similar to: check for item in vector

Hello everyone, I have a data set like this: > head( fish_transect) ID_TRANSECT ID_PROJECT DE_ZONE DE_LOCALITY DE_SECTOR MES 1 42 MB Tarragona Creixell Control I 9 2 42 MB Tarragona Creixell Control I 9 3 42 MB Tarragona Creixell Control I 9 4 42 MB Tarragona Creixell Control I 9 5 42

Estimados R-users: Estoy intentando usar la función 'agrep' para hacer búsquedas en cadenas de texto. El parámetro max.distance permite controlar la medida de aproximación de búsqueda de la función de Levenshtein. No obstante, cuando hago búsquedas específicas no obtengo siempre el resultado deseado y no se si es un bug o que no entiendo bien el algoritmo de búsqueda. Por

Hi, I hope this is not too trivial, but I've had this recurring problem and I think there is super easy solution, just not sure what it is. Please see short example below. ?I would like to get the frequency (counts) of all the variables in a single column (that is easy), but I would also like to return the value 0 for the absence of variables defined in another column. For example: animals

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

I''ve been playing around with some easier ways of specifying conditions in active record, and have come up with a little plugin that some may find useful. Currently active record finder and calculations methods can take a :conditions option with a string or array listing some sql conditions, eg: Animals.find :first, :conditions => "name = ''Tiger''" My

Dear users, My problem concerns save() within a for loop. Here is my code: for (i in 1:4) { temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)]) filename <- paste("file", i, sep="") assign(filename, temp) save(filename, file=paste(filename, ".rda", sep="")) } As you can see, save() doesn't work as I would like: (1) the object

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Hello, How can I read a xlsx file using xlsx package? Thanks Albert [[alternative HTML version deleted]]

Dear users, I would like all the ticks on a boxplot (x and y) to be labeled I have checked all the par() arguments but couldn't find what I'm looking for Here is an example to show it: df <- structure(list(SPECSHOR = structure(c(1L, 1L, 1L, 3L, 3L, 3L, 3L, 3L, 4L, 4L), .Label = c("cotau", "dibic", "eqgre", "gicam"), class =

Hi, I have tried looking at the archives but havent found any answer that works till now (Sorry if i have missed anything) I am a newbie to R and i am trying to carry out hierarchical clustering using hclust -> as.dendrogram and then plotting the results as a dendrogram using the plot function plot(object). My question is : In the function "plot", can one decrease the leaf label

It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector. Maybe you can use unlist() instead of as.vector() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others

Dear users, I have looked on different sources and found different functions to prompt the user to provide input. However, I couldn't find one that does exactly what I'm looking for. select.list() and menu() are nice because a graphic window appears to prompt the user. However, the user can only choose from a predefined list of choices. readline() and scan() are more free in the

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)

Hello, I want to make an 2D plot of .xyz data. So plot on x-axis and y-axis and use a color scale for the z. For every x-location along a cross section of the soil at several depths a resistivity must be displayed. This must result in a picture/graph which shows the resistivity for that cross section. The depths differ for each x-location. How can I do that? In fact it is an cross

Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",

Hi I have data in the following format Cort Day Animal 23 0 1 27 3 1 24 0 2 27 1 2 34 2 2 30 3 2 24 4 2 20 0 3 24 1 3 28 2 3 34 4 3 etc. It is measured across time(day) however no every individual is measured the same number of times. All I want to do is plot the Raw data and then run a line connecting the

Dear All If I have the following dataset V1 V2 x y y x z b a c b j d l c o How do I use R command to get the total number of different letter in column "V1" column "V1" has 7 different letters. Thank you -- View this message in context: http://r.789695.n4.nabble.com/Summing-up-Non-numeric-column-tp3077710p3077710.html Sent from the R help mailing list archive

Hi. In a data set I have a variable that takes values from 1 to 14. For each subgroup of values of this variable, I would like to obtain some descriptive statistics of other variables present in the data set. I've been trying with a "for" loop but I couldn't get nothing. Could you please suggest me some lines? -- View this message in context:

It's often difficult to figure out what a problem data set looks like when someone pastes a mess of output from R into an e-mail. The dput command, used judiciously?I would hope no one would send a 1 M data set?can make life much easier. I wonder if it would be useful to add a hint in the instructions at the bottom of the posting page, where the list asks for self-contained reproducible