similar to: Error: package 'akima' is not installed for 'arch=i386'

por favor alguien podria ayudarme con el paquete climatol, tengo ulgunos problemas para ingresar la informaciòn gracias El 13 de noviembre de 2013 14:49, <r-help-es-request@r-project.org>escribió: > Envíe los mensajes para la lista R-help-es a > r-help-es@r-project.org > > Para subscribirse o anular su subscripción a través de la WEB >

Hi user R, I am try to calculate the spectrum function in two time series. But when plot a single serie, the labels in axes x is in the range 0.1 to 0.6 (frequency), but when calculate de spectrum with ts.union function, the labels x is in the range 1 to 6. I not understand why change the labels, and not know that is ralationship. Samebody can hel me in this analysis..... Thank for all fdo

Hi all user R, My simple question is...I have a vector of names of predictors, text<-c("datem","cola","eslom")...I try to plot the model with this predictor in sequence loop...., for(i in 1:3){ png(paste("fig_",i,sep="")) plot(preplot.gam(mod9)[[i]],se=T,rug=F,main="",xaxt="n",ylab="",xlab="")

Hi user R, I am try to put degree character in axis x, but don't make this. I have the next code: plot(mot[,5], time1,xlim=c(-45,-10),type="l",yaxt="n",ylab="",col=1,lwd=2,xlab="",xaxt="n") The range of value in axis-x is -45 to -10, this values represents the longitudes positions in space. I try to put 45?S for real value (-45) in

Buen dia, estoy buscando algun paquete en R q me permita determinar el tamaño de la muestra para un muestreo estratificado con probabilidad proporcional al tamaño (pps). Alguien me podria decir si conoce y uso alguno? Gracias -- *"...después de todo tú eres, la única muralla...si no te saltas nunca darás un solo paso..."* L. A. Spinetta [[alternative HTML version deleted]]

Gracias Javier, algunos habia visto Creo q lo hare a mano nomas Saludos El 13 de noviembre de 2013 10:29, Javier Villacampa González < javier.villacampa.gonzalez@gmail.com> escribió: > Yo no conozco ningún paquete para hacer esto aunque probablemente exista. > De todas maneras las cuentas de este tipo de calculos no suelen ser > complicadas. Personalmente le recomendaría pasarse

Yo no conozco ningún paquete para hacer esto aunque probablemente exista. De todas maneras las cuentas de este tipo de calculos no suelen ser complicadas. Personalmente le recomendaría pasarse por una biblioteca y adquirir el siguiente libro donde explica con todo lujo de detalles, en castellano y simpliciddad como hacer estos calculos

Hi everyone I was using spline to interpolate single or two consecutive missing data points in time series. However, when it comes to longer gaps in the data the spline function generate new data for both my known and unknown data (see below). Aside from not understanding why this happens, I thought thought I might try function "aspline" in library (akima). However, I cannot install or

I am trying to load the GRASS library and am getting the following error: > library(GRASS) Loading required package: akima Error: package 'akima' could not be loaded In addition: Warning message: There is no package called 'akima' in: library(pkg, character.only = TRUE, logical = TRUE, lib.loc = lib.loc) This is on R 2.0.0, library(GRASS) is installed, and update.packages()

I am using the Akima interpolation package to generate an interpolated color contour plot. It is working very well, except for one problem. The data that I have represents real-time readings from a thermistor string vs. time, so the data points are often very nearly in a rectangular array, since the thermistors are read at regular time intervals and they are equally spaced physically.

R Users, I am using the AKIMA contrib package to generate a 2D colored contour plot. The code generates a contour value color legend adjacent the plot based on the range of Z values in the plot. Is there some way to make the association between Z values and color scale absolute rather than relative i.e., I want dark green to always mean Z = 4.00 even if I don't

Dear all! I'm using R 2.12.1 in Ubuntu 10.04. Problem is that when using functions like interp (package akima) and akimaInterp (package fUtilities), I get different results every time for the same data set. I've checked the interpolated results, and two examples (in attachment) have different sum of NA values. Also when I subtract the x,y,z values from two interpolations of the same data

Dear all; First of all, this is probably a more conceptual question than a R-related one, but still want to give it a try. When working with the interpolation function "interp" from the package akima and the triangulation function "tri.mesh" from package tripack I've got NA's for the interpolation and "error" for the triangulation. The data is arranged in a

Dear all I have this table > dput(mat) mat <- structure(c(2, 16, 9, 2, 16, 1, 1, 4, 7, 7, 44.52, 42.8, 43.54, 40.26, 40.09), dim = c(5L, 3L)) And I want to calculate result for contour or image plots as I did few years ago. However interp does not compute the z values and gives me zeros in z matrix. library(akima) > interp(mat[,1], mat[,2], mat[, 3], nx=5, ny=5) $x [1] 2.0 5.5

Dear R users, I want to do a fitted.contour plot of selected columns of a dataframe M with M$AM and M$Irradiance as x and y axes respectively. The level of the contour shall be determined by M$PR. Some words on my data first. Dataframe M looks like: head(M$Irradiance) [1] 293 350 412 419 477 509 head(M$AM) [1] 2.407 2.161 1.964 1.805 1.673 1.563 head(M$PR) [1] 70.102 72.600 75.097 80.167

Full_Name: Jonathan Lees Version: 2.0.1 OS: linux-gnu Submission from: (NULL) (152.2.75.65) there is a problem with calculating the convex hull in 2-D interpolation using the codes interp fromt eh akima package: x =c(0.6505304, -1.1821562, -0.2600792, 0.7913716) y = c(1.0424226, 0.1754048, -1.4523334, 0.2349112) z = c(0.000, 3.042, 0.370, 0.122) EX = seq(from=min(x), to=max(x),

Dear all. I am using the akima function to produce 3d contour plots using interp based on irregular data. using the eg in the akima manual library("akima") data(akima) plot(y ~ x, data = akima, main = "akima example data") with(akima, text(x, y, formatC(z,dig=2), adj = -0.1)) ## linear interpolation akima.li <- interp(akima$x, akima$y, akima$z) image (akima.li, add=TRUE)

The akima package has a problematic license (it doesn't allow commercial use), so it's been recommended that people use the interp package instead. When I use interp::interp instead of akima::interp, I get reasonable output from your example. So that's another reason to drop akima... Duncan Murdoch On 26/01/2023 9:35 a.m., PIKAL Petr wrote: > Dear all > > I have this

Full_Name: Michael R. Allen Version: 1.01 OS: linux redhat Submission from: (NULL) (149.149.32.46) Hello, Thought you might be interested. I tried to load the package tripack needed by the sgeostat package. After some careful searching, three packages were found which had the same error. Here is the output. Mike > library(acepack) Error in dyn.load(x, as.logical(local),

Si antes de hacerlo tú mismo decides mirar otras opciones, además de las que te han dicho: survey <http://cran.at.r-project.org/web/packages/survey/index.html>analysis of complex survey samples sampling <http://cran.at.r-project.org/web/packages/sampling/index.html>Survey Samplingsamplingbook<http://cran.at.r-project.org/web/packages/samplingbook/index.html>Survey Sampling