similar to: transform a df with a condition

Hi, everybody. I am working processing EEG data from 1000 pacients. I have a specific syntax to perform the Spectral Analysis and a loop to analyse all subjects. each subject data are in separate folders (P1, P2 P3...) My question is: in some cases, some errors can appear in one subject. I want to know if is possible to jump to the next subject and perform the same syntax , exibiting an error

Hi, I am trying to edit a data frame such that the string in the first line is appended onto the beginning of each element in the subsequent rows. The data looks like this: > df V1 V2 V3 V4 1 DPA1* DPA1* DPB1* DPB1* 2 0103 0104 0401 0601 3 0103 0103 0301 0402 . . and what I want is this: >dfnew V1 V2 V3 V4 1 DPA1* DPA1* DPB1* DPB1* 2 DPA1*0103

Hi, i'm very new to R, so sorry for what i'm sure is a very basic question. I'm producing a boxplot with the data below: df3<-data.frame( x=c(10,11,115,12,13,14,16,17,18,21,22,23,24,26,27,28,29,3,30,32,33,34,35,4,4 1,45,5,50,52,56,58,6,67,6738,68,7,8,9), fq=c(8,11,1,2,4,4,2,2,6,3,4,2,2,1,1,1,4,51,3,1,1,1,1,35,1,1,19,2,1,1,1,14,1, 1,1,10,13,5),

Dear R friends, I am currently working with time series data, and I have a table(as data frame) that has looks like this (TransitDate are in format = "%e-%B-%Y") : TransitDate Transits CargoTons 1985-04-01 100 2500 1985-05-01 135 4500 1985-06-01 120 1750 1985-07-01 100 3750 1985-08-01 200

I have a series of tables, one for each environment indicating a date (row) and a sample at each hour of the day (0 to 23) Test1 Table: Date,Hour1,Hour2,...Hour23 1/1/10,123,123,...,123 I would like to model this as a time series but how can I translate the table into a list such that I can get: 1/1/10 00:00, 123 1/1/10 01:00, 123 1/1/10 02:00, 123 ... 1/1/10 23:00, 123 Any suggestions on how

Hi there, I have a data.frame (pwt6) which I would like to transform: country year gdp MEX 1950 2 MEX 1951 5 BOL 1950 4 BOL 1951 12 ITA 1950 45 ITA 1951 2 This should be the result: year MEX.gdp BOL.gdp ITA.gdp 1950 2 4 45 1951 5 12 2 Right now I have this code (better - no code): country.label<-names(table(pwt6$country)) result<-data.frame(year=NULL) for(i in country.label) ?

Hi Paul, #First I set up some sample data since I don't have a copy of your data dtOrig <- as.Date( c("1985-04-01","1985-07-01","1985-12-01","1986-04-01")) dfOrig <- data.frame( TransitDate=dtOrig, Transits=c(100,100,500,325), CargoTons=c(1000,1080,3785,4200) ) #Generate the complete set of dates as a data frame dfDates<- data.frame(

Dear list, I would like to expand a DF with all the missing levels of a variable. a <- c(2,2,3,4,5,6,7,8,9) a.cut <- cut(a, breaks=c(0,2,6,9,12), right=FALSE ) (x <- data.frame(a, a.cut)) # In 'x' the level "[0,2)" is "missing". AddMissingLevel <- function(xdf) { xfac <- factor( c("[0,2)", "[2,6)", "[6,9)",

Dear R-users, I am trying to reshape the DF "dat2" in the "long" format, but can't figure out how to use the "split"-option: > dat2 a.1995.z b.1995.z a.1996.z var 1 100.00000 100.00000 100.00000 Neue Anlagen insgesamt 2 40.09904 23.60890 40.88960 Neue Ausr??stungen 3 59.90096 76.39110 59.11040 Neue Bauten This

