similar to: invert order

Dear list, While trying to identify the root of a problem I am having with garbage collected variables, I have come across the following oddity: depending on whether --verbose is set or not, I obtain different results. I have made a small standalone example to demonstrate it. The example is very artificial, but I had a hard time reproducing reliably the problem. So when I do: (the content of

I'm very green with R, so maybe this is not a bug, but it looks like one to me. The following program segfaults at the second call to Rf_PrintValue(). To failure depends on the value of the y-string. E.g., if I change it from "coverage" to, say, "COVERAGE", the segfault does not occur. /* bug.c */ #include <stdio.h> #include <Rinternals.h> #include

First, the reproducable example, showing how converting from character to POSIXct to character changes the milliseconds in the first time stamp though not in the second: > as.POSIXct('2010-06-03 9:03:58.324') [1] "2010-06-03 09:03:58.323 PDT" > as.POSIXct('2010-06-03 9:03:58.325') [1] "2010-06-03 09:03:58.325 PDT" This seems to be due to truncation of

Folks, I've been running into an odd situation that occurs when I use length() function with aggregate(), but not with either one separately. Together, the results looks correct but is given an unexpected name. 'if (stringsAsFactors) factor(x) else x' instead of just 'x'. # Numbers work ok tt <- data.frame(idx=c(1,1,1,1,1,1,2,2,2,2,2,2)

Hi all, im triyng to implement a bayesian model with R and c++. I have a strange problem. I can't reproduce the error with a small script and then i post the original one. The problem is after the line for(MCMC_iter2=0;MCMC_iter2<thin;MCMC_iter2++) For the first 34 iterations all work fine, after, all the simulations of mu_acc_P return an "nan". If i delete the line

Folks, Updating values in a table is simple in SAS or SQL, but I've wracked my brain looking for an elegant solution in R to no avail thus far. Certainly this is a common need that's been solved in dozens of different ways. Given an initial dataframe nn and a smaller dataframe of updates uu, I'd like to replace the values in nn <- expand.grid('a'=1:4, 'b'=1:3)

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Folks, I'm checking the structure of a dataframe for duplicate parameters at a site station (i.e depth should be measured once, not twice), using aggregate to count each parameter within a site station. The fake data below has only 26000 rows, and takes roughly 14 seconds. My real data has 750000 rows and I had to stop execution after about an hour. The by() function is faster, but I

Buenas tardes usuarios de R. Estoy tratando de leer un archivo excel con read.xls usando la siguiente sentencia: read.xls("resultados.xlsm", colNames = TRUE, sheet = 1, type = "data.frame", from = 1, rowNames = NA, colClasses = "character", checkNames = TRUE, dateTime = "numeric", naStrings = NA, stringsAsFactors = F) Pero me da el siguiente error: Error

Hi, I first should say I am new to R. I have searched without success the R-archives to see if I could find an answer to what I am about to ask you. My dataset is like: x fine 1 A 2010-12-09 07:57:33 2 B 2010-12-09 08:05:00 3 C 2010-12-08 20:42:00 ... that is: 'data.frame': 3 obs. of 2 variables: $ x : Factor w/ 3 levels "A","B","C":

HI everyone, I''m trying to assign colors to multiple lines in a graph. Problem is I don''t want to type in as many colors as there are lines....is there a way around this? In brief, I''m plotting the logratio for up to 60 samples and want a different color for each sample. Here is the code I''m using now.. Any help is greatly appreciated.. Best LT data <-

Gracias Javier. Voy a probar. Saludos, Sebastián. Enviado desde Correo para Windows 10 De: Javier Marcuzzi Enviado: domingo, 10 de marzo de 2019 14:53 Para: Sebastian Kruk CC: Lista R Asunto: Re: [R-es] Problema codificación archivos Estimado Sebastian Kruk Yo utilizo Microsoft R-open 3.5.1 y la r-project se encuentra en 3.5.3, ¿si intenta con cualquiera de estas dos? Javier Rubén Marcuzzi

OK, this should be trivial but I'm not finding it. I want to compress the test, if (i==7 | i==10 | i==30 | i==50) {} into something like if (i in c(7,10,30,50)) {} so I can build a "excludes" vector excludes <- c(7,10,30,50) and test if (i in excludes) {} However, I'm not finding a clue on how to accomplish this, if it can be done. Would someone with more R

By any chance is there an R command to compare two vectors?   For example, a_tmp<-c("a", "b", "c", "d", "e", "f", "g", 'h') b_tmp<-c("a", "c", "e", "g")   I would like to compare b_tmp against a_tmp to determine if the members of b_tmp are part of a_tmp.    I tried

Can anyone tell me why I would get different average nearest neighbor values for the same set of coordinates between ArcGIS 10 and R? Sometimes the difference in distance is over 1.3 km. Alexis -- View this message in context: http://r.789695.n4.nabble.com/nndist-R-vs-ArcGIS-tp3442375p3442375.html Sent from the R help mailing list archive at Nabble.com.

Hi, I have two columns with data (both identifiers - it's an affiliation list) and I would like to delete the rows in which the observations in the second column have a frequency < 5 in the entire second column. Example: 1 a 1 b 1 c 2 a 2 b 2 d Let's say, I would like to delete the rows in which the observation in the second column has a frequency < 2 in

Hi R folks, I'd like to announce several new R users groups here in SF, LA, NYC, and Ottawa - as well as their next scheduled event. The goal of these user groups, besides gently explaining 'drop=TRUE' to the uninitiated, is to exchange knowledge, promote best practices, and spur the adoption of R for innovative applications. If I've missed any groups here, please feel to add on

Hola. Tengo un archivo de texto con formato Ansi en Windows que lo quiero convertir en una serie temporal pero cuando lo trato de hacer con el siguiente comando: out <- read.zoo(readLines(con <- file("log2.log", encoding="UCS-2LE")),FUN = as.chron) Me da los siguientes errores: Error en file(file, "rt") : no se puede abrir la conexión Además: Mensajes de

Estimados: Dentro del aggregate utilice un table, son cuatro los valores que puede tomar la variable, ¿como puedo desarmar la lista y crear cuatro variables nuevas donde le asigne 0 si no se da ese valor? Saludos, Sebastián. El 25 de septiembre de 2013 10:41, Jorge I Velez <jorgeivanvelez@gmail.com>escribió: > Sebastián, > > Una forma es > > aggregate(cbind(X1,X2) ~ B +

Estimados usuarios de R: Tengo una matriz de datos que la quiero achicar. Por ejemplo las primeras cuatro preguntas pueden tomar el valor "Sí" o "No". Entonces quiero crear una nueva variable que toma el valor 1 si se respondió si a la primera pregunta, 2, si fue Si a la segunda y así sucesivamente. Esto sucede con varias variables. ¿Cuál seria la forma mas eficiente de