similar to: read.table behavior for Dates.

Hi I'm new to R and would like to implement a SAS-like macro variable in R. What I'd like to do is take the simple R code below and change the "=TEF" to different letters to refer to different companies' data for download. # DOWNLOADS FILES FROM YAHOO INTERNET

Dear R People: In library(its), there is a command priceIts. There is a problem with this command. It is returning an error message: > ibm1 <- priceIts(instrument="ibm",start="1998-01-01",quote="Open") Error in download.file(url, destfile, method = method, quiet = quiet) : cannot open URL

Hi R users, I have a problem in downloading Yahoo Finance data from R. I have tried an example given in R, to download. The error is given below: >library(fCalendar) > yahooImport("s=IBM&a=11&b=1&c=1999&d=0&q=31&f=2000&z=IBM&x=.csv ", file = "D:\\ Downlaod",source = "http://ichart.yahoo.com/table.csv?", save = FALSE,

Hi- I would like to be able to change the value of SymA below and download a file from the corresponding URL.? Hardcoded, this line works fine: Symbol<- read.csv("http://ichart.finance.yahoo.com/table.csv?s=SPY&ignore=.csv", stringsAsFactors=F) However, when I incorporate using?a variable for the ticker, it no longer works.? SymA<- "SPY" Sym1<-

I have been having the same problem as poster Hodgess, below. It appears that her question was never answered, so I would like to share a solution with the community. The problem is the (apparent?) inability to produce moving range process behavior (a.k.a. "control") charts with individuals data in the package "qcc" (v. 2.0). I have also struggled with the same limitation in

Hi there, I am having some trouble getting download.file to work. I have been searching for the answer but my raw coding ability is not at the same level as the solutions I am getting. I have checked my environment and the proxy settings are in line with what I expected: > Sys.getenv("http_proxy") http_proxy "http://proxy-lon2.macbank" >

Any pointers as to how to proceed with this would be most welcome! wine --version wine-1.3.19 lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 10.04.2 LTS Release: 10.04 Codename: lucid I used crossover to create a Win XP bottle and installed IE7 and then MLDownloader. There is a 15 day trial version available here:

There's nothing like asking someone to "give it a rest" while taking the opportunity to make fun of them. Lucky for you (and the list), I can laugh at myself, because I can seem comical at times. But in all seriousness, just remeber to hold us all to the same standard. And we are all responsible for what we say and how we say it, and I'll never claim to be better than the worst

From: Dag Wieers > Bryan, stop generalising and dramatising. What dramatising? At some point, several people decide that anything they dislike was said by me. Several other people said far more negative comments about CIPE than myself. Those comments have now been attributed to me. I purposely avoided making it about whether or not CIPE should or shouldn't not be included, just why it

Hi, suppose i have a gam object gamobject<- gam( Y~ s(X1)+s(X2)+ X3) I would like to extract the predicted partial effect of X3 but selecting it by its name, as it's to be included in a function and i don't always know the exact position of X3. something like predict(gamobject,type="terms")["X3",]. But that doesn't work as there's no name. So, looking

Dear R-helpers Apologies for the basic question, but I just got stuck: I would like to write values from a vector into array cells with the same names > count[1:10] 10010 10014 10015 10017 10030 10080 10100 10230 10250 10280 0 0 0 0 0 1 1 0 2 0 >data[1:10,,1] [,1] [,2] [,3] [,4] [,5] 10010 NA NA NA NA NA 10014 NA NA NA

Hi everybody, I've been looking around, but can't seem to find the answer. I get a list of names (which vary, so I never know them in advance), and transform them into variables, each of which is a dataframe, using assign: polyList <- c("rs123", "rs124", "rs555", "rs000") numPoly <- length(polyList) for (k in 1:numPoly) {

Hi Consider the following example: f <- function(expr) g(expr) g <- function(expr) { ? h(expr) } h <- function(expr) { ? expr # evaluation happens here ? i(expr) } i <- function(expr) { ? expr # already evaluated, no costs here ? invisible() } rprof <- tempfile() Rprof(rprof) f(replicate(1e2, sample.int(1e4))) Rprof(NULL) cat(readLines(rprof), sep = "\n") #>

From: Collins Richey <crichey at gmail.com> > I roll my eyes when I hear how good and great and all-virtuous > RedHat is, On GPL. That's all. On GPL. IBM is praised while HP, Red Hat and Sun are demonized. Companies have their agendas, and we need to be _cautious_. But one thing remains: Stallman's Moral Delima Which means that the only thing that matters in the end is

I am using asterisk with a handful of DM04B cards. Everything seems fine except for an echo on all calls on the local end of the call. In almost all cases the echo goes away after 15 to 20 seconds. I am attributing the echo going away to the echo cancellation code that was enabled when the following options are set: echocancel=yes ; echocancelwhenbridged=yes echotraining=yes ; Is there anyway

Hi everyone, I am posting this because i know its easy and i cant for the life of me figure out how to do it though i have tried and through a ridiculously complex loop made it happen. I need to convert some list elements of NULL value to 0s so they mesh with my data frame properly. So for A<-list(1,NULL) returns [[1]] [1] 1 [[2]] NULL Would instead return [[1]] [1] 1 [[2]] [1] 0

On Mar 25, 2007, at 2:18 AM, Chris Lattner wrote: > On Sat, 24 Mar 2007, Christopher Lamb wrote: >> Has there been any discussion of supporting the 'restrict' C99 >> keyword >> and C++ extension to boost alias analysis? My impression is that this >> would require modification of the LLVM IR. I couldn't find any >> discussion hits using the usual

Is there an existing function to compute Cook-Weisberg confidence curves for non-linear model parameters in R? Kari Ruohonen -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !)

Hi All, is there any chance of vectorising the two ifelse() statements in the following code: for(i in gp){ new[i,1] = ifelse(srow[i]>0, new[srow[i],zippo[i]], sample(1:100, 1, prob =Y1, rep = T)) new[i,2] = ifelse(drow[i]>0, new[drow[i]>0,zappo[i]], sample(1:100, 1, prob =Y1, rep = T)) } Where I am forced to check if the value of drow and srow are >0 for each line... in

According to Peter Freeman: >Samba 2.2.5 had a couple of interesting issues, particularly with Win2k >clients, try upgrading to the latest (2.2.8a) before doing attributing >any blame to Samba. I'd like to know the interesting issues. We haven't upgraded from 2.2.5 to 2.2.8a because we see a performance drop, instead; we back port the bug fixes - open source is great! We plan