similar to: help with Date class

I have a VBox VM running CentOS 6.7 and I want to extract the content of a 14G tar file. I'm doing as: *tar -xvf www.tar.gz* But I am getting a lot of errors like the ones shown below: html/elclarinweb.dev/wp-content/uploads/2015/03/12-Aura-?vila-400x320.jpg tar: html/elclarinweb.dev/wp-content/uploads/2015/03/12-Aura-?vila-400x320.jpg: Cannot open: No space left on device

I noticed something surprising (in R 2.2.1 on WinXP) According to the documentation, rownames and colnames are character vectors. Assigning a vector of class POSIXct or POSIXlt as rownames or colnames therefore is not strictly according to the rules. In some cases, R performs a reasonable typecast, but in some other cases where the same typecast also would be possible, it does not. Assigning a

I noticed something surprising (in R 2.2.1 on WinXP) According to the documentation, rownames and colnames are character vectors. Assigning a vector of class POSIXct or POSIXlt as rownames or colnames therefore is not strictly according to the rules. In some cases, R performs a reasonable typecast, but in some other cases where the same typecast also would be possible, it does not. Assigning a

I would like to use POSIX classes to store dates and extract components of dates. Following the example in Spector ("Data Manipulation in R"), I create a date > mydate = as. POSIXlt('2005-4-19 7:01:00') I then successfully extract the day with the command > mydate$day [1] 19 But when I try to extract the month > mydate$mon [1] 3 it returns the wrong month. And

Dear list: working with date/times I have come across a problem that ISOdate and ISOdatetime are too slow on large vectors of data. I was surprised just until I looked at the implementation and the man page: "ISOdatetime and ISOdate are convenience wrappers for strptime". In other terms, they convert data to character representation first in order to create a POSIXlt object that is then

Hi all, this one left me a bit puzzled, as I don't seem to find a function to perform this easily. I must have overlooked the obvious, so sorry in advance. I have a list of dates in numerical format (i.e. 34576), defined as the number of days that passed since january 1st 1900. So I apply the function : > MyDate <-as.Date(34576,origin="1900-01-01") > MyDate [1]

I have a vector of dates. I wish to find the month end date for each. Any suggestions? e.g. For 12/15/05, I want 12/31/05, For 10/15/1995, I want 10/31/1995, etc __________________________________________________ [[alternative HTML version deleted]]

I know that I can use as.yearmon in the package "zoo" to find the year and the month of a date. I can use as. yearqtr to find the year and the quarter. But how can one find just the year of a date? Thanks a lot! -- Dimitri Liakhovitski Ninah Consulting www.ninah.com

Hello, I have seen much discussion on Date. But I can't seem to do this simple operation. I can convert a string to a date: d <- as.Date(DATE, format="%m/%d/%Y") But what I want to do is extract the year and month so I can construct an element in a ts object. Ideally I would like to see d$year but that doesn't seem to be available. Once I have a Date object how can I get an

To whom it corresponds, I have been trying to connect my RHEL4 machine through public key authentication against a windows server 2003 machine running OpenSSH for Windows v3.8.1p1-1. I set up everything: keys, user, etc. Doing sftp -vv user@<wsip> I see that authentication went ok but somehow, connection hangs up. I removed anti-virus and other security software on the ws2003 machine

Hello, I have some data that has dates in the form 27.02.37. I convert them to a date object as follows: as.Date(data$date,format="%d.%m.%y") But this gives me years such as 2037 when I would like them to be 1937. I thought of trying to take off some time i.e. as.Date(camCD$DoB,format="%d.%m.%y") - 100*365 But that doesn't seem to work out correctly. Any ideas how to

Emil et al., On Mon, Jun 11, 2018 at 1:08 AM, Emil Bode <emil.bode at dans.knaw.nl> wrote: > I don't think there's much wrong with is.na(as_date(Inf, > origin='1970-01-01'))==FALSE, as there still is some "non-NA-ness" about > the value (as difftime shows), but that the output when printing is > confusing. The way cat is treating it is clearer: it

Hi, Given a frame with calendar date's: "2005-07-01", "2005-07-02","2005-07-03","2005-07-04","2005-07-05",etc. I want to extract the following from these dates: week number month number year number Any ideas how to accomplish this? Many thanks. Regards, Richard

Hi, Let say I have a date variable: > ?asd <- as.Date("2012-01-03") > asd [1] "2012-01-03" Now, I want to express this date like 3/1/2012. can somebody help me how to achieve that? Thanks,

Indeed. as_date is from lubridate, but the same holds for as.Date. The output and it's interpretation should be consistent, otherwise it leads to confusion when programming. I understand that the difference exists after asking a question on Stack Overflow: https://stackoverflow.com/q/50766089/914686 This understanding is never mentioned in the documentation - that an Inf date is actually

When I try to do linear interpolation between financial contracts with maturities on different dates in different months I have come across some behavior I haven't seen before. I have a data frame in R which is loaded from an access database so I can't provide a working example. It was loaded using this code: > dbPath <- "H:/pathToDB/DB.mdb" > channel <-

Hi Have this helper method inside a sites_helper.rb module def distritos [ ['0', 'Todos'], ['1', 'Aveiro'], ['2', 'Beja'], ['3', 'Braga'], ['4', 'Brangança'], ['5', 'Castelo Branco'], ['6', 'Coimbra'], ['7',

I am running R 2.9.2 and creating a PDF that I am trying to open with Adobe Reader 9.2 but when I try to open it the reader responds with "There was an error opening this document. The file is damaged and cannot be repaired.: I am using the R command(s): pdf(file="cat.pdf", title="Historical Sales By Category") for(j in 1:length(master)) { d <-

And now I've seen I copied the wrong part of ?is.na > The default method for is.na applied to an atomic vector returns a logical vector of the same length as its argument x, containing TRUE for those elements marked NA or, for numeric or complex vectors, NaN, and FALSE otherwise. Key point being "atomic vector" here. On Sat, Jun 9, 2018 at 1:41 PM, Joris Meys <jorismeys at

Hi, after a debian upgrade my dev.copy2eps dont work anymore. I have this message: Error in matchFont(postscriptFonts(family)[[1]], old$encoding) : unknown font I try to change the font family in my .Rprofile: setHook(packageEvent("graphics", "onLoad"), function(...) { grDevices::ps.options(family="ComputerModern") } ) But it no fix