could not find them. My problem is how how to extract a particular statistic from the result given by lm(). For e.g. ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) group <- gl(2,10,20, labels=c("Ctl","Trt")) weight <- c(ctl, trt) >

Dear R-helpers, I was curious why the output of summary (and many other functions in R) does not add a separator between the name of a factor and the label of a level (e.g., in the example below, 'group Trt'). If the user had lower case labels (e.g., 'trt'), the output would be particularly hard to read. ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt

Hi! In R 3.0.0 from current SVN, ?summary.lm says: > Value [...] > df degrees of freedom, a 3-vector (p, n-p, p*), the last > being the number of non-aliased coefficients. ?summary.glm says: > df a 3-vector of the rank of the model and the number of residual > degrees of freedom, plus number of non-aliased coefficients. It seems to me that the description is reversed: p is

Hi all, This should be a very simple question for you, whereas it is proving devilish for me. How do I output the STANDARD ERROR of the regression coefficient (i.e., the standard error of b) from a simple linear regression? Consider this data, taken directly from ?lm: ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69)

Hi all, I wanted to mark the estimation sample: mark what rows (observations) are deleted by lm due to missingness. For eg, from the original example in help, I have changed one of the values in trt to be NA (missing). # code below # ---- # original example > ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) > trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) #

Dear all, I have the following question. Is it possible in R to call for the p-value directly in a model like this a <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) b <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) summary(lm(a~(b+0))) or even in this a <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) b <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14)

Hello all: (First of all, sorry for my very bad english) I came from R-help-es with this problem, they say me this is a better place to find a solution, I hope that. I try to use lm function, then R exploit. After I cleaned my code without success I try the basic: open R (try on console and Rkward) and run lm examples, this is the output: ---------- console cut ------------------- R version

Hola a todos. Quería saber si conocéis alguna librería que haga esto: SPSS permite enlazarse con PowerPoint de manera que si quiero modificar un gráfico del ppt, con solo pinchar en el gráfico me aparece los datos del spss y al modificar estos cambia la gráfica directamente sin tener que hacer la gráfica de nuevo. Hay algo parecido en R???? Saludos José Miguel Contreras [[alternative

Hi, I am trying to create a graph using Arial font (as required by PLoS One). I have read probably all posts in R-help on this topic, as wells as R-news 2006. The code I have been trying is following: Arial <- Type1Font(family="Arial", metrics=c("ArialMT.afm", "arial-BoldMT.afm", "Arial-ItalicMT.afm",

Hello list, I am used to give a lot of attention to the standardized regression coefficients, which in SPSS are listed automatically. Is there alternative to running the last two lines in the following example to get all the information? ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) summary( lm(ctl ~ trt) )

Hi Peter, the "residuals()" function returns the residuals of a model fitted using the "lm" function. For instances, using the example included in the help of lm: ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) group <- gl(2, 10, 20, labels = c("Ctl","Trt")) weight <-

Hi, I have a little problem : Some user have problem with file is read-only mode But all unix acl and posix acl are correct : ls -l drwxrwx---+ 19 root Utilisateurs 4096 jun 9 11:33 STEPHANE -rwxrwx---+ 1 root Utilisateurs 1027584 jun 7 14:33 dossier fraise.ppt getfacl: Removing leading '/' from absolute path names # file: