Displaying 20 results from an estimated 200 matches similar to: "the output of function lars"
2010 Jun 09
1
TermGenerator incorrectly tokenizes German text which contains special characters
Dear Xapian users,
I try to index some German text with Xapian using the xapian_php bindings. I
run Apache 2.2 on Windows using PHP 5.2.13 with the pre build xapian
bindings from Flax:
Xapian Support enabled Xapian
Compiled Version @PACKAGE_VERSION@
Xapian Linked Version 1.2.0
The problem is that after indexing text which contains special characters
like ?, ?, ? and ?, using
2010 Nov 16
1
how to do linear regression when dimension is high
Hi I am a newbie in R.
I have data with dim of 20.
How to use lm if i want to do regression with the whole design matrix? My y
is the first column.
the left are xs.
Thanks a lot.
--
View this message in context: http://r.789695.n4.nabble.com/how-to-do-linear-regression-when-dimension-is-high-tp3045167p3045167.html
Sent from the R help mailing list archive at Nabble.com.
2011 Jan 23
3
how to store a number into a vector
Hi Everyone,
A quick question how to store a number like 12345 to a vector or array with
size(1,5), like 1, 2, 3, 4, 5
So I can compare if the last three digits of this number is the same with
some other numbers.
Thanks a lot
[[alternative HTML version deleted]]
2018 Feb 27
2
scale.default gives an incorrect error message when is.numeric() fails on a sparse row matrix (dgeMatrix)
I am attempting to use the lars package with a sparse input feature matrix,
but the following fails:
library(Matrix)
library(lars)
data(diabetes)
attach(diabetes)
x = as(as.matrix(as.data.frame(x)), 'dgCMatrix')
lars(x, y, intercept = FALSE)
Error in scale.default(x, FALSE, normx) :
>
> length of 'scale' must equal the number of columns of 'x'
>
>
More
2018 Mar 01
0
scale.default gives an incorrect error message when is.numeric() fails on a dgeMatrix
>>>>> Michael Chirico <michaelchirico4 at gmail.com>
>>>>> on Tue, 27 Feb 2018 20:18:34 +0800 writes:
Slightly amended 'Subject': (unimportant mistake: a dgeMatrix is *not* sparse)
MM: modified to commented R code, slightly changed from your post:
## I am attempting to use the lars package with a sparse input feature matrix,
## but the following
2011 Apr 07
1
dotplot as a background for multiple barchart plots (with Lattice)
Hi R users,
I'm kind stuck in my R experience...
I want to have a multiple barchart with n windows, but with the same
background for each window, and I want that background to be a recorded
dotplot.
First, is it possible ?
If so, I guess I have to call a record plot in the panel function but how ?
As there is no panel.plot and I can't use the recorded plot as an
argument for the
2005 Oct 05
1
(no subject)
hi all
why does the following not work???
this was someone elses code and i couldnt explain why it doesn't work.
m=matrix(c(0,0),2,1)
v=matrix(c(1,0,0,1),2,2)
Y=function(X1,X2,mu=m,V=v)
{
X=matrix(c(X1,X2),2,1)
a=(1/((2*pi)*sqrt(det(V))))*exp((-0.5)*(t(X-mu)%*%solve(V)%*%(X-mu)))
a[1]
}
x1=seq(-1,1)
x2=x1
Z=outer(x1,x2,FUN="Y",mu=m,V=v)
persp(x1,x2,Z)
my code:
2006 Apr 08
1
add lines to a plot with a loop without erase the last one
Hello,
I want to plot several lines to a main plot but at the end of each loop, it
erases the last one.
Here my program:
alpha<-5
beta<-10
var<-0.5
s<-runif(1000,0,50)
m<-length(s)
variancealpha<-0.002
variancebeta<-0.051
variancevar<-0.001
alphachap<-vector()
betachap<-vector()
varchap<-vector()
epsilon<-vector()
b<-vector()
2011 Aug 12
2
recode Variable in dependence of values of two other variables
Hi,
as an R-beginner, I have a recoding problem and hope you can help me:
I am working on a SPSS dataset, which I loaded into R (load("C:/...)
