similar to: multiple plots without for loops

Dear all- I have a dataset (see a sample below - but the whole dataset is June 2005 - June 2008). The "LST" format is "YYMMDDHHmm" and I would like to get the hourly average of the "mph" for the summer months (spanning all years). I have been trying to use "aggregate" but am not having much success at all! any thoughts would be greatly appreciated.

Dear All- I am trying to merge two data files - they have different date formats and different times zones. I need to match up the date/time of the datasets and then invoke a conditional statement, such as: if dataC$mph is >= 12 then keep dataM$co23 for the corresponding time/date stamp. snippets of data files: *dataC.txt* LST in mph Deg DegF DegF2 % volts Deg

Hi All- I have a data set (spdco2) > spdco2 [,1] [,2] [,3] [1,] 1 5.4 382.4212 [2,] 2 5.1 383.0315 [3,] 3 4.8 383.9520 [4,] 4 4.7 384.4376 [5,] 5 4.7 384.5929 [6,] 6 4.4 384.8864 [7,] 7 4.1 385.2156 [8,] 8 3.8 385.2919 [9,] 9 3.7 385.5925 [10,] 10 3.9 385.6801 I am subsetting it to output when [,2] is >= 4.7 .

Hi All- I have 24 boxplots on one graph. I do not have the whiskers extending to the outliers, but I would like to label the maximum value of each outlier above the whiskers. I have the stats but am having trouble figuring out how to label the whiskers. Any suggestions would be great! sherri

Dear R-Help List, I'm trying to simulate data from a conditional distribution, and haven't been able to modify my existing code to do so. I searched the archives, but didn't find any previous post that matched my question. n=10000 pop = data.frame(W1 = rbinom(n, 1, .2), W2 = runif(n, min = 3, max = 8), W3 = rnorm(n, mean=0, sd=2)) pop = transform(pop, A = rbinom(n, 1,

Hi everyone- I have a dataset that I created using the aggregate command: Hour Level C2 1 1 1 -3.517117e+00 2 2 1 -2.536083e+00 3 3 1 -1.429000e+00 4 4 1 -1.148667e-01 5 5 1 1.345333e+00 6 6 1 3.108117e+00 7 7 1 4.763733e+00 8 8 1 6.161867e+00 9 9 1

Hi All- I would like to create a 3d topographic map using lat/lon and z(height). I have been scouring the R help pages and have not located the package I am looking for. Does anyone have a suggestion of package that will work for this? thanks- sherri

Hi, I am new to programming and R. I am reading the manual and R books by Dalgaard and Veranzo to help answer my questions but I am unable to figure out the following: I have a data file that contains 1080 data points. Here's a snippet of the file: [241] 0.3603704000 0.1640741000 0.2912963000 NA 0.0159259300 0.0474074100 I would like to break the file up into 30

Hi all- I have a dataset (year, month, hour, co2(ppm), num1,num2) [49,] 2006 11 0 383.3709 28 28 [50,] 2006 11 1 383.3709 28 28 [51,] 2006 11 2 383.3709 28 28 [52,] 2006 11 3 383.3709 28 28 [53,] 2006 11 4 383.3709 28 28 [54,] 2006 11 5 383.3709 28 28 [55,] 2006 11 6 383.3709 28 28 [56,] 2006 11 7 383.3709 28 28 [57,] 2006

Hi, I have a data frame like this: ScoreDoseSex 2.81Dose1M 1.81Dose1M 1.22Dose1M 0.81Dose1M 0.49Dose1M 0.22Dose1M 0.00Dose1M -0.19Dose1M -0.17Dose1F -0.32Dose1F -0.46Dose1F -0.58Dose1F -0.70Dose1F -0.81Dose1F -0.91Dose1F -1.00Dose1F -1.77Dose2M -1.85Dose2M -1.93Dose2M -2.00Dose2M -2.07Dose2M -2.14Dose2M -2.20Dose2M -2.26Dose2M -2.32Dose2F -2.38Dose2F -2.17Dose2F -2.49Dose2F -2.54Dose2F

Hello all, I am doing an aggregation where the aggregating function returns not a single numeric value but a vector of two elements using return(c(val1, val2)). I don't know how to access the individual columns of that vector in the resulting dataframe though. How is this done correctly? Thanks, robert > agg <- aggregate(formula=df$value ~ df$quarter + df$tool, + FUN=cp.cpk,

I'm having difficulty finding a solution to my problem that without using a for loop. For the amount of data I (will) have, the for loop will probably be too slow. I tried searching around before posting and couldn't find anything, hopefully it's not embarrassingly easy. Consider the data.frame, Data, below Data Sub Tr IA FixInx FixTime p1 t1 1 1 200 p1 t1 2

Hi I generate a new dataframe by doing: npl.agg <- aggregate(npl$DensPlants, list(year=npl$year, sim=npl$sim), mean, na.rm=TRUE ) Now I want to plot it by using coplot(npl.agg$x ~ npl.agg$year | npl.agg$sim, type="l") but, as npl.agg$year is seen as a factor, the order of the points on the x-axis (time axis) does not follow the numerical sorting 1...100, but rather the text

Hi all, I'm currently working on getting the whole samba with ldap working. I'm having an error trying to join a computer to the domain, when windows goes to change to the new domain I get the dialogue box to enter the user/pass to join I do that and it returns: the following error occurred.... the username could not be found. taking a look at the smbd.log file it shows: [2005/06/16

Hi R-list, I'll apologize in advance for (1) the wordiness of my note (not sure how to avoid it) and (2) any deficiencies on my part that lead to my difficulties. I have an application with several stages that is meant to simulate and explore different scenarios with respect to product sales (in units sold per month). My session info is at the bottom of this note. The steps include (1) an

Hi all, There might be a bug in DeadStoreElimination.cpp. This pass eliminates stores backwards aggressively in an end BB. It does not check dependencies on stores in an end BB though. For example, in this code snippet: ... 1. %sum.safe_r47.pre-phi = phi i64* [ %sum.safe_r47.pre, %entry.for.end_crit_edge ], [ %sum.safe_r42, %for.body ] 2. %call9 = call i32 @gettimeofday(%struct.timeval* %end,

I have a string such as fileName<-"Agg.20.20.20-all-01". All I want to do is pull the "20.20.20" and the "all" as strings. Obviously, they aren't always those values. The "20.20.20" can be "30.30.30" but it's always after the . which is next to the second g in Agg and it's always the same length. The all might not always be

*Combining 2 columns into 1 column many times in a very large dataset* The clumsy solutions I am working on are not going to be very fast if I can get them to work and the true dataset is ~1500 X 45000 so they need to be efficient. I've searched the R help files and the archives for this list and have some possible workable solutions for 2) and 3) but not my question 1). However, I include

Dear All - I would like to make multi-page plots, but my plots are writing over one another - thus leaving just the last plot. Here is what I am doing: pollutionRose(temp, "nox", type="hour") update(trellis.last.object(), layout =c(3,3,3) ) I would like 24 plots with 9 plots/page (the last page would not have 9 plots) Is there any way to "force" layout to make 3

On Thu, Oct 6, 2011 at 2:20 PM, Eli Friedman <eli.friedman at gmail.com> wrote: > On Thu, Oct 6, 2011 at 2:12 PM, Zeng Bin <ezengbin at gmail.com> wrote: >> Hi all, >> >> There might be a bug in DeadStoreElimination.cpp. This pass eliminates >> stores backwards aggressively in an end BB. It does not check dependencies >> on stores in an end BB though.