Hello, R-helpers. I have a data frame below called df. I want to add a variable c, based on the following logic: if df$a < 5 then the first two times this condition is met place a 1 in c, the next two times this condition is met place a 2 in c and when the condition is not met let c equal df$b. The result would look like, dfnew, shown below. a <- rep(c(3,5,7), 4) b <- rep(c(NA,1,2),

Hello All, Would like to be able to convert a matrix to a dataframe without losing an assigned dimname. Here is an example that should illustrate what I'm talking about. tableData <- state.x77[c(7, 38, 20, 46), c(7, 1, 8)] names(dimnames(tableData)) <- c("State", "") tableData State Frost Population Area Connecticut 139 3100 4862

Dear Eric, Hope you are doing great. I also tried the following: #First I created the complete date sequence TransitDateFrame <- data.frame(TransitDate=seq(as.Date(dataset1[1,1]), as.Date(dataset1[nrow(dataset1),1]), by = "month")) #Then I did the merging dataset1NEW <- merge(TransitDateFrame, dataset1, by="TransitDate", all.x=TRUE) Now it has, as expected the

Hi, I am a beginner in R and have only read a few chapters in the R book, I was not able to find a solution for this simple problem. I have an empty data frame: a=data.frame(name="test") which I would like to extend in a for-loop (with data extracted from a database). Ideally I would like to extend the data frame like this: a["new_1"] = 1:10 a["new_1"] = 1:12

Dear list, # I have a DF like this: sleep$b <- c(rep(8,10), rep(9,10)) sleep$me <- with(sleep, ave(extra, group, FUN = mean)) sleep # I would like to create a new variable # holding the b-th value of group 1 and 2. # This is not what I want, it takes always the '8' from group '1' # and not the '9' sleep$gr <- with(sleep, ave(extra, group, FUN = function(x)

I've been using R for several months now, in fact it was my intro to "real" computer programming. It used to frustrate me no end, but lately I've noticed my reaction has changed. Nowadays its much more like "wow, is that cool, or what?". So I guess I've gotten over the hump of the learning curve. Comparing what I now do with R to my previous hodge-podge of

Hi Instead of attachments copy directly result of dput(TransitDateFrame) and dput(dataset1) to your email. Or, if your data have more than about 20 rows you could copy only part of it. dput(TransitDateFrame[,1:20]) dput(dataset1[,1:20]) Only with this approach we can evaluate your data in all aspects and provide correct answer. Cheers Petr > -----Original Message----- > From: R-help

Hi everyone! I'm matching two samples to create one sample that have pairs of observations equal for the k1 variable. Merge() doesn't work because I dont't want to recycle the values. x <- data.frame(k1=c(1,1,2,3,3,5), k2=c(20,21,22,23,24,25)) x y <- data.frame(k1=c(1,1,2,2,3,4,5,5), k2=c(10,11,12,13,14,15,16,17)) y merge(x,y,by="k1") k1 k2.x k2.y 1 1 20

Dear list, this works fine: x <- split(iris, iris$Species) x1 <- lapply(x, function(L) transform(L, g = L[,1:4] * 3)) but I would like to multiply each Species with another factor: setosa by 2, versicolor by 3 and virginica by 4. I've tried mapply but without success. Any thoughts? Thanks for any idea! Patrick

Sorry, but I'm just an ignorant Linux user! I have a silly question. Situation: Now that R 2.1.0 is out (Thank you, to all concerned!) I'm about to go off and download it and all the packages. What this means in practice is trotting off to my "local" (and brand new) Internet Cafe with some CDs, where I can get the lot over a fast link and burn it onto a CD or two. However,

Dear all I have a data.frame like that : father mother num_daughter daughter 291 3906 0 NULL 275 4219 0 NULL 273 4236 1 49410 281 4163 1 49408 274 4226 1 49406 295 3869 2 49403 49404 287 4113 0 NULL 295 3871 1 49401 292 3895 4 49396 49397 49398 49399 291 3900 3 49392 How to read it into R and transform it like that: father mother num_daughter