Displaying 20 results from an estimated 6000 matches similar to: "to remove duplicate values"
2010 Jul 05
4
To detect the location of duplicate values
Dear R family,
I have a question about how to detect some duplicate numeric observations.
Suppose that I have two variables dataset.
order value
1 0.52
2 0.23
3 0.43
4 0.21
5 0.32
6 0.32
7 0.32
8 0.32
9 0.32
10 0.12
11 0.46
12 0.09
13 0.32
14 0.25
;
Could you help me indicate where the duplicate observations in a row
(e.g., 0.32) are?
best,
moohwan
2012 Jul 30
2
distance matrix and hclustering
Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis
i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values
> dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,
2009 Dec 11
3
how to creat a matrix
Dear R family
I am attempting to create a matrix. e.g.,
0 0 0 0 1
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
How could I write a R program?
Later I want to extend it to a N by N case.
Thanks in advance
best
Moohwan
2009 Dec 18
1
to remove an error with log(zero)
Dear R family
I have an arbitrary column vector.
1
2
4
0
7
5
0
0
0
9
11
12
When I attempt to take natural logarithm of the series, as you guess
there is an error message. To overcome this problem, my idea is to
replace a zero or zeros in a row with appropriate numbers.
In order to implement it, I need to detect where zeros are.
Then I am going to take the average of two adjacent neighbors. In the
2013 May 15
1
x and y lengths differ
I have a problem with R. I try to compute the confidence interval for my
df. When I want to create the plot I have this problem: Error in
xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ.
I try this code:
library(dplR)
df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL)
write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)
2012 Sep 28
2
Converting array to matrix
Hi,
I have a 3d array as below, I want to make this array to a matrix of p=50(rows) and n=20(columns) with the coverage values .
The code before the array is:
library(binom)
Loading required package: lattice
pi.seq<-seq(from = 0.01, to = 0.5, by = 0.01)
no.seq<-seq(from = 5, to = 100, by = 5)
cp.all = binom.coverage( p = pi.seq, n = no.seq , conf.level = 0.95, method = "exact")
2013 Mar 06
3
About basic logical operators
Hello everyone,
I have a basic question regarding logical operators.
> x<-seq(-1,1,by=0.02)
> x
[1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78
[13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54
[25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30
[37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16
2010 Mar 31
1
Weird R behaviour?
Dear list,
I have observed a weird behaviour from R --- apologies if I am missing
something obvious!
df3f826f28
df3f826f28
Say you type in R:
>c.preec <- 10074
>c.gd <- 2200
>p1 <- .2
>c.neo <- p1*9451 + (1-p1)*3883
>n.preec <- 3710
>n.gd <- 2650
>n.neo <- 2120
>n.pcos <- 53000
>unit.met <- 94
>cost.met <- 94*n.pcos
>effect <-
2010 Jul 21
1
Question about allocMatrix error message
Dear R family,
I faced a technical problem in r coding.
#s=t(dev)%*%dev/(nr-1) # dev (100,000 by 2) stands for
deviation from the mean
#sinv=solve(s)
#t2=diag(dev%*%sinv%*%t(dev))
I got an error message at t2 statement:
Error in diag(dev %*% si %*% t(dev)) : allocMatrix: too many elements specified
Please let me know if there is a way to overcome this problem.
best
moohwan
2009 Dec 11
2
How to calculte the power of a matrix
Dear R family
I have a following question.
Suppose I have a matrix as follows, for instance:
tau=
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
0 0 0 0 1
1 0 0 0 0
I want to calculate (-m) power of tau, for example, m=893.
When I run tau^2, the outcome is just tau.
Any help would be appreciated.
thanks in advance.
best
moohwan
2013 May 23
1
sample(c(0, 1)...) vs. rbinom
Greetings.? My wife is teaching an introductory stat class at UC Davis.? The
class emphasizes the use of simulations, rather than mathematics, to get
insight into statistics, and R is the mandated tool.?? A student in the class
recently inquired about different approaches to sampling from a binomial
distribution.? I've appended some code that exhibits the idea, the gist of
which is that using
2011 Jun 18
1
double integral calculation
a=[0.1,0.2,0.1,0.3,0.4]
b=[0.2,0.3,0.1,0.2,0.5]
c=[1,1,1,1,1]
log(c+a-x*b) where x=unknown scale variable.
int=$$log(c+a-x*b)dadb, where $ denotes integral sign.
Actually, how could I calculate the integral's approximation?
double summation?
best,
moohwan
2009 Dec 11
1
How could I find the inverse of a matrix?
Dear R family
I have a following question.
Suppose I have a matrix as follows, for instance:
tau=
0 0 0 0 1
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
I want to have the inverse of the above matrix and then add some
exponent to it. That is, I want to calculate tau to the (-m). For
example, m=893.
Thanks in advance
Best regards
Moohwan Kim
2009 Dec 13
1
too large dimension problem
Dear R family
When I run the command below, the error message came up. It seems like
the problem is about computer capacity.
It would be appreciated if anyone could give me a solution.
###########
> N <- 415884
> tau <- diag(1, N)[c(N, 1:(N - 1)),]
Error in array(0, c(n, p)) : 'dim' specifies too large an array
Best
Moohwan
2010 Jun 04
2
Convolution vector to be derived
I want to generate the following outcome using convolution of two sequences.
x <- c(1,2,3,4,5)
y <- c(6,7,8,9)
The resulting convolution vector is
6
19
40
70
100
94
76
45
When using convolve(), it is hard to produce the result above.
Would you help me out to get that?
Best regards
Moohwan Kim
2013 May 29
0
[LLVMdev] Polyhedron 2005 results for dragonegg 3.3svn
On Wed, May 29, 2013 at 03:25:30PM +0200, Duncan Sands wrote:
> Hi Jack, I pulled the loop vectorizer and fast math changes into the 3.3 branch,
> so hopefully they will be part of 3.3 rc3 (and 3.3 final!). It would be great
> if you could redo the benchmarks rc3.
>
Duncan,
As requested, appended are the updated Polyhedron 2005 benchmark results with both RC1 and RC3 llvm 3.3
2007 Mar 05
4
Identifying last record in individual growth data over different time intervalls
Hi
I have a plist t which contains size measurements of individual plants,
identified by the field "plate". It contains, among other, a field
"year" indicating the year in which the individual was measured and the
"height". The number of measurements range from 1 to 4 measurements in
different years.
My problem is that I would need the LAST measurement. I only
2007 Oct 22
2
Help interpreting output of Rprof
Hello there,
I am not quite sure how to interpret the output of Rprof (in the following the output I was staring at). I was poking around the web a little bit for documentation but without much success. I guess if I want to figure out what takes so long in my code the 2nd table $by.total and the total.pct column (pct = percent) is the most helpful. What does it mean that [ or [.data.frame is
2012 Jul 02
1
How to get prediction for a variable in WinBUGS?
Dear all,I am a new user of WinBUGS and need your help. After running the following code, I got parameters of beta0 through beta4 (stats, density), but I don't know how to get the prediction of the last value of h, the variable I set to NA and want to model it using the following code.Does anyone can given me a hint? Any advice would be greatly appreciated.Best
2013 May 23
4
[LLVMdev] Polyhedron 2005 results for dragonegg 3.3svn
Below are the results for the Polyhedron 2005 benchmarks compiled with llvm/compiler-rt/dragonegg 3.3svn at r182439 against current
FSF gcc 4.7.3svn and 4.8.1svn. The only major bug remaining in the dragonegg 3.3svn support for gcc 4.8.x is http://llvm.org/bugs/show_bug.cgi?id=15980
which results in unresolved symbols for _iround and _iroundf in the aermod and rnflow testcases. Note that this