similar to: unable to get bigglm working, ATTN: Thomas Lumley

Hello useRs, Pls help with removing a single interaction term from a formula: summary( glm.turn.2 <- glm(cbind(turn.cnt,tot.cnt-turn.cnt)~sn+poly(relAge,2,raw=T)+termfac+rate:termfac,data=fix, family="quasibinomial") ) Gives Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) -7.028467

I have some data set which has some values -999.000 & I would like to remove whole row of this kind of values. e.g a<-matrix(c(1,2,3,4,4,5,6,6,-999.99,5,9,-999.00),nrow=4) a<- [,1] [,2] [,3] [1,] 1 4 -999.99 [2,] 2 5 5.00 [3,] 3 6 9.00 [4,] 4 6 -999.00 expected answer [,1] [,2] [,3] [1,] 2 5 5.00 [2,] 3 6 9.00 I

I have a model with quant vars only and the error message does not make sense: (mod1 <- coxph(Surv(time=strt,time2=stp,event=(resp==1))~ +incpost+I(amt/1e5)+rate+strata(termfac), subset=dt<"2010-08-30", data=inc,method="efron")) Call: coxph(formula = Surv(time = strt, time2 = stp, event = (resp == 1)) ~ +incpost + I(amt/1e+05) + rate + strata(termfac),

Hello, I have a couple questions about removing rows from a data frame and creating a new data frame with the removed values. I provided an example data frame (d) below. Questions: 1) How can I search for "-999.000" and remove the entire row from data frame "d"? (all -999 values will be in sd_diff) 2) Can I create a new data frame "d.new" that only contains the

I am attemting to use glmD in order to use latex(obj) afterwards. Glm works fine, glmD throws an error: > conv.go <- glmD(cbind(go.cnt,tot.cnt-go.cnt)~sn+rcs(relAge,4)+termfac+rate:termfac+ + I(relAge*term>(term-1.25))+I((prevbal/tot.cnt)*1e-4)+prod+newmort+ +

I am dealing with a huge matrix in R (20 columns, 54000 rows) and have lots of missing values within the dataset which are currently displayed as the value "-999.00" I am trying to create a new matrix (or change the existing one) to display these values as "NA" so that I can then perform the necessary analysis on the columns within the matrix. The matrix name is temp and the

I am wondering how to interpret the parameter estimates that lm() reports in this sort of situation: y = round(rnorm(n=24,mean=5,sd=2),2) A = gl(3,2,24,labels=c("one","two","three")) B = gl(4,6,24,labels=c("i","ii","iii","iv")) # Make both observations for A=1, B=4 missing y[19] = NA y[20] = NA data.frame(y,A,B) nonadd = lm(y ~

Hi see in line > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Courtney > Benjamin > Sent: Thursday, August 10, 2017 5:55 AM > To: r-help at r-project.org > Subject: [R] Creating New Variable Using Ifelse > > Hello R Help List, > > I am an R novice and trying to use the ifelse function to create a new binary >

Hello, We are having some strange issues with RODBC related to integer columns. Whenever we do a sql query the data in a integer column is 150 actual data points then 150 0's then 150 actual data points then 150 0's. However, our database actually has numbers where the 0's are filled in. Furthermore, other datatypes do not have this problem: double and varchar are correct and do not

useR's, I need help getting a Fortran DLL successfully returning the correct output. The attached fortran source code (filter2d.f) and DLL (filter2d.dll) are attached. Also, I attached a text file for which I want to apply the filter to (time702.txt). Here is what I am doing... > dyn.load("C:/f/NEW/filter2d.dll") > is.loaded("filter2d") [1] TRUE Then I pass the

I am using R-1.8.0 on Debian. I'm trying to read in a large table (1441*16) which currently has no header line. I have set up a list of column names which is 16 names long. when i try the following: myfiledate.01<-read.table("filenamedate.01",row.names=NULL,col.names="names",na.strings="-999.00") I am returned with an error saying there are more columsh

Hi, this patch enables the use of time stamps in dump file names: diff -ur icecast-2.0.1/src/source.c icecast-2.0.1.scram/src/source.c --- icecast-2.0.1/src/source.c Wed May 12 17:55:30 2004 +++ icecast-2.0.1.scram/src/source.c Wed Jun 2 23:17:29 2004 @@ -50,6 +50,16 @@ http_parser_t *parser, const char *mount, format_type_t type, mount_proxy *mountinfo) { + char buffer[PATH_MAX]; +

Hi, this patch enables the use of time stamps in dump file names: diff -ur icecast-2.0.1/src/source.c icecast-2.0.1.scram/src/source.c --- icecast-2.0.1/src/source.c Wed May 12 17:55:30 2004 +++ icecast-2.0.1.scram/src/source.c Wed Jun 2 23:17:29 2004 @@ -50,6 +50,16 @@ http_parser_t *parser, const char *mount, format_type_t type, mount_proxy *mountinfo) { + char buffer[PATH_MAX]; +

Hello R Help List, I am an R novice and trying to use the ifelse function to create a new binary variable based off of the responses of two other binary variables; NAs are involved. I pulled it off almost successfully, but when I checked the counts of my new variable for accuracy, I found that a small portion of the NA cases were not being passed through as NAs, but as "0" counts in my

Hi. I am running the as.ltraj () function in adehabitat (v 1.4 under R 2.2.1) but can't seem to correctly specify the burst argument. i.e., the ltraj object returned consists of only one component, when in fact my data consist of more than one burst of reloctions per animal. i've set up the data (xy, date, id, burst) in list form following the example given in ?as.ltraj. to simplify,

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Good day to you, Who Are We? Downloadable Software (DS) is a rapidly growing company providing high quality software. You've come to the right place if you need professionally implemented programming solutions for your usage. Thousands of satisfied customers have already benefited from our products and solutions. Hundreds are joining this community every day. Our Mission To deliver

Hello! I would like to prepare training data to predict stock flow. Prediction should be based on 2 inputs (date, stock currency) input data : date, stock_currency 1.1.2004, 1000.00 2.1.2004, 1120.00 5.1.2004, 1230.00 7.1.2004, 1150.00 10.1.2004,1040.00 11.1.2004, 999.00 1.2.2004, 945.00 How should training instances look like? I use nnet function to train the model and predict function

Greetings useRs, Can anyone provide an example how to use ff to feed a very large data frame to glm? The data.frame cannot be loaded in R using conventional read.csv as it is too big. glm(...,data=ff.file) ?? Thank you Stephen B

> Message: 4 > Date: Sat, 17 Nov 2018 18:43:40 -0800 > From: "Timothy B. Terriberry" <tterribe at xiph.org> > To: opus at xiph.org > Subject: Re: [opus] Impossible two bugs in Opus > > ongaku zettai wrote: > > i think opus decreasing bitrate only when it thinks that audio > > is too complex for human to hear difference. that's a bad attitude.