I have 2 existing Variables: "ID" and "X" ,
and one variable to be computed: meanX.dependID (=mean of X for all rows
in which ID has the same value)
ID = subject ID. Since it is a longitudinal dataset, there are repeated
2011 Mar 11
3
Large dataset operations
Hello all,
I'm new to R and trying to figure out how to perform calculations on a large dataset (300 000 datapoints). I have already made some code to do this but it is awfully slow. What I want to do is add a new column for each "rep_ " column where I have taken each value and divide it by the mean of all values where "PlateNo" is the same. My data is in the following
2013 Jan 13
1
How to combine two loops?
Hello R-helpers,
I want to ask your opinion since I am not so sure how to do it. This is regarding one part of my paper project and my situation is:
Stage I
I have 2 groups and for each group I need to compute the following steps;
i) Generate 3 random numbers from normal distribution and square them.
ii) Repeat step 1 for 15 times and at the end I will get 15 random numbers.
I already done
2011 Aug 11
1
Splitting data
I want to implement the following algorithm in R:
I want to split my data, use a t test to compare both means of the groups to see if they significantly differ from each other. If this is a yes (p < alpha) I want to split again (into 4 groups) and do the same procedure twice, and stop otherwise (here the problem arises). As a final result I would have different groups of data.
I made some
2012 Jun 14
0
fixed trimmed mean for j-group
Hello...i want to find the empirical rate for type 1 error using fixed
trimmed mean. To make it easy, i'm referring to journal given by this
website
http://www.academicjournals.org/ajmcsr/PDF/pdf2011/Yusof%20et%20al.pdf.
I already run the programme and there is no error in it but i got zero for
the empirical rate of type 1 error. The empirical rate for the type 1 error
given in the journal
2012 Feb 02
1
"shifted" bar chart / battleship curve
What I want to do is create a horizontal bar chart matrix for a set of data that have a common set of variables (e.g., % of As, % of Bs, etc.) listed on the Y-axis and groups (e.g., Classes) on the X-axis. The key here is that the bars for each individual class plot are "centered" rather than left or right-justified. In archaeology plots similar to this are called battleship curves or
2012 Jul 07
0
fixed trimmed mean for group
Hello,
I haven't found errors in your code. I implemented the test in the paper
(the first, fixed symetric mean) and it also gives me zero Type I
errors, when alpha = 0.05. Try to see the value of min(pv) or to plot
the histogram of 'pv', hist(pv) and you'll see that there are no
significant p-values, at that level.
Anyway I'll continue to look at it, but my first
2008 Jul 25
2
Fit a 3-Dimensional Line to Data Points
Hi Experts,
I am new to R, and was wondering how to do 3D linear
regression in R. In other words, I need to Fit a
3-Dimensional Line to Data Points (input).
I googled before posting this, and found that it is
possible in Matlab and other commercial packages. For
example, see the Matlab link:
2012 Dec 17
1
seeking a help on if function
Hello r helpers! Below is the whole coding for my programme. Before proceed more further, let me explain for you. First of all, I need to compute trimmed mean. Till that step is ok. Then I need to compute ssdw which is sum of square deviation. If I do equal trimming at both tail of distribution that I chose, I will use the first ssd formulae which is "a". But if I am doing unequal
2010 Feb 07
2
conditioned xyplot, many y variables
The example below creates parallel time-series plots of three different y variables conditioned by a dichotomous factor. In the graphical layout,
? Each y variable inhabits its own row and is plotted on its own distinct scale.
? Each level of the factor has its own column, but within each row the scale is held constant across columns.
? The panels fit tightly (as they do
2005 Jun 08
1
A question about lars
Hi,
I am trying to use lars on my data. After getting the
model and did the prediction, I compare the predicted
value and the coefficients and it seems like there
should be a constant term in the model. I have gone
through the documentation of the lars package and I
can't seem to find how to get this piece of
information from the lars object. Can somebody help
me? Thanks a lot!
Mark
2007 Jan 06
0
has anyone implemented LARS with the "positive lasso"?
Hi,
I am interested in a modification to LARS that allows for positive-only
constraints in the variables (with details about how to implement this as
described in section 3.4 of the Efron et al (2003) LARS paper).
Before I dive into the "lars" package code myself, I was wondering if anyone
knew of a version where this is available, or if another package that I have
not found can do