Displaying 20 results from an estimated 20000 matches similar to: "subset of a dataframe"
2011 Jul 07
3
Suggestions for R-devel / R-help digest format
Hello,
I am passive reader of both R-devel and R-help mailing lists. I am
sending the following comments to r-devel as it seemed more suitable. I
am aware that this list uses GNU mailman for the list management. I have
my options set that it sends a email digest. One thing I find is that
the digest consists of emails that ordered temporarlly. For eg lets say
there are two threads t1 and t2
2011 Feb 02
2
subset in a BIG matrix
I have a matrix with a lot of values inside..
when I execute the folowing command
matrix2=subset(martix, condition.....)
it works...
but after the previous command I execute another "subset"
matrix3=subset(martix2, condition2.....)
and appears the following error:
(subscript) logical subscript too long
How can I solve this???
I think the probles is the size of the matrix...
2010 Sep 17
7
removing specific rows from array
I'm attempting to create an array of treatment comparisons for modelling data generation. This involves comparison of one treatment (c2) with another (c3), relative to a common comparator (c1).
Attached code gives me the correct array but need to remove duplicates. Duplicates relate only to c2 and c3
such that I need to remove
r3 because c2 and c3 are same as r1 with c2 and c3 swapped
r5
2012 Apr 01
1
extend data frame for plotting heat map in ggplot2
Hi all!
I want to generate a heat map from an all-vs-all comparison. I have the
data, already scaled to 0-1. However, I have the values only for the
comparisons in one way, and not for the comparisons between the same
group (which are always 1), i.e. I have half the matrix and am missing
the other half and the diagonal.
What is a good way to get it into a form that ggplot2 can use for the
2017 Jun 03
4
New var
Hi all,
I have a data set with time interval and depending on the interval I want
to create 5 more variables . Sample data below
obs, Start, End
1,2/1/2015, 1/1/2017
2,4/11/2010, 1/1/2011
3,1/4/2006, 5/3/2007
4,10/1/2007, 1/1/2008
5,6/1/2011, 1/1/2012
6,10/15/2004,12/1/2004
First, I want get interval between the start date and end dates
(End-start).
obs, Start , end, datediff
2017 Jun 03
0
New var
Ii is difficult to provide useful help, because you have failed to
read and follow the posting guide. In particular:
1. Plain text, not HTML.
2. Use dput() or provide code to create your example. Text printouts
such as that which you gave require some work to wrangle into into an
example that we can test.
Specifically:
3. Have you gone through any R tutorials?-- it sure doesn't look like
2010 Jun 02
1
compute the associate vector of distances between leaves in a binary non-rooted tree
Hello.
I'd like to compute the associate vector of distances between leaves in a binary non-rooted tree. The definition of a distance between two leaves in a binary non-rooted tree is the number of edges in the path joining the two leaves.
I've tried the ape package but I'm unable to find this vector.
For example, using rtree(5,rooted=F) I've obtained the following tree:
$edge
2017 Jun 03
2
New var
Thank you all for the useful suggestion. I did some of my homework.
library(data.table)
DFM <- read.table(header=TRUE, text='obs start end
1 2/1/2015 1/1/2017
2 4/11/2010 1/1/2011
3 1/4/2006 5/3/2007
4 10/1/2007 1/1/2008
5 6/1/2011 1/1/2012
6 10/5/2004 12/1/2004',stringsAsFactors = FALSE)
DFM
DFM$D =as.numeric(difftime(as.Date(DFM$end,format="%m/%d/%Y"),
2006 Sep 13
1
reformat records one to several
Hi,
I am a new user of R and am still trying to figure out which statements
do which functions and am looking for a jump start.
I have a dataset where the data were collected as ten minute counts
where the number of new individuals within a species was recorded as
cohorts within 3 separate time intervals within the ten minute count
persiod. Each row of data therefore follows a format like
2007 Dec 14
3
How to convert Datetime numbers from Excel to POSIXt objects
Hi all,
I need to compare time series data files of different time formats. I
had no problems with text format using strptime.
But how can I convert datetime numbers from Excel (days since 30.12.1899
00:00:00) into POSIXt objects?
