similar to: Question regarding R plot

Hi All, I try to do a scatterplot for a bunch of variables. I plot a dependent variable against a bunch of independent variables: -- cut -- graphics::plot( v01_r01 ~ v08_01_up11, data = dataset, xlab = "Dependent", ylab = "Independent #1" ) -- cut -- It is tedious to repeat the statement for all independent variables. Found an alternative, i.e. : -- cut -- mu

Dear all, I am using the following code to write the plot to an eps format postscript(file="test.eps",horizontal=FALSE)

Hi, I try to create a vertical line in my plot, which has a xaxis comprising time formated data. This is what I tried: ---------------- y<-152833 x<-strptime(y, format="%H%M%S") abline(v=x, col="red") ---------------- for some reason, it doesn't work and no error msg is displayed... I hope someone can tell me what I do wrong, or maybe an alternative. Thanks

Hello, I'm very new to R, and have managed to plot xy graphs, but can't seem to plot a matrix properly. The first column is my time points, and the following columns 2-4 are the replicates of my experiment. I've tried using row.names=1 to make the first column the value for that row (whereas before I had 1-31 sequence) and then my 1st column) but I can't work out how to tell it

I need to update a record in a table based on a event that occurs in the View. I believe the update action should occur in the controller. I think I need to call the controller action from the View and pass data that is stored in a Javascript variables as a parameter, but I am not sure how to do it. Can someone show me how I should be doing this? Below is a simplified version of the code I

It''s been a few days since I posted my last two emails (of which, no one replied to) so I''ve gone ahead and coded a working slider class as well as a ''resizeable'' class that allows a user to drag and resize the element. I also linked these two together as I want to have slider behavior that can resize the resizeable element. The end result is both the

Good day all, I'm trying to plot a continuous line plot, which is followed by two forecast points eg. one forecast point is 12 months out, and another 24 months out from the last date of the line plot. In my attempts so far, the second plot (the forecast points) is scaled against a new axis scale, thus the two plots are not directly comparable (I need the forecast points to be scaled

panel.lmline returns intercept and slope of y ~ x subsetted to the combination of conditioning factors given to xyplot in lattice. for instance: xyplot(Xvalues ~ log(Qvalues)|Tfac, data = df7, panel = panel.lmline) I am looking to find the equivalent formulation for lm() proper. If I do this: lmcal <- lm(Xvalues ~ log(Qvalues):Tfac, data = df7) Only one value of the intercept is returned.

Dear All, Does anyone know how to get the maximum/minimum value of a function using R, I think there should be an instruction, but i can not find it in help files Thank you in advance for your help :) [[alternative HTML version deleted]]

I am new to R. I want to graph group data using a "Traditional Bar Chart with Standard Error Bar", like the kind shown here: http://samiam.colorado.edu/~mcclella/ftep/twoGroups/twoGroupGraphs.html Is there a simple way to do this? So far, I have only figured out how to plot the bars using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927

Hi R-users! I'm trying to create an easy Excel chart using the package RDCOMClient. The following example is working fine: #------------------------------------------------------------------- library(RDCOMClient) xlLocationAsObject <-2 xlXYScatterSmoothNoMarkers <- 73 ex <- COMCreate("Excel.Application") wb <- ex[["Workbooks"]]$Add() sh <-

R-Help community, I understand that data.frames can hold elements of type double, string etc but NOT objects (such as a matrix etc). This is not convenient for me in the following situation. I have a function that takes 2 inputs and returns a vector: testfun <- function (x,y) seq(x,y,1) I have a data.frame defined as follows: testframe<-data.frame(xvalues=c(2,3),yvalues=c(4,5)) I would

On Thu, Jul 17, 2014 at 4:45 PM, Alp Toker <alp at nuanti.com> wrote: > > On 18/07/2014 02:21, David Blaikie wrote: >> >> Are people OK with/prefer the use of owning smart pointers in APIs? > > > I think smart pointers are great to use for storage, or as struct members > where there's actually a clear need for ownership. Just by virtue of getting > rid of

Suppose I create an R program called myTest.R with only one line like the following: type <- as.integer(readline("input type (1: type1; 2: type2)? ")) Then I'd like to run myTest.R in batch mode by constructing an input file called answers.R with the following: source("myTest.R") 1 When I ran the following at the terminal: R CMD BATCH answer.R output.Rout it failed

The following gives two functions for producing distribution graphs: distribution-graph produces a single graph, and multiple.distribution.graph produces a number of graphs side by side. Regards, Tore Wentzel-Larsen statistician Centre for Clinical research Armauer Hansen house Haukeland University Hospital N-5021 Bergen tlf +47 55 97 55 39 (a) faks +47 55 97 60 88 (a) email

Dear All: I have succeeded in fitting a GAMLSS.dist model to growth data I am working with it. My aim is to create a matrix of predicted percentiles and the corresponding the fitted model's sigma mu nu by agebins. Q: How do it generate these parameters as in L M S per Cole and Green 1992? Here are my working codes. Name of fitted model is gamlssfit > Agebin<-seq(6,36,6)

There seems to be some uncertainty about the use of smart pointers (previously OwningPtr, now std::unique_ptr and std::shared_ptr predominantly) in the LLVM project as a whole, so here's a thread to discuss/clarify/etc the project preferences/direction with regard to smart pointer usage. For some context, see discussions in LLVM r212403 and Clang r213307. The basic question here seems to be

Hola, Esta es una forma de hacerlo... Mira que lo primero que he modificado es el fichero "x.csv" para sustituir los espacios en los nombres por "_". Y también he quitado los acentos y las eñes... He utilizado el paquete RNNS y la función "mlp()" para ajustar la red. #------------------------------------------- > x <- read.csv("x.csv",

Estimados Les consulto por redes neuronales, hay diversos artículos como los siguientes (el último tienen un error actualmente). Pero mi pregunta va un poco por otro lado. http://www.r-bloggers.com/build-your-own-neural-network-classifier-in-r/ http://www.r-bloggers.com/classification-using-neural-net-in-r/ Básicamente se puede calcular un valor, por ejemplo doblar 2,4 grados a la derecha, luego 1

Hi Folks, I'd be grateful for some views on the following. When I say "plot y against x" I mean that y is on the vertical axis and x is on the horizontal axis. I acquired this usage so long ago that I can no longer remember how I acquired it, and therefore can not cite my "authority" for my usage. There can also be an implication that y is a function of x (or y is a