similar to: How to change leaf color by group in hclust plot or how to install A2R package in windows?

Dear R users, Hi. I want know R code of a function: predict.cv.glmnet (which is included in glmnet package). Could you let me know how I can see the R code of the function? Thank you, Soyeon Kim

Hi there, I've tried to install the A2R package using the files from http://addictedtor.free.fr/packages/A2R/lastVersion/ This is the error I get when trying to load the library: library(A2R) Error in library(A2R) : 'A2R' is not a valid package -- installed < 2.0.0? Can anyone please help? Thanks. Kate [[alternative HTML version deleted]]

Dear my R friends, I want to get a number from a list using paste function. In my example, lambda.rule <- "lambda.1se" cvtest is a list (result from cv.glmnet) and cvtest$lambda.1se [1] 1.308973 I want to call the value using paste function. I used get function but there was an error. test <- get(paste("cvtest$",lambda.rule, sep="")) Error in

Dear All, I have data which contains 14 variables. And I have to regress one of variables on each variable (simple 13 linear regressions) I try to make a loop and store only R-squared colnames(boston) [1] "CRIM" "ZN" "INDUS" "CHAS" "NOX" "RM" "AGE" [8] "DIS" "RAD"

Dear List I'm trying to install a package not present in cran named A2R ( http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=79) After running the demo script I retrieve the following error: cannot change value of locked binding for '._a2r_counter' Please could someone give to me a tip about my error? Thank you very much Here is my sessionInfo() R version 2.15.0

Dear R users, Hi. I am using prediction function in ROCR package. y consists of two classes 0 and 1. However, since I am using cross-validation, a sampled small number of y may consist of only one class >y [1] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 In this case, prediction function gives an error: Error in prediction(predic, y) : Number of classes is not equal to 2. ROCR currently supports

Dear All, I have vn variable > vn [1] "V300" "V376" What I want to get is 300 376 without V and "" from vn variable. Could you help me about this issue? Thank you, Soyeon [[alternative HTML version deleted]]

Dear All, I made a function which gives 3 plots in one window(I used par(mfrow=c(1,3)) in the function). Using that function 3 times, I want to produce 9 plots in one window. I tried par(mfrow=c(3,1)) or par(mfrow=c(3,3)) but it didn't work. For example, pf <- function(p) { par(mfrow=c(1,3)) plot(c(p:(p+10)),c(1:11)) plot(c(p:(p+10)),c(2:12)) plot(c(p:(p+10)),c(3:13)) } p <-

Dear All, This is hard to describe so I made a simple example. set.seed(1001) total <- 0 data <- vector("list", 30) for(i in 1:30) { data[[i]] <- runif(50) } Let's call a data set runif(50). While the for loop is running, 100 data sets are generated. I want to restore 23th data set (the data set generated in 23th for loop) without the loop. I've tried set.seed(1023)

Hi All R-helpers This is my first (but probartly not last ;-) mail to R-help, so hello to everybody. My problem: Is there a way to give colors to the labels (sample labels) in plots for a hclust object for better visualization? I have looked through plot, points, hclust and more but cannot find anything on label color. Anybody know if this is doable? Best regards Jeppe

Hi. I am trying to generate a correlated binary data set. I've tried to use mvtBinaryEP, binarySimCLF, and bindata packages but none of them works in R version 2.15.1. Do you know any package to generate correlated binary covariates and work in R version 2.15.1, or how to generate it? Thanks, [[alternative HTML version deleted]]

Hi, I have a grouping of some observations. I want to cluster them using hierarchical clustering and compare how the hierarchical clustering shows up vis-a-vis the groupings. Is it possible to do this in color? I guess what I am looking for is a way to color the labels of a hierarchical clustering plot using different colors according to the original grouping. Any suggestions? Many thanks and

Hi Everyone, I'm trying to use cutree to get the clusters after hclust. What I used is: mycluster<-cutree(cnclust,h=0.5) Now, my problem is, how can I get the actual clusters? Thanks! Best, Baoqiang Cao

Dear r-list, I am trying to visually seperate the two main clusters of a dendrogram. The idea is to use: 'edgePar=list(lty=3)' for 'dend1[[1]]' and 'edgePar=list(lty=1)' for 'dend1[[2]]' I have not found a way to solve this. Any suggestions? Patrick hc <- hclust(dist(USArrests), "ave") (dend1 <- as.dendrogram(hc)) par(mfrow=c(2,2)) plot(dend1)

Hello everyone, I wanted to know if it was possible to change the color of certain leaves in a hclust object in order to make my graph more readable. I know I can color certain groups but I would like to enter a vector telling the plot function which leaves to color in which color. Thanks in advance, William.

Hi all, I am creating dendrograms using agnes and was wondering if it is possible to add color to the leaves (and just the leaves). For example, in the documentation, they have an example using the "votes.repub" data set. If I wanted to make the word "Washington" green (and only Washington), is it possible and if so how? I can apply "summary" to the object

Dear All, I have a cluster object based on a dissimilarity matrix from about 1,100 cases and wish to know whether anyone can think of any tips to display some form of graphical output which would give some sense of the similarity between the cases. A standard form of dendrogram would be fine, but with so many cases the dendrogram on the standard devices (R-2.20 on NT4) is very compact

I've been trying to get plot.hclust to work with a hclust object I created and have not had much success. It seems that there is some "hidden" characteristic of a hclust object that I can't see. This is most easily seen in the following example, where plot.hclust works on one object, but when this object is "dumped" and then re-read, plot.hclust no longer works. Is

Hello all, I'm now working with hclust objects and was hoping to perform some basic editing on them like: - Joining = the merging of two hclust objects (so they will share one root) - Splicing = So to cut/extract a branch out of an hclust object - that by itself will be an hclust object. I noticed I could extract one element of an hclust object by turning it into a dendrogram,

I could not figure out what was the default when I ran hclust() without specifying the method. For example: I just have a code like: hclust(dist(data)) Any input would be appreciated:) [[alternative HTML version deleted]]