For example 29770.375 should be converted to "03.07.1981 09:00:00"
I tried the following code and encountered strange results:
t1-t0 gives 29770.33
2017 Jun 04
0
New var
# read.table is NOT part of the data.table package
#library(data.table)
DFM <- read.table( text=
'obs start end
1 2/1/2015 1/1/2017
2 4/11/2010 1/1/2011
3 1/4/2006 5/3/2007
4 10/1/2007 1/1/2008
5 6/1/2011 1/1/2012
6 10/5/2004 12/1/2004
',header = TRUE, stringsAsFactors = FALSE)
# cleaner way to compute D
DFM$start <- as.Date( DFM$start, format="%m/%d/%Y" )
DFM$end
2007 Sep 13
1
Subset Quirk?
Hello All,
I am trying to subset a matrix using subset() and it works fine when I use
matrix notation, but doesn't work when I use established column names.
Sample code is below:
library(mvtnorm)
library(sm)
library(ltm)
library(irtoys)
k<- 100
set.seed(271828)
t <-
rmvnorm(n=k,mean=c(-1,0,1),sigma=matrix(c(1,.8,.5,.8,1,.8,.5,.8,1),3,3))
colMeans(t)
var(t)
pairs(t)
#tview
2017 Jun 04
2
New var
Thank you Jeff and All,
Within a given time period (say 700 days, from the start day), I am
expecting measurements taken at each time interval;. In this case "0" means
measurement taken, "1" not taken (stopped or opted out and " -1" don't
consider that time period for that individual. This will be compared with
the actual measurements taken (Observed-
2017 Jun 04
0
New var
Since the number of choices is small (6), how about this?
Starting with Jeff's initial DFM:
DFM <- structure(list(obs = 1:6, start = structure(c(16467, 14710, 13152,
13787, 15126, 12696), class = "Date"), end = structure(c(17167,
14975, 13636, 13879, 15340, 12753), class = "Date"), D = c(700,
265, 484, 92, 214, 57), bin = structure(c(6L, 3L, 5L, 1L, 3L,
1L), .Label
2002 Oct 02
6
help to make a map on R
Hi all,
I need a little help for construct an state's map on R.
The first problem is to get the data.
I have a datafile of longitude and latitude in the follow format:
trajectory latitude longtude
T -22.045618 -51.287056
T -22.067078 -51.265888
T -22.067039 -51.207249
T -22.059690 -48.089695
T -22.075529 -48.074608
T -22.072460 -48.044472
T -22.062767 -48.298473
T -22.077349
2004 Jun 01
1
swapping with data.frame
Hi there,
I have some data which are convenient to enter as lists. For example:
t1<-list(fname="animal1",testname="hyla",dspkr="left",res1=39.7,res2=15.0)
t2<-list(fname="animal1",testname="bufo",dspkr="left",res1=14.4,res2=56.1)
2009 Jun 18
2
Argument as.integer(NA) to a function C
Hi the list,
I am writing a R function that call a C function. The C function needs
integers but I do not manage to give a NA integer as argument :
--- C code ---
void essai(int *t){
Rprintf("\nT0=%i T1=%i T2=%i T3=%i",t[0],t[1],t[2],t[3]);
}
--- R ---
boub <- c(1,2,3,4)
.C("pour",as.integer(boub),NAOK=TRUE)
# T0=1 T1=2 T2=3 T3=4[[1]]
# [1] 1 2 3 4
boub <-
2004 May 12
1
Sem error - subscript out of bounds
What??s happening with this following code:
require(sem)
Celpe.Mod.RAM <- matrix(c(
# path parametro Inicio
"Produ????o -> T1", "gamma.11", NA,
"Produ????o -> T2", "gamma.12", NA,
2024 Jan 30
1
linear programming in R | limits to what it can do, or my mistake?
Apart from the fact that the statement "such that t1+t2+t3+t4=2970 (as
it must)" is not correct, the LP can be implemented as follows:
library(lpSolve)
LHS <- rbind(
c(0,0,0,0, 1, 0, 0,0),
c(1,0,0,0,-1, 1, 0,0),
c(0,1,0,0, 0,-1, 1,0),
c(0,0,1,0, 0, 0,-1,1),
cbind(-diag(4),diag(4)),
c(0,0,0,0,0,1,0,0),
c(0,0,0,0,0,0,1,0),
c(0,0,0,0,0,0,0,1)
)
RHS <-
2004 Jul 07
3
KalmanSmooth problem
Hello,
In R I am trying to use Kalman filtering to find a solution for an hydrological problem. With Kalman Filtering I want to estimate the discharge comming from three storage bassins. I have programmed a function in R which can run KalmanSmooth. When I'm asking for the function and putting in values, R detects the following error: "Error in as.vector(data) : Argument "S1" is