similar to: how to construct a time series

Dear list, I have a big data frame which looks like this: variable YEAR VAR EC01 2006 100 EC01 2007 200 EC02 2006 500 EC02 2007 450 PROD

Dear list, I'm trying to implement the following function, but what I get is an error message and I don't understand where is the error: #outliers'identification: iqr=lapply(bb,function(){ inner_fencesl=quantile(x,0.25)-1.5*IQR(x) inner_fencesh=quantile(x,0.75)+1.5*IQR(x) outer_fencesl=quantile(x,0.25)-3*IQR(x) outer_fencesh=quantile(x,0.75)+3*IQR(x)}) where bb is a dataframe

I spent a lot of time searching and came up empty handed on the following query. Is there an equivalent to rowSums that does product or cumulative product and avoids use of apply or looping? I found a rowProd in a package but it was a convenience function for apply. As part of a likelihood calculation called from optim, I?m computing products and cumulative products of rows of matrices with

Dear list, I have a question about the interaction between R code and Latex language trough the Sweave function in the package "utils". What I'm trying to do is to write a report. Contrary to the examples shown in the Sweave Manual in which table already constructed by R are "exported" on Latex files, what I would like to do is to build a table in which I combine text and

Hi I have a question, as im not able to import a csv file which contains a big dataset(100.000 records) someone knows how many records R can handle without giving problems? What im facing when i try to import the file is that R generates more than 100.000 records and is very slow... thanks a lot!!!

Dear list, I'm looking for an inverse function of melt(which is in package reshape).Namely, I had a data frame like this (Table1) YEAR VAR1 VAR2 VAR3 1995 7 3 45 1996 5 6 32 1997 6 10 15 I transformed my data by using the melt function and my data was reshaped in the following format: (Table2) YEAR variable

Dear list, Im trying to do the following operation but im not able to do it This is my table: 1 2 3 1 0 7 4 2 0 2 0 3 0 1 3 4 0 3 4 what i would like to do is divide each row values with the corresponding column' sum,namely: 1 2 3 1 0 0.54 0.36 2 0 0.15 0 3 0 0.08

Is there anything like cumsum and cumprod but which allows you to apply an arbitrary function instead of sum and product? In other words, I want a function cumfunc(x, f) that returns a vector, so that for all n up to the length of x cumapply(x,f)[n] = f(x[1:n]) This would give cumsum and cumprod as special cases when f=sum or f=prod. I could write such a function, but I can't see

Dear List I would like to ask you something concenting a better print of the R output: I have a bit data frame which has the following structure: CFISCALE RAGSOCB ANNO VAR1 VAR2......... 9853312 astra 2005 6 45 9853312 astra 2006 78 45

Dear list, I'm trying to concatenate the values of two columns but im not able to do it: i have a dataframe with the following two columns: X VAR1 VAR2 1 2 2 1 3 2 4 3 5 4 6 4 what i would like to

Dear list, in the following loop im generating objects of type table. What I would like to do is to put all those objects together in a list (that i called cc).I did this but the result is not what i espect to get: cc=list() d=1 for (i in data) { cc=list(cc,assign(paste("n",d,sep=""),table(i,subsample$vD31NADD))) d=d+1} I know that this won't work properly:

i simply want a set of numbers in a vector which: in the vector v, i want the numbers be (x[1]*x[2]*....*x[100], x[2]*x[3]*...*x[100], x[3]*x[4]*...*x[100],...,x[98]*x[99]*x[100], x[99]*x[100],x[100]) so there should be 100 elements in the vector. here's how i do it x=rnorm(100,0.5,0.2) v=prod(x[(1:100):100]) but it turns out failed as it says there are 100 elements in the expression, but only

Hi I want to write a little function that takes a vector of arbitrary length "n" and returns a matrix of size n+1 by n+1. I can't easily describe it, but the following function that works for n=3 should convey what I'm trying to do: f <- function(x){ matrix(c( 1 , 0 , 0 , 0, x[1] , 1 , 0 , 0, x[1]*x[2] , x[2] , 1 , 0,

Dear R list I have a problem with NA, which should be a string, but R seems that it doesn't recognize it. What I do is first give the format command to my data frame: format.data.frame(mydata,big.mark=" ") so I give a blank as thousand separator. All my records in my data frame become strings, so instead of having NA I have "NA". I try to convert "NA" in

Dear list, I have a question. I have the RKward configuration. I don't know what happened but now when I open R I have in my workspace data frames with which I used in the past sessions.How can I set RKward in order to open a new workspace? Thanks a lot [[alternative HTML version deleted]]

Dear list, I have a problem with the cumsum function. I have a data frame like the following one variable Year value EC01 2005 5 EC01 2006 10 AAO1 2005 2 AAO1 2006 4 what I would like to obtain is variable Year value cumsum EC01 2005 5 5 EC01

Dear list, I have the following problem, what i'm trying to do is to built a function which does the following calculationg in a recursive way: I have a data frame more or less like this: variable year DELTA EC01 2006 / EC01 2007 10 EC01 2008 5 EC01 2009 9 And then I have at time

It surprised me that prod(numeric(0)) is 1. I guess if you say (operation(nothing) == identity element) this makes sense, but ?? Looking in the code, this makes sense: basically (s=1; for i=0 to length(x), multiply s by x[i]) -- which comes out to 1. What *should* prod(numeric(0)) produce? I couldn't find the answer documented anywhere. (And how about sum(numeric(0))==0, which for

Dear list, I'll try to be more clear in explaining my problem. I have a data frame like this called X: CLUSTER YEAR variable value1 value2 M1 2005 EC01 NA NA M1 2006 EC01 2 5 M1 2007

Hi, I'm currently in the process of writing an R-installation SOP for my company. As part of that process I'm using the recommendations from the 'R Installation and Administration' document, section 3.2, "Testing an installation". This is done on an XP machine, using the latest binary of 2.11.0. The binary is downloaded and then installed from the installer. I then